glaze | Python library and command line tool | User Interface library
kandi X-RAY | glaze Summary
kandi X-RAY | glaze Summary
glaze is a Python library and command line tool for rendering algorithmically-generated fonts and typefaces.
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Top functions reviewed by kandi - BETA
- Visualize the visualization
- Render a curve
- Read glyphs from json file
- Validate glyph arguments
- Get output filename
- Setup the logger
- Get the version number from the version file
glaze Key Features
glaze Examples and Code Snippets
Community Discussions
Trending Discussions on glaze
QUESTION
I have two examples of foldLeft
that I cannot really grasp the logic.
First example:
...ANSWER
Answered 2022-Mar-27 at 21:07Does not
foldLeft
accumulate value that was earlier?
yes it does. It uses result of previous iteration and current element and produces new result (using the binary operator you have provided) so for the first example next steps are happening:
the start value of accumulator -
""
acc = ""
,curr = "Plain"
->" , Plain Donut "
acc = " , Plain Donut "
,curr = "Strawberry"
->" , Plain Donut , Strawberry Donut "
acc = " , Plain Donut , Strawberry Donut "
,curr = "Strawberry"
->" , Plain Donut , Strawberry Donut , Glazed Donut"
For the second example current value is simply ignored - i.e. multi
can be rewritten as def multi(acc:Int, curr:Int):Int = acc*10
where curr
is not actually used so foldLeft
simply multiplies starting value (1
) by 10 n
times where n
is number of elements in the sequence (i.e. (1 until 3).length
which is 2).
Why does it not take any input variables (num and num1)?
foldLeft
is a function which accepts a function. It accepts
a generic function which in turn accepts two parameters and returns result of the same type as the first parameter (op: (B, A) => B
, where B
is the the result type and A
is sequence element type). multi
matches this definition when B
== A
== Int
and is passed to the foldLeft
which will internally provide the input variables on the each step.
QUESTION
`
Here's the code written in TypeScript.
This is code to build HTML table which display items from Nested objects. This code works fine but just there is an issue in printing like it should only create table with rows but it is also printing some coma's which are not even part of any line which is executed
...ANSWER
Answered 2022-Mar-26 at 10:17in your code the snippet Object.keys(data).map(.....)
converts it to array. Now when you put this array in string literal JavaScript will try to convert it to a string so it will call .toString()
on it which joins all the elements of array using ,
by default.
instead do this Object.keys(data).map(....).join("")
this will join array with empty string
QUESTION
Thanks in advance for any help with this.
I have a function where users can pass in arguments to a list()
with ...
. I am looking for a way to overwrite obj_a
with all values that exist in obj_b
.
Here's a reprex:
...ANSWER
Answered 2022-Mar-18 at 20:18Some recursion should work here:
QUESTION
Say we have a type representing a box of a dozen donuts,
...ANSWER
Answered 2022-Feb-01 at 22:02If your base type is an integer type, the subtype is an integer type. You can't make it an enumeration type.
You can declare constants for your Donuts if you want, then you can refer to them by name. You can instead give the other values names and then have Bakers_Dozen
be an enumeration type. If arithmetic operations do semantically not make sense on values of your type, it shouldn't be an integer type anyway.
QUESTION
I have a nested json file with the below data and I need some help in writing an interactive program where it should take a topping as input and prints out the names of all the donuts that have this topping.
...ANSWER
Answered 2022-Jan-28 at 11:10Try:
QUESTION
I'm trying to figure out what dictates if a value is returned from a PowerShell function or not, and I've run into some oddities. The about_return docs say:
In PowerShell, the results of each statement are returned as output, even without a statement that contains the Return keyword.
But this seems to glaze over details. If I run this:
...ANSWER
Answered 2022-Feb-07 at 21:09This section discusses the specific statements from your sample functions.
See the bottom section for background information.
$n = 1
and$n++
are assignments and therefore do not produce output.$n
is an expression whose value is output$null
- ditto, but even though it is output, it doesn't display by default($n++)
- due to enclosure in(...)
- turns the assignment into an expression and therefore does output the assigned value (too).- However, because you've used the post-increment form of the assignment, it is the old value that is output, not the now incremented value; to increment first (pre-increment) and then output, use
(++$n)
- However, because you've used the post-increment form of the assignment, it is the old value that is output, not the now incremented value; to increment first (pre-increment) and then output, use
[System.Console]::WriteLine("Hello")
prints directly to the console, which bypasses PowerShell's system of output streams.- This means you cannot capture or redirect such output from inside PowerShell (see the next section).
Tip of the hat to iRon for his help.
PowerShell, following the model of traditional shells, is organized around streams - see the conceptual about_Redirection help topic for an overview of all 6 streams that PowerShell supports.[1]
That is, any statement - and therefore potentially multiple ones - in a script or function can write to any of the output streams.
The primary output stream, meant to convey data, is the success output stream (whose number is 1
), and only it is sent through the pipeline by default, and therefore by default only it is captured in a variable, suppressed, or redirected to a file.
There are two ways to write to the success output stream, i.e. to produce data output:
Explicitly, with a
Write-Output
call - although that is rarely needed.Typically implicitly, by neither capturing, suppressing, nor redirecting output produced by a statement.
In other words: Output from any command (e.g.,
Get-ChildItem *.txt
) or expression (e.g,1 + 2
or(42).ToString('x')
) is sent to the success output stream by default.Unlike in traditional programming languages,
return
is not needed to produce output - in fact, its primary purpose is to exit the enclosing scope independently of any output the scope produces, though as a syntactic convenience you can combine the two aspects:return
is in effect the same as the following two statements, the first of which (potentially) produces output, the second of which exits the scope:; return
This implicit output behavior is convenient and and allows for concise, expressive code, but can also be a pitfall: it is easy to accidentally produce output - typically from a .NET method whose return value isn't needed (see this question for an example).
iRon's GitHub feature request #15781 discusses one potential way to remedy this problem: introduction of an opt-in strict mode that only permits using explicit output statements (
Write-Output
,return
) in order to produce output.This answer shows troubleshooting techniques you can use with the currently available features.
As for assignments - e.g. $n = 1; $n += 1; ++$n; $n--
:
- By default they do not produce output.
- A hybrid case is the chaining form of a multi-assignment, e.g.
$a = $b = 1
, which assigns1
to both variables: statement-internally the assignment value is passed through, but the statement as a whole has no output.
- A hybrid case is the chaining form of a multi-assignment, e.g.
- However, as an opt-in you can make them pass the value(s) being assigned through via
(...)
, the grouping operator; e.g.($n = 1)
both assigns1
to variable$n
and outputs1
, which allows it to participate in larger expressions, such as($n = 1) -gt 0
- Note that the related
$(...)
(subexpression operator) and@(...)
(array-subexpression operator) do not have that effect - they wrap one or more entire statement(s), without affecting the enclosed statements' intrinsic output behavior; e.g.$($n = 1)
does not produce output, because$n = 1
by itself doesn't produce output; however,$(($n = 1))
does, because($n = 1)
by itself does.
- Note that the related
As for output enumeration behavior:
By default, PowerShell enumerates collections that are being output, in the spirit of streaming output: That is, it sends a collection's elements to the pipeline, one by one.
In the rare event that you do need to output a collection as a whole - which in general should be avoided, so as not to confound other commands participating in a pipeline, which usually do expect object-by-object input - you have two options:
, $collection
(sic; uses an aux. one-element wrapper array)- More explicitly, but less efficiently:
Write-Output -NoEnumerate $collection
- See this answer for more information.
As for outputting $null
:
$null
is output to the pipeline, but by default doesn't show.$null
by itself produces no visible output,but the following returns
$true
, demonstrating that the value was sent:
QUESTION
Morning folks.
I am scraping some data from a letting site using Beautifulsoup and Requests.
I am managing to get the data as needed but keep getting an error when I add .text any help would be appreciated, Code below and error further down. The ANC code does return correctly just with the error
...ANSWER
Answered 2021-Nov-02 at 11:16What the docs say beautifulsoup documentation:
How to check?AttributeError: 'NoneType' object has no attribute 'foo' - This usually happens because you called find() and then tried to access the .foo attribute of the result. But in your case, find() didn’t find anything, so it returned None, instead of returning a tag or a string. You need to figure out why your find() call isn’t returning anything.
QUESTION
Can somebody tell me how I can display all the pizzas and their toppings without displaying the same pizza multiple times with each topping?
name name Cajun Combo bacon crumble Cajun Combo ham Cajun Combo spicy pepperoni Cajun Combo Cajun spice Cajun Combo Fresh garlic Cajun Combo garlic sauce topping Bistro black pepper Bistro cheddar cheese Bistro chili flakes Bistro pepperoni Bistro red onion BBQ King cream cheese BBQ King jalapeno BBQ King pepper cheese BBQ King pepperoni BBQ King pulled pork BBQ King BBQ topping Fiesta cream cheese Fiesta Fresh garlic Fiesta mushrooms Fiesta oregano Fiesta pepperoni Fiesta pineapple Italiana balsamic glaze Italiana cream cheese Italiana dates Italiana pepperoni Italiana semi dried tomatoes Italiana spinach Champion bacon crumble Champion black pepper Champion Fresh garlic Champion ham Champion jalapeno Champion mushrooms Champion pepperoni Champion pineapple Champion red onion ...ANSWER
Answered 2021-Sep-28 at 16:23You can use the group_concat
aggregate function:
QUESTION
I have a word game here made with javascript,
I play against a robot that guesses a word from a directory of words it has. If the guessed word have a matching letter and matching index it turns blue and gets displayed.
If any letter only exist in the guess word but not at correct index it turns orange.
The robot now randomly guesses the words and doesn't do anything with the blue or orange letters. I want the robot to filter the word directory it guesses from with the letters that are correct or exist in the guess word.
I can store those letters in two variable but I'm having scope problems to filter the word directory from the scope these variable
...ANSWER
Answered 2021-Aug-04 at 09:42You have too much code too see where the problem is happening. Is this the filter you are looking for?
QUESTION
Hi i am writing a javascript guessing game which on start of the page a random word is generated, then the user tries to guess the word, if the user guess the whole word correctly the word is turned to green and pushed to page. i have made this part. now here if the user guess doesn't match the random word I'm trying to compare the two words and if any letters in user guess matches the random words letters and both letters are at the same index the letter in the use guess becomes yellow and then pushed to the screen. but if the letters is in the wrong index but still exist in the other word i want that letter to be blue.i have tried to make them into arrays and compare them but i cant find the logic to do so.
...ANSWER
Answered 2021-Aug-03 at 11:09You can make use of String#includes()
and String#charAt()
to check each character in the userGuess
against the pickedWord
.
The snippet below uses the results to wrap each character in a span
of the appropriate color. You can refactor the HTML generated as needed.
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