deluca | Performant , differentiable reinforcement learning | Reinforcement Learning library

by google Python Version: 0.0.18 License: Apache-2.0

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | deluca Summary

deluca is a Python library typically used in Artificial Intelligence, Reinforcement Learning, Tensorflow applications. deluca has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install deluca' or download it from GitHub, PyPI.

Performant, differentiable reinforcement learning.

Support

Quality

Security

License

Reuse

Support

deluca has a low active ecosystem.

It has 105 star(s) with 13 fork(s). There are 8 watchers for this library.

It had no major release in the last 12 months.

There are 12 open issues and 21 have been closed. On average issues are closed in 53 days. There are 8 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of deluca is 0.0.18

Quality

deluca has no bugs reported.

Security

deluca has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

deluca is licensed under the Apache-2.0 License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

deluca releases are available to install and integrate.

Deployable package is available in PyPI.

Build file is available. You can build the component from source.

Top functions reviewed by kandi - BETA

kandi has reviewed deluca and discovered the below as its top functions. This is intended to give you an instant insight into deluca implemented functionality, and help decide if they suit your requirements.

Train the model .
Train a controller .
Plot the pressure .
Train a model .
Run a controller controller .
Run a controller .
r LQG .
Implementation of LQR algorithm .
Calculate the payoff function .
Validate the function .

Get all kandi verified functions for this library.

deluca Key Features

No Key Features are available at this moment for deluca.

deluca Examples and Code Snippets

No Code Snippets are available at this moment for deluca.

Community Discussions

Trending Discussions on deluca

Trying to extract Photoshop layer co-ordinates and dimensions

Filtering SELECT TOP WITH TIES When No Records Exist for a Specific Column

Python - find _any_ and _all_ matches in a nested list, and return the indices

QUESTION

Trying to extract Photoshop layer co-ordinates and dimensions

Asked 2020-Apr-28 at 13:56

Example Photoshop file:

...

ANSWER

Answered 2020-Apr-28 at 13:56

I've been tinkering for a couple of hours and managed to answer my own question. It's a bit hacky and I'm sure there is a more elegant solution but it works!

Here it is if anyone else needs it:

Source https://stackoverflow.com/questions/61478810

QUESTION

Filtering SELECT TOP WITH TIES When No Records Exist for a Specific Column

Asked 2018-Nov-28 at 00:21

Question: How can I filter my results (see below) to exclude erroneous data? I'm guessing my problem is somewhere in the WHERE clause but for the life of me, I can't figure it out.

End Goal: Return NULL values for the CDA_Orientation column where no values exist in the portfolio and e_component tables (e.g. employee has not had Orientation yet)

DB Schema:

Result Set with Errors:

NOTE: The Orientation dates for Eastman, DeLuca, and Fontano are the same date and represent the TOP 1 result from the course_startdate column of the portfolio table.

What I Want the Results to Look Like:

If I've done my JOINS correctly, the CDA_Orientation column should show NULL because there is no entry in the portfolio table (and accordingly, the e_component table) for these three individuals. The entry is only created by the front end when the Employee is assigned to a course.

Here is My Code:

...

ANSWER

Answered 2018-Nov-28 at 00:21

I believe the joins are the issue. Using WITH TIES in that way is also confusing if you're just trying to get a record for each person; I would use a GROUP BY. If you wanted to do it without a sub-query you could do:

Source https://stackoverflow.com/questions/53509782

QUESTION

Python - find _any_ and _all_ matches in a nested list, and return the indices

Asked 2018-Aug-21 at 20:55

Okay, so this is a bit of both Python 2.7, and Ren'Py, so bear with me (I'm rusty, so I might just be doing something incredibly stupid)

I have an input:

input default "0" length 20 value VariableInputValue('playstore_search')

This goes on to run a function to check for matches in (currently one) nested list:

...

ANSWER

Answered 2018-Aug-21 at 20:42

I recommend converting the entries in the nested-list to lowercase first and then search for the term using find(). Consider following function:

Source https://stackoverflow.com/questions/51955449

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install deluca

You can install using 'pip install deluca' or download it from GitHub, PyPI.
You can use deluca like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: