hass | home assistant and appdaemon scripts and configuration file
kandi X-RAY | hass Summary
kandi X-RAY | hass Summary
home assistant and appdaemon scripts and configuration file
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Sets up the configuration
- Save device data
- Set the current value
- Sets the variable
- Calculate the rain sensor
- Calculate the Fao56 for the given day of the week
- Estimate Fao56 for a given date
- Login to device
- Compute client proof
- Handle a state change
- Trigger water flow
- Called when the client is listening
- Called when a schedule event is received
- Set parser options
- Return all device state attributes
- Handle a button change
- Called when the client has been added
- Computes the mean squared separation between two values
- Time event handler
- Calculate the mean daylight hours of the month
- Calculate solar irradiance from sunrise and sunset
- Calculate the ET angle of a sun
- Update last day
- Handle a state change event
- Handle input
- Called when cube changes
hass Key Features
hass Examples and Code Snippets
Community Discussions
Trending Discussions on hass
QUESTION
list2 = [(2, 4), (2, 6), (2, 8), (2, 12), (3, 6), (3, 12), (4, 8), (4, 12), (6, 12)]
...ANSWER
Answered 2022-Mar-25 at 21:02The dict.setdefault
to group by the second values, by first, will solve that easily
QUESTION
I have a few lists
...ANSWER
Answered 2022-Feb-10 at 12:59Have a look at itertools.combinations
. It returns all possible combinations of a given length for a given iterable. You'll have to loop over all possible lengths.
QUESTION
I'm struggling with the Linux tool "iptables". Following situation: I have a RaspberryPi running with HASS (Home Assistant) connected via ethernet. Now I want to add my inverter to home assistant, but this needs to be done by using his own WiFi network. So I need to forward requests to IP 11.11.11.1 (only this IP, not all trafic) to the wifi network.
Is that doable with iptables? Meaning defining a rule which says "target is 11.11.11.1, so lets put this to the wifi network".
I'm actually not sure whether iptables can do that or not. I read soming about nginx, but not sure how this would work.
...ANSWER
Answered 2022-Jan-07 at 08:57iptables -A FORWARD -i eth0 -o wlan0 -p tcp --destination 11.11.11.1
QUESTION
Problem (briefly)
Documented functions are not listed on the related group page, but listed on the file's page. One of the functions listed on the file's page does not have documantation despite it is doumented in the source file.
Details
I'm using Doxygen v1.9.2 to document an embedded application written in C. I also use git as versioning tool. I had documented the code for example in v2.0.0 and everything was ok. Recently I made some improvements and added 2 new files and new functionalities in the application. I documented the newly added files as per instruction of doxygen and some stackoverflow topics, but I did not figure out why the new file is partially documented. Since the project is a little large relatively, I will try to illustrate the documentation structure and add only issue related parts to avoid crowd and focus to the issue.
Necessarily sharing he Doxyfile config; comments, blank lines and some directory paths are omitted for brevity:
...ANSWER
Answered 2021-Dec-02 at 19:32Since @albert didn't post an answer to check it as a solution, I needed to post an answer for anyone who struggle with the same problem.
Briefly the solution to this problem that I've faced was not to use nested grouping blocks. Grouping blocks start with @{
and end with @}
. This structure currently cannot be used nested in Doxygen v1.9.2.
As Albert pointed out and made me understand, I needed to make each grouping block as an individual block and without nesting. After doing this all documented members finally appeared on the html output page. I share the source code with fixed documentation for anyone who wants to compare the erroneous documentation (see the question) and the fixed working documentation.
QUESTION
I want to use a typed list in dart that can be one of the following types
...ANSWER
Answered 2021-Nov-01 at 23:24That should be TypedData
:
QUESTION
Let X be a set of distinct 64-bit unsigned integers std::uint64_t
, each one being interpreted as a bitset representing a subset of {1,2,...,64}.
I want a function to do the following: given a std::uint64_t
A, not necessarily in X, list all B in X, such that B is a subset of A, when A, B are interpreted as subsets of {1,2,...,64}.
(Of course, in C++ this condition is just (A & B) == B
).
Since A itself need not be in X, I believe that this is not a duplicate of other questions.
X will grow over time (but nothing will be deleted), although there will be far more queries than additions to X.
I am free to choose the data structure representing the elements of X.
Obviously, we could represent X as a std::set
or sorted std::vector
of std::uint64_t
, and I give one algorithm below. But can we do better?
What are good data structures for X and algorithms to do this efficiently? This should be a standard problem but I couldn't find anything.
EDIT: sorry if this is too vague. Obviously, if X were a std::set
we could search through all subsets of A, taking time O(2^m log |X|) with m <= N, or all elements of X in time O(|X| log |X|).
Assume that in most cases, the number of B is quite a bit smaller than both 2^m (the number of subsets of A) and |X|. So, we want some kind of algorithm to run in time much less than |X| or 2^m in such cases, ideally in time O(number of B) but that's surely too optimistic. Obviously, O(|X|) cannot be beaten in the worst case.
Obviously some memory overhead for X is expected, and memory is less of a bottleneck than time for me. Using memory roughly 10 * (the memory of X stored as a std::set
) is fine. Much more than this is too much. (Asymptotically, anything more than O(|X|) or O(|X| log |X|) memory is probably too much).
Obviously, the use of C++ is not essential: the algorithms/data structures are the important things here.
In the case that X is fixed, maybe Hasse diagrams could work.
It looks like Hasse diagrams would be quite time-consuming to construct each time X grows. (But still maybe worth a try if nothing else comes up). EDIT: maybe not so slow to update, so better than I thought.
The below is just my idea so far; maybe something better can be found?
FINAL edit: since it's closed, probably fairly - the "duplicate" question is pretty close - I won't bother with any further edits. I will probably do the below, but using a probabilistic skip list structure instead of a std::set
, and augmented with skip distances (so you can quickly calculate how many X elements remain in an interval, and thus reduce the number of search intervals, by switching to linear search when the intersection gets small). This is similar to Order Statistic Trees given in this question, but skip lists are a lot easier to reimplement than std::set
(especially as I don't need deletions).
Represent X as a std::set
or sorted std::vector
of 64-bit unsigned integers std::uint64_t
, using the ordinary numerical order, and do recursive searches within smaller and smaller intervals.
E.g., my query element is A = 10011010. Subsets of A containing the first bit lie in the inclusive interval [10000000, 10011010].
Subsets of A containing the second bit but not the first lie in the interval [00010000, 00011010].
Those with the third but not the second bit are in [00001000, 00001010].
Those with the fourth but not the third bit are in [00000010, 00000010].
Now, within the first interval [10000000, 10011010] you could make two subintervals to search, based on the second bit: [10000000, 10001010] and [10010000, 10011010].
Thus you can break it down recursively in this manner. The total length of search intervals is getting smaller all the time, so this is surely going to be better asymptotically than a trivial linear search through all of X.
E.g., if X = {00000010, 00001000, 00110111, 10011100} then only the first, third, fourth depth-1 intervals would have nonempty intersection with X. The final returned result would be [00000010, 00001000].
Of course this is unbalanced if the X elements are distributed fairly uniformly. We might want the search intervals to have roughly equal width at each depth, and they don't; above, the sizes of the four depth-1 search intervals are, I think, 27, 11, 3, 1, and for larger N the discrepancies could be much bigger.
If there are k bits in the query set A, then you'll have to construct k initial search intervals at depth 1 (searching on ONE bit), then up to 2k search intervals at depth 2, 4k at depth 3, etc.
If I've got it right, since log |X| = O(N) the number of search intervals is O(k + 2k + 4k + ... + 2^n . k) = O(k^2) = O(N^2), where 2^n = O(k), and each one takes O(N) time to construct (actually a bit less since it's the log of a smaller number, but the log doesn't increase much), so it seems like this is an O(N^3) algorithm to construct the search intervals.
Of course the full algorithm is not O(N^3), because each interval may contain many elements, so listing them all cannot be better than O(2^N) in general, but let's ignore this and assume that there are not enough elements of X to overwhelm the O(N^3) estimate.
Another issue is that std::map
cannot tell you how many elements lie within an interval (unlike a sorted std::vector
) so you don't know when to break off the partitioning and search through all remaining X elements in the interval. Of course, you have an upper bound on the number of X elements (the size of the full interval) but it may be quite poor.
EDIT: the answer to another question shows how to have a std::set
-like structure which also quickly gives you the number of elements in a range, which obviously could be adapted to std::map
-like structures. This would work well here for pruning (although annoying that, for C++, you'd have to reimplement most of std::map
!)
ANSWER
Answered 2021-Oct-29 at 04:33Treating your integers as strings of 0
and 1
, build a customized version of patricia tree, with the following rule:
- During lookup, if
1
is the current input bit at a branch, continue down both subtrees
The collection of all valid leaf nodes reached will be the answer.
ComplexityLet n be size of X,
Time: O(n)
- Worst case
-1
, when all subtrees are traversed. Complexity is bound by total number of nodes, stated below
Space: O(n)
- Number of nodes in a patricia tree is exactly 2n - 1
Given that your match condition is (A & B) == B
, a truth table is thus:
Hence, during lookup, we collect both subtrees on a branch node when the input bit is 1
.
QUESTION
I have a VueJs component, the data was originally on the page which worked well. It populated 3 drop-down menus. I want to move the data to a separate file hosted locally but I cant seem to get it to populate the drop-down menus. At the moment the first drop-down menu only displays the text 'data' which is the text from the top of the JS file. How do I get it to pull in all the data please? Any help is appreciated!
One of the select menus:
...ANSWER
Answered 2021-Aug-05 at 11:22Inside the JS file, remove the data object and export a normal object that contains your data.
After that, import that object in the component and add a computed method that will return it.
JS file -
QUESTION
I need some help in getting the table final_price values added to each other where the customer_name/customer_id is the same so the row count becomes 3 so example: the customer named Hass H final_price would be:
417 + 21 = 438 on one row
...ANSWER
Answered 2021-Aug-01 at 19:57You can use grouping sets
. I think this does what you want:
QUESTION
I am trying to make a query to see the total price a customer has to pay when their order is completed, but I am having issues with this error statement. How do I get the correct query?
ERROR: argument of HAVING must be type boolean, not type money
Tables involved and inserting some fake quick data:
Some of the customers:
...ANSWER
Answered 2021-Aug-01 at 15:08Cast 0
to money
to give zero the same type as the calculation and thus provide for a legal comparison:
QUESTION
So I got in WPF an ListBox where I got an Button in my ListBoxItem through an DataTemplate. Im adding that Button Like this to my Item:
...ANSWER
Answered 2021-Jul-07 at 11:44In RemoveMark_Click
the first argument (typically called sender
and of type object
) should by the Button
you clicked on, and its DataContext should be your collection item to remove.
So change RemoveMark_Click to sth like:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install hass
You can use hass like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page