reversing | stupid reversing stuff
kandi X-RAY | reversing Summary
kandi X-RAY | reversing Summary
stupid reversing stuff
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QUESTION
I am writing code to answer the following question: "for two linked lists l1 and l2 that contain positive integers (and have at least one node), return their sum as a linked list. "
For example:
...ANSWER
Answered 2021-Jun-14 at 13:51The reason for the error is that you cannot assume that both prev
and prev2
are not None
. Your while
condition only guarantees that at least one of them is not None
, but not both. So that means you still need to have a None
check inside the body of the loop.
There are also some other issues:
l1==[0]:
is not correct. The left side of this comparison is a linked list instance, while the right side is a standard list. These comparisons will always beFalse
, and so you can just omit themYou are adding the
carry
to the wrong sum. You should add thecarry
from the previous iteration to the current sum, so things are currently happing in the wrong order.The resulting list should be reversed. You can do this on the fly by prefixing each node to
l3
, instead of appending it. This will also make it unnecessary to create a dummyListNode(0)
before the final loop. You can just start withNone
.Your code mutates the original input lists. This will be acceptable on code challenge sites, and be efficient, but it is bad practice. The caller should not be unpleasantly surprised that the lists they provide as input have been reversed by a call to this
addTwoNumbers
function. You can solve this in several ways, but it is probably easiest to reverse them a second time to undo that operation.To avoid repetition of code, you should create a
reverse
function
I'll assume that the ListNode
constructor can take a second argument for initialising its next
reference:
QUESTION
I am taking a course about language design and this particular question has to do with how printf in C deal with issue of variable number of arguments. In essence, I learned that printf would push arguments from the last one all the way to the format string which stores information about offsets so that the frame pointer would find the format string and then use the offset derived from the format string to find arguments' offsets.
But the question I have asks for another way to deal with this problem when reversing of arguments is not allowed. This confuses me. For now, my approach is move the frame pointer to the lowest point of the runtime stack so that it finds format string and offsets to the actuals are positive.
Please advise
...ANSWER
Answered 2021-Jun-13 at 15:00If you were to design a new compiler for a different calling convention, you could have the compiler push the number of actual arguments with which the call was done, or set that number in a specific register such as RAX/EAX, which will be overridden anyway.
Another option would be to redefine the printf()
API to have the format string as the last parameter. In this way you will have all you need to access the stack looking for your parameters.
QUESTION
I'm writing to an MS Word document (.docx) using Apache POI from a JavaFX UI. the String is in Arabic, and when it contains one pair of brackets, the output is okay, but when there are 2 pairs or a quote, the output is messy, even though it appears okay in Eclipse's console too. Here's my code:
...ANSWER
Answered 2021-Jun-13 at 04:52The parentheses are not RTL text as your arabic text is. So it leads to problems if they are not marked as LTR text. See https://en.wikipedia.org/wiki/Bidirectional_text#Table_of_possible_BiDi_character_types.
So either you mark each LTR character using U+200E LEFT-TO-RIGHT MARK
and then RTL characters using U+200F RIGHT-TO-LEFT MARK (RLM)
.
Or you are using U+202E RIGHT-TO-LEFT OVERRIDE (RLO)
before the text line having LTR charcters ((
and )
) and RTL characters mixed and U+202C POP DIRECTIONAL FORMATTING (PDF)
after that text line. That tells the word processing software exactly where RTL starts and ends. That leads to correct output for me.
Complete example:
QUESTION
I have 2 simple capsules. 1 is stationary and the other is moving to the same tile on the tilemap using transform.position.
Both capsules have capsule colliders and rigid bodies. I've attempted to remove the rigid body but from what I can tell, the OnCollisionEnter function requires a rigid body to work.
My script, attached to both of these, is a simple:
...ANSWER
Answered 2021-Jun-12 at 19:36Here is an infographic
to show when a collision message will be detected by OnCollisionEnter
between two objects. Both objects will need some sort of collider, and will most likely need a Rigidbody
.
You will not want to set isTrigger
as that will not make it physically react to a collision, but will just detect when a collision occurs. It will also not call OnCollisionEnter
but will call OnTriggerEnter
. Setting both not as triggers, adding a collider, and giving them Rigidbodies
should allow the collision to be detected. You will also need to attach this script to one of the objects that have the collider. Are there other components on the objects you are using?
QUESTION
I'm looking for anything that can help me deviate string GetRTTIClassName(IntPtr ProcessHandle, IntPtr StructAddress)
. The function would use another (third-party) app's process handle to get names of structures located at specific addresses in its memory (should there be found any).
All of RTTI questions/documentation I can find relate to it being used in the same application, and have nothing to do with process interop. The only thing close to what I'm looking for is this module in Cheat Engine's source code (which is also how I found out that it's possible in the first place), but it has over a dozen of nested language-specific dependencies, let alone the fact that Lazarus won't let me build it outside of the project context anyway.
If you know of code examples, libraries, documentation on what I've described, or just info on accessing another app's low-level metadata (pardon my French), please share them. If it makes a difference, I'm targeting C#.
Edit: from what I've gathered, the way runtime information is stored depends on the compiler, so I'll mention that the third-party app I'm "exploring" is a MSVC project.
As I understand, I need to:
- Get address of the structure based on address of its instance;
- Starting from structure address, navigate through pointers to find its name (possibly "decorated").
I've also found a more readable C# implementation and a bunch of articles on reversing (works for step 2), but I can't seem to find step 1.
I'll update/comment as I find more info, but right now I'm getting a headache just digging into this low-level stuff.
...ANSWER
Answered 2021-Jun-12 at 20:23It's a pretty long pointer ladder. I've transcribed the solution ReClass.NET uses to clean C# without dependencies.
Resulting library can be found here.
QUESTION
I created table of 500 rows, and reversing it on click feels slow, subjectively like 500ms or so.
Is it reasonable performance? I have a feeling that reversing table of 500 lines in JS should be faster.
Svelte demo and Pure JS demo.
Pure JS feels much faster than Svelte
Table.svelte
...ANSWER
Answered 2021-Jun-11 at 23:14I first thought that it has something to do with the index not working properly, but when adding a 'slice' button and a fade-effect it seems to work fine -> the first item fades out and after it was totally removed the other elements move up.
SEE THIS slightly modified version of yours
- 'slice' button and effect on StringView added
- timer in console tracking time before -> after Update
Nevertheless, since I already wondered how to properly define the id on arrays an nested each loops (Nested each loops over array in Svelte - how to set unique id / key?) I made a version with objects instead of row-arrays and just one Component for the rows. When comparing the time for updating, it's almost twice as fast ( firstLoad/Update --> ≈700ms/250ms --> 330ms/160ms (in Firefox)) -> See this REPL
I'm still wondering if this might be optimized, since even when the id/key seems to work, every TableRow-Component logs an Update when the order is reversed or the first element is sliced. I once made a very simple example which behaves differently and only elments without id log an update -> see this REPL
(this part of your code could be written shorter ->
QUESTION
I have a very basic question about linked list
say I reverse the following linked list:
#1->2->3->4
to become 4->3->2->1
And say I start first with reversing the pointer that points from 1 to 2; so that 2 points to 1. My question is, does the pointer/connection from 1 to 2 still exist when I do this?
Or does this connection get removed when we do 2->1?
A further question if the above is true, is "does the original connection 1->2->3->4 always hold, no matter what we do to the pointers; or does it get removed, if say I changed the pointer at 1 to point at 3; i.e. 1->3 ; then does the connection 1->2 gets removed automatically?
...ANSWER
Answered 2021-Jun-12 at 08:23Usually a node in a linked list has a single reference to another node: the next one.
When you have a list with 4 nodes, you can visualise it like this:
QUESTION
I'm writing this code for more than 3 hours already..
I gave up about the overflow thing and tried to google and look it up on stackoverflow.
I did not find any solution besides the one that I wrote in my code as you can see in lines 27-28
(where it returns 0).
But this condition also does not work.
ANSWER
Answered 2021-Jan-13 at 12:43The main thing you want to check for overflow is this:
QUESTION
I call a function signInModeIsEmail()
in the onPressed of my elevated button. It executes but, the issue is that it also runs a second function signInModeIsGoogle()
, reversing the boolean state.
These functions are in my ViewModel class:
...ANSWER
Answered 2021-Jun-05 at 23:41Well, of course. This:
QUESTION
I am reversing a singly- linked list with the following code:
...ANSWER
Answered 2021-Jun-05 at 13:35There are a few issues:
curr.next
has already been modified by the time you docurr = curr.next
. So instead of going forward in the list, you're going backward (sincecurr.next
is actually equal toprev
by that time).head.next
is never modified, yet it should becomeNone
. You should actually start one step "earlier" in the list, makingcurr
equal tohead
andprev
should beNone
.return curr
is always going to returnNone
, as that is the condition by which thewhile
loop exits.
Here is a fix:
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Install reversing
You can use reversing like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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