dictdiffer | Dictdiffer is a module that helps you to diff and patch

 by   inveniosoftware Python Version: 0.9.0 License: Non-SPDX

kandi X-RAY | dictdiffer Summary

kandi X-RAY | dictdiffer Summary

dictdiffer is a Python library typically used in Utilities applications. dictdiffer has no bugs, it has no vulnerabilities, it has build file available and it has medium support. However dictdiffer has a Non-SPDX License. You can install using 'pip install dictdiffer' or download it from GitHub, PyPI.

Dictdiffer is a module that helps you to diff and patch dictionaries.
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              dictdiffer has a medium active ecosystem.
              It has 788 star(s) with 89 fork(s). There are 101 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 24 open issues and 43 have been closed. On average issues are closed in 62 days. There are 6 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of dictdiffer is 0.9.0

            kandi-Quality Quality

              dictdiffer has 0 bugs and 0 code smells.

            kandi-Security Security

              dictdiffer has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              dictdiffer code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              dictdiffer has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              dictdiffer releases are available to install and integrate.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              dictdiffer saves you 637 person hours of effort in developing the same functionality from scratch.
              It has 1481 lines of code, 154 functions and 15 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed dictdiffer and discovered the below as its top functions. This is intended to give you an instant insight into dictdiffer implemented functionality, and help decide if they suit your requirements.
            • Diff two objects .
            • Patch a diff result .
            • Look up a value in a nested dictionary .
            • Swap diff result .
            • Resolve conflicts .
            • Return the value of a wildcard .
            • Compare two arrays .
            • Unify conflicts between conflicts .
            • Initialize the dictionary .
            • Check if a conflict between two paths .
            Get all kandi verified functions for this library.

            dictdiffer Key Features

            No Key Features are available at this moment for dictdiffer.

            dictdiffer Examples and Code Snippets

            No Code Snippets are available at this moment for dictdiffer.

            Community Discussions

            QUESTION

            How to Parse a list of tuples with different number of key values
            Asked 2021-Dec-07 at 18:07

            I have a list of tuples like this.

            ...

            ANSWER

            Answered 2021-Dec-07 at 18:07

            Thanks to inputs from Barmar. This is how I got it.

            Source https://stackoverflow.com/questions/70263888

            QUESTION

            Accessing lists within multidimentional tuple
            Asked 2021-May-15 at 01:29

            I am new to Python ..

            I am able to generate the following output by comparing two dictionaries with dictdiffer and it is in oo variable:

            ...

            ANSWER

            Answered 2021-May-15 at 01:29

            The data structure seems to be tuples of tuples and lists.

            The below seems to work to get the desired results.

            Source https://stackoverflow.com/questions/67542516

            QUESTION

            Calculate difference or compare two dictionaries - Groundtruth and clustering
            Asked 2020-Jul-01 at 07:39

            I have two dictionaries h and c. Here 1,2,3 are the folder names and IMG_0001... are all image files contains in each particular folder.

            This is my groundtruth

            ...

            ANSWER

            Answered 2020-Jul-01 at 07:39
            from sklearn.metrics import accuracy_score
            
            h = {'1': ['IMG_0001.png', 'IMG_0002.png', 'IMG_0003.png', 'IMG_0004.png'],
                 '2': ['IMG_0020.png', 'IMG_0021.png', 'IMG_0022.png', 'IMG_0023.png'],
                 '3': ['IMG_0051.png', 'IMG_0052.png', 'IMG_0053.png', 'IMG_0054.png']}
            
            c = {'1': ['IMG_0001.png', 'IMG_0002.png', 'IMG_0053.png', 'IMG_0054.png'],
                 '2': ['IMG_0020.png', 'IMG_0021.png', 'IMG_0022.png', 'IMG_0023.png'],
                 '3': ['IMG_0003.png', 'IMG_0004.png', 'IMG_0051.png', 'IMG_0052.png']}
            
            images = []
            for key, value in h.items():
                images.extend(value)
            print(images)  # ['IMG_0001.png', 'IMG_0002.png', 'IMG_0003.png', 'IMG_0004.png', 'IMG_0051.png', ..., 'IMG_0023.png']
            
            reverse_h = {}
            for key, value in h.items():
                for img in value:
                    reverse_h[img] = key
            print(reverse_h)  # {'IMG_0003.png': '1', 'IMG_0051.png': '3', 'IMG_0004.png': '1', ..., 'IMG_0054.png': '3'}
            
            y_true = [reverse_h[img] for img in images]
            print(y_true)  # ['1', '1', '1', '1', '3', '3', '3', '3', '2', '2', '2', '2']
            
            reverse_c = {}
            for key, value in c.items():
                for img in value:
                    reverse_c[img] = key
            
            print(reverse_c)  # {'IMG_0053.png': '1', 'IMG_0020.png': '2', 'IMG_0003.png': '3', ..., 'IMG_0054.png': '1'}
            
            y_pred = [reverse_c[img] for img in images]
            print(y_pred)  # ['1', '1', '3', '3', '3', '3', '1', '1', '2', '2', '2', '2']
            
            score = accuracy_score(y_true, y_pred)
            print(score)  # 0.6666666666666666
            

            Source https://stackoverflow.com/questions/62652691

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install dictdiffer

            You can install using 'pip install dictdiffer' or download it from GitHub, PyPI.
            You can use dictdiffer like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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            Install
          • PyPI

            pip install dictdiffer

          • CLONE
          • HTTPS

            https://github.com/inveniosoftware/dictdiffer.git

          • CLI

            gh repo clone inveniosoftware/dictdiffer

          • sshUrl

            git@github.com:inveniosoftware/dictdiffer.git

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