dictdiffer | Dictdiffer is a module that helps you to diff and patch
kandi X-RAY | dictdiffer Summary
kandi X-RAY | dictdiffer Summary
Dictdiffer is a module that helps you to diff and patch dictionaries.
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Top functions reviewed by kandi - BETA
- Diff two objects .
- Patch a diff result .
- Look up a value in a nested dictionary .
- Swap diff result .
- Resolve conflicts .
- Return the value of a wildcard .
- Compare two arrays .
- Unify conflicts between conflicts .
- Initialize the dictionary .
- Check if a conflict between two paths .
dictdiffer Key Features
dictdiffer Examples and Code Snippets
Community Discussions
Trending Discussions on dictdiffer
QUESTION
I have a list of tuples
like this.
ANSWER
Answered 2021-Dec-07 at 18:07Thanks to inputs from Barmar. This is how I got it.
QUESTION
I am new to Python ..
I am able to generate the following output by comparing two dictionaries with dictdiffer
and it is in oo
variable:
ANSWER
Answered 2021-May-15 at 01:29The data structure seems to be tuples of tuples and lists.
The below seems to work to get the desired results.
QUESTION
I have two dictionaries h and c. Here 1,2,3 are the folder names and IMG_0001... are all image files contains in each particular folder.
This is my groundtruth
...ANSWER
Answered 2020-Jul-01 at 07:39from sklearn.metrics import accuracy_score
h = {'1': ['IMG_0001.png', 'IMG_0002.png', 'IMG_0003.png', 'IMG_0004.png'],
'2': ['IMG_0020.png', 'IMG_0021.png', 'IMG_0022.png', 'IMG_0023.png'],
'3': ['IMG_0051.png', 'IMG_0052.png', 'IMG_0053.png', 'IMG_0054.png']}
c = {'1': ['IMG_0001.png', 'IMG_0002.png', 'IMG_0053.png', 'IMG_0054.png'],
'2': ['IMG_0020.png', 'IMG_0021.png', 'IMG_0022.png', 'IMG_0023.png'],
'3': ['IMG_0003.png', 'IMG_0004.png', 'IMG_0051.png', 'IMG_0052.png']}
images = []
for key, value in h.items():
images.extend(value)
print(images) # ['IMG_0001.png', 'IMG_0002.png', 'IMG_0003.png', 'IMG_0004.png', 'IMG_0051.png', ..., 'IMG_0023.png']
reverse_h = {}
for key, value in h.items():
for img in value:
reverse_h[img] = key
print(reverse_h) # {'IMG_0003.png': '1', 'IMG_0051.png': '3', 'IMG_0004.png': '1', ..., 'IMG_0054.png': '3'}
y_true = [reverse_h[img] for img in images]
print(y_true) # ['1', '1', '1', '1', '3', '3', '3', '3', '2', '2', '2', '2']
reverse_c = {}
for key, value in c.items():
for img in value:
reverse_c[img] = key
print(reverse_c) # {'IMG_0053.png': '1', 'IMG_0020.png': '2', 'IMG_0003.png': '3', ..., 'IMG_0054.png': '1'}
y_pred = [reverse_c[img] for img in images]
print(y_pred) # ['1', '1', '3', '3', '3', '3', '1', '1', '2', '2', '2', '2']
score = accuracy_score(y_true, y_pred)
print(score) # 0.6666666666666666
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install dictdiffer
You can use dictdiffer like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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