l3 | Learning with latent language

In pandas you can do groupby with pd.crosstab

Get the index of columns with substring L1 to L3 using grep. Extract the columns, multiply with the value 0.1343109 and update by assigning back to the columns. (Note - multiplying by 1 returns the same value, thus it is left as such)

The reason for the error is that you cannot assume that both prev and prev2 are not None. Your while condition only guarantees that at least one of them is not None, but not both. So that means you still need to have a None check inside the body of the loop.

There are also some other issues:

• l1==[0]: is not correct. The left side of this comparison is a linked list instance, while the right side is a standard list. These comparisons will always be False, and so you can just omit them

• You are adding the carry to the wrong sum. You should add the carry from the previous iteration to the current sum, so things are currently happing in the wrong order.

• The resulting list should be reversed. You can do this on the fly by prefixing each node to l3, instead of appending it. This will also make it unnecessary to create a dummy ListNode(0) before the final loop. You can just start with None.

• Your code mutates the original input lists. This will be acceptable on code challenge sites, and be efficient, but it is bad practice. The caller should not be unpleasantly surprised that the lists they provide as input have been reversed by a call to this addTwoNumbers function. You can solve this in several ways, but it is probably easiest to reverse them a second time to undo that operation.

• To avoid repetition of code, you should create a reverse function

I'll assume that the ListNode constructor can take a second argument for initialising its next reference:

The function week_no is not vectorised so you would need some kind of loop to iterate over each value after strsplit. In the for loop you use sapply, so we can use the same here.

If you read the assembler code from the top you will see that it reaches .L3, plus it also jumps to it with jne .L3, which is your for loop in C.

@ima, Accessing L2|L3|L4 are easily covered in DPDK examples. For your particular requirement DPDK example, l3fwd easily covers the scenario. Hence my humble recommendation is to refer to such an application first.

The answer to your query is the way in which you are trying to access the L3 headers is incorrect. To properly access the L3 header you will need to changes from

It seems that you're looking for a tile plot. Here is an approach with ggplot2:

Maybe you can try crossprod like below

Here is one way: