daiquiri | Python library to easily setup basic logging functionality

by jd Python Version: Current License: Apache-2.0

X-Ray Key Features Code Snippets Community Discussions(8)Vulnerabilities Install Support

kandi X-RAY | daiquiri Summary

daiquiri is a Python library typically used in Logging applications. daiquiri has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install daiquiri' or download it from GitHub, PyPI.

Python library to easily setup basic logging functionality

Support

Quality

Security

License

Reuse

Support

daiquiri has a low active ecosystem.

It has 316 star(s) with 22 fork(s). There are 10 watchers for this library.

It had no major release in the last 6 months.

There are 6 open issues and 14 have been closed. On average issues are closed in 17 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of daiquiri is current.

Quality

daiquiri has no bugs reported.

Security

daiquiri has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

daiquiri is licensed under the Apache-2.0 License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

daiquiri releases are not available. You will need to build from source code and install.

Deployable package is available in PyPI.

Build file is available. You can build the component from source.

Top functions reviewed by kandi - BETA

kandi has reviewed daiquiri and discovered the below as its top functions. This is intended to give you an instant insight into daiquiri implemented functionality, and help decide if they suit your requirements.

Format a record
Add color to record
Remove color from record
Configure the root logger
Add this handler to the given logger
Return the path to the log file
Gets the program name
Parse the default log levels
Set default log levels

Get all kandi verified functions for this library.

daiquiri Key Features

No Key Features are available at this moment for daiquiri.

daiquiri Examples and Code Snippets

No Code Snippets are available at this moment for daiquiri.

Community Discussions

Trending Discussions on daiquiri

Train new model with Spacy

How To make 2 or more tables From one JSON data

How to Hide / Show Image on HTML page

How to move text to New line of same row when text is bigger

How to hide/show HTML table rows at an interval

VBA for-loop adding blank dictionary entries

python if statement text

Bootstrap accordions and tabbed nav in one page?

QUESTION

Train new model with Spacy

Asked 2019-Jul-31 at 21:50

I am using Spacy for a model of recognition of named entities, Update of the Recognition of the Named Entity the documentation provided me with this code to update an existing model, this code only specifies the model that will be used as a base, the place where it would be stored and the Number of iterations

...

ANSWER

Answered 2019-Jul-31 at 21:50

I solve this removing plac.

Source https://stackoverflow.com/questions/57203633

QUESTION

How To make 2 or more tables From one JSON data

Asked 2019-Jun-30 at 05:35

I am working on creating dynamic HTML table from JSON Data, I have already created the table dynamically but now I have to Change it with new Requirement

What I am doing

I have array of objects from which i am creating the table and spiting the table into four columns by dividing the length of JSON to 4
My table is rendering perfectly into 4 columns

What I am trying to Do

I want to show only 5 Rows in a single go then reloads the div and render the next five rows in same dive and so on until all data gets render
Currently I have 68 total data so i am populating it as 17 rows of 4 columns
Now on one go when page lodes I want to show 5 rows then after 5 seconds Next 5 rows in same div
In simple terms I want to split my JSON data into part of 5-5 rows and show only 5 rows at once then next five after 5 seconds
Spiting the Table into Four Columns I have done already,now just want to Show only five rows at a time
I am lacking with idea or approach how to do this, How can i divide my JSON in five-five rows and show them at each time interval of 5 seconds

What I am have done

...

ANSWER

Answered 2019-May-28 at 09:51

Instead of creating the rows after every 5 seconds, you can create the rows in one go and hide them all using a class .hidden. Then every 5 seconds make first 5 hidden rows visible.

Source https://stackoverflow.com/questions/56339301

QUESTION

How to Hide / Show Image on HTML page

Asked 2019-Jun-04 at 21:47

I am working with Dynamic HTML table in which I am showing my data as in HTML table as my data is in large amount so what I am doing is showing amount of data which will be fixed to one screen, So here i am showing 12 rows at one time then after 5 seconds page refresh hen next 12 and so on, When it reaches to the last page than what I am doing is calling the JSON object again and doing whole process again because in my code that JSON data will be dynamic

Issue I am facing

I have done all the things to refresh page after 5 seconds and calling whole data when it reaches to last page
Now what I am trying to do is when it is the last page than after that want to show a image for 10 seconds than again call the whole process
Now the whole process on first go will be like table will show 12 rows than if there is more data it will show next 12 row of table and when it reaches the last page I want to show an Image for 10 seconds then call the JSON object again to go through whole process again
In my code I have commented What I am doing where

...

ANSWER

Answered 2019-Jun-03 at 07:15

I think this will help you.

Source https://stackoverflow.com/questions/56422075

QUESTION

How to move text to New line of same row when text is bigger

Asked 2019-May-29 at 10:28

I am working on HTML table and i am stuck here for very long now, I have a requirement of displaying table into four columns/grid which i have done

Now when i am rendering the table i am displaying first 17 rows in one go than next 17 after five seconds

What is the issue

some ItemNames are big like BIG BANAYAN CARBINET SAUVIGNON BY GLASS
So when page is refreshing after five seconds the the column which contains this long name gets very large width which is not good to see as on UI
I am trying to make the width of each column uniform all four will have same width
So when the long ITEM NAME is coming what I am trying to do is to use word-wrap: normal; to break it after some width,but it is not working
I am dividing the four columns into equal part, which ever screen it is rendering the table it should be divided into 4 parts and when ITEMNAME is large i want to display it into same row but in new line after that exceeds the width of column
I think i have to give some sort of height to all the rows when it can accept one single small item name then it will show in single row but when the name is large it should show in same row but in two lines with same font

...

ANSWER

Answered 2019-May-29 at 09:24

You are getting the data in four rows using the for loop. I would suggest you should use bootstrap class="col-sm-3" in your html file table tag. This wraps the string how long it is and displays four rows with equal space. Also import

Source https://stackoverflow.com/questions/56356668

QUESTION

How to hide/show HTML table rows at an interval

Asked 2019-May-28 at 16:56

I am working on HTML tables. Here I have made a table and split into four columns to show up on a display screen, the table is fully dynamic.

Now what I have to do is to show 5 rows at a time on the screen. I am using CSS to do that. What I am doing is creating table in one go and populating the first 5 rows at once; then after 5 seconds that content gets refreshed and I have to show next five rows this will go on until the all the data loads

What I have tried

...

ANSWER

Answered 2019-May-28 at 16:38

Your function showRows() only removes class hidden, it won't hide the previous five. And your selector is based on the element that has hidden class. So, even though if you hid the previous five, it will just show that five items again. The easy way to fix this is giving each table row an index and hide item based on their index, or rework your selector to select which five you want to display.

Source https://stackoverflow.com/questions/56345863

QUESTION

VBA for-loop adding blank dictionary entries

Asked 2019-Apr-05 at 06:09

I'm trying to replace some values in an Excel worksheet by using a VBA dictionary. When I did this last year, it worked perfectly. Upon trying it again it is adding blank values to duplicate keys, and not writing anything to the cells as a result.

I've tried both early binding and late binding with no success.

Here is the code with late binding.

...

ANSWER

Answered 2019-Apr-05 at 06:09

Dictionaries actually use variants for keys rather than strictly strings or numbers, which is why when looping through keys you have to define k as a variant. A key can actually be anything.

Also, dictionaries add new keys spontaneously if you refer to a key that isn't already defined, which is why you have to use the safe function Exists to test whether a key has been defined.

VBA, being the undisciplined beast that it is, tries to be helpful in determining what you want when you refer to a Range() object in code. If a range object can be used, then it will use the range object. If a string/number is expected, then it will use the value of the Range() object instead (being the default property).

Because dictionaries can take any object as a key, rather than using the value in Cells(i, 4), it uses the actual range object of Cells(i, 4) and creates a new key with no value. You can see this in the Locals windows, which shows the sub-types of the variant dictionary keys:

When you debug.print keys at the end, the print function expects a string/number. So when it reaches the "duplicate" keys, which are actually range objects, it instead prints the value of the range object.

In stepping through the code, you can actually get any range properties of those keys in the immediate window instead! For example: ?k.Address

To fix your code, you just need to explicitly refer to the value of the cell:

Source https://stackoverflow.com/questions/55528021

QUESTION

python if statement text

Asked 2018-Dec-10 at 10:30

x =(soup.find_all('p'))
if (x.find('British dishes') != -1): 
    print ("TRUE")
else: 
    print ("FALSE")

...

ANSWER

Answered 2018-Dec-10 at 10:30

In your example, you need to go through each

tag text with a loop, and make sure your searching for text in one case, which can be lowercase, since British Dishes and British dishes won't match. You are also not calling .text on the

elements, which won't extract the text from the tag.

Fixed code:

Source https://stackoverflow.com/questions/53703272

QUESTION

Bootstrap accordions and tabbed nav in one page?

Asked 2017-Jul-27 at 05:58

I have a site I'm building and I want to have tab nav with different accordion things on each tab. I've done this; but the one tab I've placed it in copies over to the other tabs.

I want it so that each tab has a different set of accordion links that load different things per tab.

Is this possible?

(edit): here's what I have so far:

the html:

...

ANSWER

Answered 2017-Jul-27 at 05:50

Replace Your whole html with following, You didn't close properly.

Try this:

Source https://stackoverflow.com/questions/45321259

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install daiquiri

You can install using 'pip install daiquiri' or download it from GitHub, PyPI.
You can use daiquiri like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: