benford | Benford's Law
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kandi X-RAY | benford Summary
Benford's Law
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QUESTION
ANSWER
Answered 2022-Mar-19 at 00:56to_extract <- list(MAD.conformity = c('MAD.conformity'),
n = c('info', 'n'))
top_vendors %>%
split(.$VendorNum) %>%
map(~ benford(number.of.digits = 1, discrete = TRUE, sign = "positive", data = .x$Amount)) %>%
map_df(~map(to_extract, ~.y[[.x]], .x), .id = 'VendorNum')
# A tibble: 4 x 3
VendorNum MAD.conformity n
1 2001 Nonconformity 4735
2 3630 Acceptable conformity 13361
3 4984 Acceptable conformity 4311
4 6661 Nonconformity 4133
QUESTION
I need to extract specific information from a list in R. My data is 'Benford' object and doesn't seem to be coercible using as_tibble()
My data looks as follows:
...ANSWER
Answered 2022-Mar-18 at 10:06You can use purrr::map_dfr()
to extract MAD.conformity
on each iteration, row-bind the results, and add an .id
column containing the names of each element of dat_list
. Since dat_list
was created by split
ting on CITY
, the names already correspond to the levels of CITY
. (I'm not familiar with the structure of Benford
objects, so you may have to tweak the $MAD.conformity
index.)
QUESTION
I have Benford test results, test_show
ANSWER
Answered 2021-Nov-23 at 17:20As of Python 3.8 you can use NormalDist to calculate a confidence interval as explained in detail here. With a slight adjustment to that approach you can include it in your setup with fig.add_traces()
using two go.Scatter()
traces, and then set fill='tonexty', fillcolor = 'rgba(255, 0, 0, 0.2)')
for the last one like this:
QUESTION
I want to have a bar plot and a line plot on the same axis.
The line plot should be above the bars, colors should cycle as would be expected with two consecutive calls to plt.plot()
.
ANSWER
Answered 2021-Nov-12 at 10:09This answer is a follow-up to a comment by the OP
Why doesn't it cycle further by the prop_cycler?
The reason why is, even if the prop_cycle
is loosely defined as a property of the axes
(you retrieve it using plt.rcParams['axes.prop_cycle']
), in reality the axes.bar
method and the axes.plot
method, during initialization, instantiate separate copies of the cycler so, by default (as Matplotlib 3.4), the bars and the lines both start from blue
QUESTION
ANSWER
Answered 2021-Oct-15 at 19:32I had installed the R
plugin and did not restart the IDE. In the past Intellij-Idea had always required a restart. I had thought - given I was not required to restart before using the plugin - that maybe in the lastest 2021.2.X they had relaxed that requirement.
Well what happened is the plugin partially worked : syntax highlighting popped up and the R commands / menu items appeared. But apparently this "install plugins without restart" is not reliable - at least for the R
plugin. After restarting IJ the problem desribed inthe question disappeared and R scripts appear to be working within Intellij now.
QUESTION
I'm actually creating a package for the Benford Law (for academic purpose). And I'm trying to perform a goodness of fit with the "chisq.test".
I've this vector :
prop = [1377 803 477 381 325 261 253 224 184]
That I want to compare with this vector of probabilities (1st digit from Benford Law) :
th = [0.301 0.176 0.125 0.097 0.079 0.067 0.058 0.051 0.046]
Thus, I perfom the test :
...ANSWER
Answered 2021-Aug-05 at 07:53I think the low p-value is because you have a good number of measurements, and the data just doesn't fit the theoretical expectation well enough.
If you had fewer measurements there would be more uncertainty and you would get higher p-values.
QUESTION
I'm trying to plot some different distributions from simulation and from observed in the same graph. The lines represent the distribution of simulation and have values from 1 to 9, which are samplings following Benford's law.
And the bar chart, which is the observed distribution, has some missing values (3,4,5,6) and these values are from the first digit of all the elements in the variable amount
. My final graph looks very strange. Could someone explain how to keep these missing values when I plot the bar chart? Thank you very much.
ANSWER
Answered 2021-Feb-17 at 08:16The problem is that the values
for the bars are stored as strings. Matplotlib plots these strings like any other strings, placing them side-by-side on the x-axis starting at location 0 up to the last string at position 4 (bar for digit 9). You can verify this by adding print(plt.xticks())
to your code just before plt.show()
.
To solve this, you must use an array of integers. In the following example, this is done by changing the data type of first
. In addition, the ticks are edited to show a tick label for each integer in the range of values:
QUESTION
First time around here, and I'm an awful dev, so forgive in advance my possibly numerous mistakes :)
here's my issue: I'm trying to make a program that checks the proportions of each number from 1 to 9 in an array (I'm putting Benford's Law to the test), for that I have created 9 different variables (basically nX where X=1-9), I'm reading through my array with a for loop, and incrementing on each of my variables every time that the corresponding number is found (if array[i]= X, nX++), and I then console log my array. The issue is that on that console log, all values in my array are set to "1", which isn't the case prior to the execution of these few lines. So I'm not quite sure what happens, but I'm guessing that my "if" checks are returning "true" and changing the value of my array elements to 1 to reflect that. So my question would be: any of you wise wizards know what I'm doing wrong and how to keep my data from being corrupted by this operation?
here's some code:
...ANSWER
Answered 2020-Aug-03 at 10:47In your expression, you need use boolean expression instead of assignment, e.g. if (benfordArrayProcessed[i] == 1)
. The values in the error get overwritten with because of assignment int he first statement itself and that's the reason you see 1 for all the elements.
QUESTION
I found this package for R: https://rdrr.io/cran/BenfordTests/man/ks.benftest.html
It allows you to perform a Kolmogorov Smirnov test against the Benford distribution (https://en.wikipedia.org/wiki/Benford%27s_law) given a list of numbers.
I am looking for the equivalent in Python (preferrably, I could install it via conda) but my Google searches were so far in vain. Any input appreciated, thank you.
...ANSWER
Answered 2020-Apr-29 at 11:04I would recommend checking out this link: https://github.com/nyoshimizu/benfordspy. It's not downloadable via Conda, but you can install it directly from GitHub.
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Install benford
You can use benford like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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