kth | High performance Bitcoin development platform | Cryptocurrency library
kandi X-RAY | kth Summary
kandi X-RAY | kth Summary
High performance Bitcoin development platform
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Top functions reviewed by kandi - BETA
- Create release branch
- Update the project version
- Finds and replaces old_str with new_str
- Find and replace old_str with old_str and new_str
- Get all files in kth project
- Create a new pull
- Clone the kth repository
- Commit a new version
- Creates a new branch
- Call update version
- Parse command line arguments
- Update the CMakeLists
- Create tag for each project
- Make a new tag
- Return the CONAN request version
- Get the content of a file
- Return the version
- Return channel info
kth Key Features
kth Examples and Code Snippets
Lines of Code : 45License : Permissive (MIT License)
Copypublic static int findKthSmallestElement(int k, int[] list1, int[] list2) throws NoSuchElementException, IllegalArgumentException {
checkInput(k, list1, list2);
// we are looking for the minimum value
if(k == 1) {
def kth_number(lst: list[int], k: int) -> int:
"""
Return the kth smallest number in lst.
>>> kth_number([2, 1, 3, 4, 5], 3)
3
>>> kth_number([2, 1, 3, 4, 5], 1)
1
>>> kth_number([2, 1, 3, 4, public List findTopK(List input, int k) {
List array = new ArrayList<>(input);
List topKList = new ArrayList<>();
for (int i = 0; i < k; i++) {
int maxIndex = 0;
for (int j = 1; j < Community Discussions
Trending Discussions on kth
QUESTION
I am challenged with the following problem: I need to write a program that takes as input n intervals [a,b], and m pairs (k,d). For each (k,d) pair, the program should output the length of the kth shortest interval (where the length of an interval is defined as b - a + 1) where a <= d <= b. If d is not within any interval, or d is within less than k intervals, the program should output -1.
Example input/output:
The first integer (5) represents n. The next n lines contain intervals (so [2..4], [2..6], etc). Following is the integer m (3), followed by m lines of pairs (k,d).
I am looking for an algorithm that solves this problem as quickly as possible.
...ANSWER
Answered 2021-Jun-07 at 19:33This can be solved in O((n + m) log n) time with a sweep line algorithm.
Sweep line algorithms set up a list of timed events and then process it in sorted order. For this problem, each interval [a, b] gives rise to a start event at time a and a stop event at time b. Each query (k, d) gives rise to a query event at time d. Since the intervals are fully closed, at each time, we process start events, then query events, then stop events.
We maintain a sorted list of the interval lengths stabbed by the sweep point. To process a start event, add the length of the interval to the list. To process a stop event, remove the length of the interval from the list. To process a query event, retrieve the kth element of the list. A sorted list data structure that supports all of these operations in O(log n) time is a red-black tree where each node contains the number of nodes in its left subtree. This is pretty much the canonical example of a tree augmentation, so CLRS and many other sources should have details.
QUESTION
I'm having trouble analyzing the running time of the following iterative function, written in pseudocode:
...ANSWER
Answered 2021-May-27 at 16:22You need to go in steps. You start with :
QUESTION
Is this below function is a tail recursion? And how to write it more efficiently and clearly.
Based on this question: We build a table of n rows (1-indexed). We start by writing 0 in the 1st row. Now in every subsequent row, we look at the previous row and replace each occurrence of 0 with 01, and each occurrence of 1 with 10.
For example, for n = 3, the 1st row is 0, the 2nd row is 01, and the 3rd row is 0110. Given two integer n and k, return the kth (1-indexed) symbol in the nth row of a table of n rows.
...ANSWER
Answered 2021-May-23 at 04:25Is your function currently tail recursive? No. The recursive call is then followed by a call to getValue.
Your function can be cleaned up dramatically, however. We will begin by replacing 0 and 1 with False and True.
QUESTION
Given a decimal number m. Convert it into a binary string and apply n iterations, in each iteration 0 becomes 01, and 1 becomes 10. Find the kth (1-indexing) character in the string after nth iteration.
Example 1:
Input: m = 5, n = 2, k = 5 output: 0 Explanation: Binary represntation of m is "101", after one iteration binary reprentation will be "100110", and after second iteration binary repreentation will be "100101101001".
Here is my code:
...ANSWER
Answered 2021-May-09 at 01:34A couple observations which may help. The first isn't critical but I point it out anyway.
- if the character at
iis0then it can't be1so no need to do the second check. So eliminate the condition following&&. This will help to improve performance somewhat by eliminating an unnecessary test. But keep your following else clause to properly append the desired replacement string.
QUESTION
I have a temperature corresponding to a coordinate. Over the fixed area, I want to include a square grid (all the grids must have the same length). For this end I use numpy.meshgrid to generate the cells over my entire area. Now my question is how to sum up the temperature of each row whose coordinate are in kth cell? I am a bit confused as should I use the numpy.histogram2d? It is giving me the frequency of X and Y, does it mean I have to use multidimensional histogram?
Many thanks in advance!
...ANSWER
Answered 2021-Apr-20 at 18:33This takes your data set, and produces a 20x20 array that contains the average temperature of all the points within that grid. If there are no temps in a grid, it will produce a NaN:
QUESTION
I have to find the most frequent number (or mode) from a sorted array of ranges. This range consists simply of a start and end number that is inclusive. As an example arr[0] could contain the numbers {0, 3}, which would then mean the numbers {0, 1, 2, 3}. The ranges are sorted by start number, and when start numbers are equal they are sorted by the end number. Both in ascending order.
The array is filled with n of these ranges. I need to find a way to find the number that occurs in the most ranges.
I have thought of a solution that goes through all the numbers once, but this is in O(n * m), where m is the average length of the ranges. This is an horrendously slow algorithm for the size I am dealing with.
I have also looked at some faster solutions such as this, but I can't think of an efficient way of implementing it when you cannot easily find the kth number, because the ranges can be wildly different sizes.
I'm currently trying to implement this in C, but any idea's or links to resources dealing with this are greatly appreciated.
Solved:
Someone pointed out Finding the most frequent number from a set of ranges - to me.
...ANSWER
Answered 2021-Apr-20 at 14:45- Convert each ranges
{a, b}to two events "add 1 ata" and "subtract 1 atb+1". - Sort the events by ascending order of where to add or subtract. subtract events should be come earlier than add events for same position.
- Execute the events and check at what point the result of calculation became highest.
For example, if we have 3 ranges {0, 5}, {2, 9}, {4, 7}, each range will be like this:
QUESTION
Looking for alternative algorithms
Below are the ones l have made but are being flagged as incorrect by the Online Judge on a coding website.
After declaring variable of int data type k, l received an input from the console using cin(). Since the constraints of the question read that the possible number(s) is/are between 1 and 20000, l first off opened a for loop using these conditions. At every iteration of i (one after the other), the number is tested whether its digits sum up to 10 and if they do, whether its the kth number whose digits are of sum 10.
To find the sum of digits, l used either a recursive function or an iterative method using a while loop. Hence the two snippets of codes. In both methods, the sum is calculated by finding the digits first using modular % operator and division operator /. The sum is figured out and then further tested if its equal to 10 and if Yes, it is also tested if its the K th element by means of keeping count of all previous similar elements. After all conditions are satisfied, only then is the value i outputted using cout().
...ANSWER
Answered 2021-Apr-13 at 10:35You can solve this problem in a "recursive" way.
If a given number starts with the digit d, then the digits that follow must have the sum 10-d. As the numbers do not exceed 20000, they have at most 5 digits and the first is one of 0, 1.
A simple solution is to use four nested loops. Then you check if the last digit is legal.
QUESTION
I have a scoring matrix called argRcount. The data is in form of a matrix where rownames indicate nucleotide names a/t/c/g and there are k = 18 columns indicating 1 to kth value of each of the nucleotide.
I have another data (list actually) where first item contains gene-names and second item contains a vector (character) of nucleotide sequence of say n characters. In the below example n=450.
What I actually want is to have a rolling sum for each gene, wherein first k consecutive nucleotide sequence will matched from matrix argRcount, thereafter from 2nd nucleotide to 19th, and so on for each gene. Thus in the end I will have n-k+1 values (rolling sum values) for each gene. In this particular example final outcome should have 433 values for each gene.
These are the dput of my data:
...ANSWER
Answered 2021-Apr-14 at 09:26In view of changed data in upstream BaseR strategy (without loading any extra pacakage/library)
QUESTION
I was trying to write code for determining permutations. In Wikipedia there is psuedo code for a simple algorithm (from BR Heap). I attempted to translate the psuedo code
...ANSWER
Answered 2021-Apr-09 at 21:39This is not really my kind of thing, but it looks to me at a glance as if the problem is that Swift arrays are passed by value, so we need an inout param here. Therefore I translated it like this:
QUESTION
I want to make the following code iterate through an object I created.
...ANSWER
Answered 2021-Mar-27 at 21:53Do you mean something like this?
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Install and configure the Knuth build helper:
Install the appropriate node executable:
Run the node:
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