corrplot | Create a correlation plot , as in the corrplot R package | Time Series Database library
kandi X-RAY | corrplot Summary
kandi X-RAY | corrplot Summary
Create a correlation plot, as in the corrplot R package.
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QUESTION
I'm looking to replicate this correlation plot, or at least get as close as possible to it.
Specifically, I want:
- the correlation values in the lower half, with values varying on a greyscale based on absolute value
- the circles in the top half, with varying diameter and on the colour scale.
- I want to be able to edit the axis scale labels so that full descriptions are on the y-axis, and numeric references on the x-axis
I have gotten relatively close, but have not managed precise enough replication. I describe my closest attempts below with reproducible code. The corrplot
package has gotten me closest.
ANSWER
Answered 2022-Apr-16 at 10:49Out-of-the-box options are quick and nice. However, when it comes to customizing then IMHO it may be worthwhile to build up the plot from scratch using ggplot2
. As a first step this involves some data wrangling to get you correlation matrix into the right shape. Also in this step I convert the categories to factor
s and a numeric id. Based on the ids I split the data in the upper and lower diagonal values which could then be plotted separately using a geom_point
and a geom_text
. Besides that it's important to add the drop=FALSE
to the x and y scale to keep all factor levels and the right order. Also I use some functions to get the desired axis labels:
EDIT: Following the suggestion by @AllanCameron I added a coord_equal
as the "final" touch to get a nice square matrix like look. And Thanks to @RichtieSacramento the code now maps the absolute value on the size
aes.
QUESTION
I am writing a project in Tidymodels
. I have created a train
and test
set, set out a recipe
and a model
. When I call workflow()
, add the recipe
and model
, then call fit(data = df_train
, I am getting the following error.
ANSWER
Answered 2022-Mar-20 at 09:32I am responding to my own question.
One thing I have realised is that the problem is in the recipe
step. When I replace step_str2factor
with step_dummy
, then everything works fine.
I still do not know why this is the case. Maybe I will need to study Tidymodels more keenly!!
QUESTION
I have done the following visualization of a correlation matrix:
...ANSWER
Answered 2022-Jan-15 at 16:50You could define your own colorRampPalette
:
QUESTION
I have a data.frame database with 14 columns. I split these columns into two groups: [,1:6] and [,7:14]
.
ANSWER
Answered 2021-Dec-21 at 21:23I would use the well established Hmisc::rcorr
for the calculations. In corrplot::corrplot
, subset both the corr=
and the p.mat=
with [1:6, 7:14]
.
QUESTION
I have performed Spearman correlation for my data. Then I tried to cluster and plot my data using the "ward.D2" method for corrplot()and pheatmap(). However, the order of the variables is different between the two plots.
Could someone help me clarify this point, thus correcting my code and creating the two plots with the same order of clustered variables? Thank you so much.
...ANSWER
Answered 2021-Dec-20 at 21:46You can create a corrplot
with the same order given by pheatmap
as follows:
QUESTION
How can I save an R plot that is only displayed in the "plots-pane" and not saved in the workspace?
Here simplified example on how I create my plot:
...ANSWER
Answered 2021-Oct-22 at 09:47You are trying to save a loop. Try this:
QUESTION
I want to add a colour to each "row" of the corrplot but I haven't found any solution yet.
My code looks like this:
...ANSWER
Answered 2021-Oct-19 at 10:33It doesn't look like corrplot
offers the functionality to colour by row. The alternative would be to build the chart in ggplot
. More work, for sure, but it allows the flexibility to colour rows.
As a start of a solution:
QUESTION
does anybody have an idea why ggcorrplot2 shows different significance asterisks than ggcorrplot? Very confusing to me.
...ANSWER
Answered 2021-Oct-13 at 07:40data(mtcars)
cor.matrix <- corr.test(mtcars,method = "spearman", adjust = "BH", alpha = 0.05, ci = F)
corr <- cor.matrix[["r"]]
p.mat <- cor.matrix[["p"]]
p.mat[lower.tri(p.mat)] <- t(p.mat)[lower.tri(p.mat)] #to get only the adjusted p.Values symmetrically over the plot
p.mat[lower.tri(p.mat, diag = T)] <- 1 #to set the lower triangle to 1 (this way the asterisks wont be displayed on this part of the graph)
corrplot.mixed(corr, order= "original",mar=c(0,0,2,0), tl.col = 'black', p.mat = p.mat, insig = "label_sig", sig.level = c(.001, .01, .05), pch.cex=1.5, tl.cex = .8, number.font=2, number.cex=0.8)
QUESTION
I'm trying to visualize the results of chisq.test with the corrplot package and I'm getting an error I don't understand. Hope someone can enlighten me.
...ANSWER
Answered 2021-Oct-06 at 23:02I don't think "M" is a correlation matrix, so if you set is.corr = FALSE
you get output (although I'm not sure whether the output is correct or not; p.mat is only 4 values, but you have 14 values in M so you get a bunch of warnings):
QUESTION
I have look into this problem and some people suggest that changing column name might work. But I can't seems to figure out which column is causing the issue.
my code
...ANSWER
Answered 2021-Sep-29 at 10:30First of all in your dput(data.new)
the target variable is called oly_success
and in the formula, you use oly.success
, second you remove the target variable with:
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Install corrplot
You can use corrplot like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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