RBP | Recurrent Back Propagation | Machine Learning library
kandi X-RAY | RBP Summary
kandi X-RAY | RBP Summary
This is the PyTorch implementation of Recurrent Back Propagation as described in the following ICML 2018 paper:.
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Top functions reviewed by kandi - BETA
- Train the model
- Snapshot a model
- Loads a model from file
- Forward computation
- Calculates RBP
- Calculates the gradient of the gradient Ax = b
- Detach param from params_src
- Concatenate a tensor to a tensor
- Train the MNIST model
- Corrupt the image
- Parse command line arguments
- Configure logging
- Get a logger
- Get a configuration file
- Convert edict to dict
- Create folder if necessary
RBP Key Features
RBP Examples and Code Snippets
Community Discussions
Trending Discussions on RBP
QUESTION
I wrote a demo with some inline assembly (showing how to shift an array of memory right one bit) and it compiles and functions fine in GCC. However, the with Clang, I'm not sure if it's generating bad code or what but it's unhappy that I'm using memory despite the "rm" constraint.
I've tried many compilers and versions via Godbolt and while it works on all x86/x86_64 versions of GCC, it fails with all versions of Clang. I'm unsure if the problem is my code or if I found a compiler bug.
Code:
...ANSWER
Answered 2021-Jun-16 at 00:48I'm unsure if the problem is my code or if I found a compiler bug.
The problem is your code. In GNU assembler, parentheses are used to dereference like unary *
is in C, and you can only dereference a register, not memory. As such, writing 12(%0)
in the assembly when %0
might be memory is wrong. It only happens to work in GCC because GCC chooses to use a register for "rm"
there, while Clang chooses to use memory. You should use "r" (bytes)
instead.
Also, you need to tell the compiler that your assembly is going to modify the array, either with a memory
clobber or by adding *(unsigned char (*)[16])bytes
as an output. Right now, it's allowed to optimize your printf
to just hardcode what the values were at the beginning of the program.
Fixed code:
QUESTION
I ran into less than ideal inlining behavior of the .NET JIT compiler. The following code is stripped of its context, but it demonstrates the problem:
...ANSWER
Answered 2021-Jun-15 at 19:35The functions Hash_Inline
and Hash_FunctionCall
are not equivalent:
- The first statement in
Hash_Inline
rotates by 1, but inHash_FunctionCall
it rotates bycurIndex
. - For
RotateLeft
you may have probably meant:
QUESTION
Taking the following C code
...ANSWER
Answered 2021-Jun-14 at 11:23If you read the assembler code from the top you will see that it reaches .L3
, plus it also jumps to it with jne .L3
, which is your for
loop in C.
QUESTION
Compiling C/C++ code with the -g
flag results in debug information in the produced binary file. In particular, there is a mapping of source code to binary code:
ANSWER
Answered 2021-Jun-10 at 15:38llvm-objdump -S
should work in the same way that it does for native object files.
If you are looking for nice display of code that lacks debug info you might also want to take a look at wasm-decompile
which is part of the wabt project. Its able to do a much better job of making something readable than normal/native decompilers.
QUESTION
Here is the function definition
...ANSWER
Answered 2021-Jun-06 at 09:04The language doesn't define where arguments to functions are stored. Different ABIs, for different platforms, define this.
Typically, a function argument, before any optimization, is stored on the stack. A reference is no different in this respect. What's actually stored would be a pointer to the refered-to object. Think of it this way:
QUESTION
I am novice in assembly (NASM). I know that RBP points to any parameters and local variable in function. It’s implemented by simple offset. If we wanna get first variable we rbp-4
, if we wanna get fist parameter we add to rbp 4. But how can we do this if any function can have any number of local variable or parameters? If we want we can have 100 variable in one function and how does we can points to any variable by simple constant offset?
Thank you. Sorry for my English. I am not native speaker.
...ANSWER
Answered 2021-Jun-06 at 06:36Addressing of function parameters and local variables depends on the chosen calling convention. Your to get first parameter we add to rbp 4 is certainly wrong, because in 64bit mode (implied by using RBP
or RSP
for addressing) can items be pushed on stack with 64bit granularity only. Perhaps you had 32bit StandardCall convention on your mind, where typical prologue of a function looks like this:
QUESTION
I try to put Apache Arrow vector in Ignite, this is working fine when I turn off native persistence, but after I turn on native persistence, JVM is crashed every time. I create IntVector first then put it in Ignite:
...ANSWER
Answered 2021-Jun-01 at 11:11Apache Arrow utilizes a pretty similar idea of Java off-heap storage as Apache Ignite does. For Apache Arrow it means that objects like IntVector
don't actually store data in their on-heap layout. They just store a reference to a buffer containing an off-heap address
of a physical representation. Technically it's a long
offset pointing to a chunk of memory within JVM address space.
When you restart your JVM, address space changes. But in your Apache Ignite native persistence there's a record holding an old pointer. It leads to a SIGSEGV
because it's not in the JVM address anymore (in fact it doesn't even exist after a restart).
You could use Apache Arrow serialization machinery to store data permanently in Apache Ignite or even somewhere else. But in fact after that you're going to lose Apache Arrow preciousness as a fast in-memory columnar store. It was initially designed to share off-heap data across multiple data-processing solutions.
Therefore I believe that technically it could be possible to leverage Apache Ignite binary storage format. In that case a custom BinarySerializer should be implemented. After that it would be possible to use it with the Apache Arrow vector classes.
QUESTION
I am starting to learn x86_64 assembly, one thing I noticed is the usage of registers such as rdi, rbp, rax, rbx. Do they exist in the CPU or is this some sort of abstract mechanism used by assembler?
For example if I do
...ANSWER
Answered 2021-May-30 at 01:59CPU hardware doesn't find registers by name, it's up to the assembler to translate names like rax
to 3 or 4-bit register numbers in machine code. (And the operand-size implied by the register name is also encoded via the opcode and (lack of) prefixes).
e.g. add ecx, edx
assembles to
01 d1
. Opcode 01
is add r/m32, r
. The 2nd byte, the ModRM 0xd1 = 0b0b11010001
, encodes the operands: the high 2 bits (11) are the addressing mode, plain register, not memory (for the dest in this case, because it's 01 add r/m32, r
not 03 add r32, r/m32
).
The middle 3 bits are the /r
field, and 010
= 2 is the register number for edx.
The low 3 bits are the r/m
field, and 001
is the register number of ECX.
(The numbering goes EAX, ECX, EDX, EBX, ..., probably because 8086 was designed for asm source compatibility with 8080 - i.e. "porting" on a per-instruction basis simple enough for a machine to do automatically.)
This is what the CPU is actually decoding, and what it uses to "address" its internal registers. A simple in-order CPU without register renaming could literally use these numbers directly as addresses in an SRAM that implemented the register file. (Especially if it was a RISC like MIPS or ARM. x86 is complicated because you can use the same register numbers with different widths, and you have partial registers like AH and AL mapping onto halves of AX. But still, it's just a matter of mapping register numbers to locations in SRAM, if you didn't do register renaming.)
For x86-64, register numbers are always 4-bit, but sometimes the leading zero is implicit, e.g. in an instruction without a REX prefix like mov eax, 60
. The register number is in the low 3 bits of the opcode for that special encoding.
Physically, modern CPUs use a physical register file and a register-renaming table (RAT) to implement the architectural registers. So they can keep track of the value of RAX at multiple points in time. e.g. mov eax, 60
/ push rax
/ mov eax, 12345
/ push rax
can run both mov
instructions in parallel, writing to separate physical registers. But still sorting out which one each push
should read from.
if thats the case, i am wondering why there are only 16 registers in x86_64 architecture ...
A new ISA being designed for the high-performance use-cases where x86 competes would very likely have 32 integer registers. But shoehorning that into x86 machine code (like AVX-512 did for vector regs), wouldn't be worth the code-size cost.
x86-64 evolved out of 16-bit 8086, designed in 1979. Many of the design choices made then are not what you'd make if starting fresh now, with modern transistor budgets. (And not aiming for asm source-level compatibility with 8-bit 8080).
More architectural registers costs more bits in the machine code for each operand. More physical registers just means more out-of-order exec capability to handle more register renaming. (The physical register numbering is an internal detail.) This article measures practical out-of-order window size for hiding cache miss latency and compares it to known ROB and PRF sizes - in some cases the CPU runs out of physical registers to rename onto, before it fills the ROB, for that chosen mix of filler instructions.
, doesn't more registers means more performance ?
More architectural registers does generally help performance, but there are diminishing returns. 16 avoids a lot of store/reload work vs. 8, but increasing to 32 only saves a bit more store/reload work; 16 is often enough for compilers to keep everything they want in registers.
The fact that AMD managed to extend it to 16 registers (up from 8) is already a significant improvement. Yes, 32 integer regs would be somewhat better sometimes, but couldn't be done without redesigning the machine-code format, or with much longer prefixes (like AVX-512's 4-byte EVEX prefix, which allow 32 SIMD registers, x/y/zmm0..31 for AVX-512 instructions.)
See also:
https://www.realworldtech.com/sandy-bridge/5/ - Intel Sandybridge was when Intel started using a PRF (Physical Register File) instead of keeping temporary values in the ROB (Reorder Buffer).
Related Q&As:
QUESTION
I was just messing around with Compiler Explorer a bit... I was asking myself why there is no lenth() function in C++ to determine the size of an array at compile time, because in my opinion it should be easy to write. But apparently it's not that easy. My idea was something like this:
...ANSWER
Answered 2021-May-29 at 12:52As already pointed out in the comments, enabling optimisations does remove the call. Alternatively, you could use C++ attributes; with GCC and clang inserting [[gnu::always_inline]]
will always omit the call:
QUESTION
So as my question states, how do you get the ASCII key code from keyboard input as an integer value, then I want to save that value in a dataword inside of .data so I can then place the dataword into a different function.
...ANSWER
Answered 2021-May-26 at 15:59You should be able to store a single byte by calling x64's SYS_READ system call. Here is some modified code based on your example.
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