converge | The Converge programming language
kandi X-RAY | converge Summary
kandi X-RAY | converge Summary
See the docs/ directory for documentation, including installation instructions.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Parse OOOO OOOOOOOOOOO
- Get the term off and length
- Convert an int tree node into a TreeNode
- Convert a tree node to a list of tokens
- Imports the VM
- Bootstrap a parser class
- Create a simple exception class
- Bootstrap array class
- Get an array from the vm
- Return list of index indexes
- Add executable bits
- Decorator to create Con object
- Set the value of the array
- Return an iterator over the array
- Pretty print the tree
- Translate slice index object
- Get the slice of the array
- Append an array to the vm
- Get a match object
- Add lib
- Checks if the mod file is newer than mtime
- Extend this array from a string
- Parse an XML document
- Extend this array
- Start an element
- Insert characters
converge Key Features
converge Examples and Code Snippets
Lines of Code : 11
License : No License
Copypublic static OptionalInt gcd(int[] numbers) {
return Arrays.stream(numbers)
.reduce((a, b) -> gcd(a, b));
}
private static int gcd(int a, int b) {
if (b == 0) {
return a;
}
return gcd(b, a % b);
}
public static void main(String[] args) {
System.out.println(gcdOfStrings("bcdbcdbcd", "bcdbcd"));
System.out.println(gcdOfStrings("bcdbcdbcdbcd", "bcdbcd"));
System.out.println(gcdOfStrings("ABCABC", "ABC"));
System.ou public static int gcd(int a, int b) {
if (a < 0 || b < 0) {
throw new ArithmeticException();
}
if (a == 0 || b == 0) {
return Math.abs(a - b);
}
if (a % b == 0) {
re private static GcdSolutionWrapper gcd(final int a, final int b, final GcdSolutionWrapper previous) {
if (b == 0) {
return new GcdSolutionWrapper(a, new Solution(1, 0));
}
// stub wrapper becomes the `previous` of t Community Discussions
Trending Discussions on converge
QUESTION
I am trying to extract random effect correlation parameters from an lmer output.
This is my model:
...ANSWER
Answered 2021-Jun-15 at 12:38You want to use lme4::VarCorr to extract those values. Here is an example.
QUESTION
I am trying to turn my edge labels into node labels, in order to predict unlabeled nodes. Currently the dataset has edge_labels but I would need to have each node (ID) getting exactly one node_label:
The code I am using is the following:
...ANSWER
Answered 2021-Jun-11 at 20:38You have nodes that are only appearing in the Target column, so you need to incorporate that column when finding all unique nodes. I did this by concatenating the two columns (along with Label), grouping by node ID while summing the Label values, and then replacing summed labels with 1 if the sum was > 0:
QUESTION
I am attempting to write a code for Newton's Method for nonlinear systems in Python. My g function is a 5x1 matrix and the jacobian (derivative matrix) of this is a 5x5 matrix. The vector for the initial y values (y0) is also a 5x1. i keep on getting the error
...ANSWER
Answered 2021-Jun-10 at 14:39The dimensions of y0 and g seems to be wrong. Reduce them by one dimension:
QUESTION
I am trying to use Torch for Label Propagation. I have a dataframe that looks like
...ANSWER
Answered 2021-Jun-10 at 10:00For other readers here, it seems like this is the implementation being asked about in this question.
The method you are using to try to predict labels works with labels for nodes, not edges. To visualize this, I plotted your example data and colored the plot by your Weight and Label columns (code to produce plot appended below) where Weight is the line thickness of the edge and Label is the color:
In order to use this method, you will need to produce data that looks like this, where each node (denoted by ID) gets exactly one node_label:
QUESTION
Suppose you have a neural network with 2 layers A and B. A gets the network input. A and B are consecutive (A's output is fed into B as input). Both A and B output predictions (prediction1 and prediction2) Picture of the described architecture You calculate a loss (loss1) directly after the first layer (A) with a target (target1). You also calculate a loss after the second layer (loss2) with its own target (target2).
Does it make sense to use the sum of loss1 and loss2 as the error function and back propagate this loss through the entire network? If so, why is it "allowed" to back propagate loss1 through B even though it has nothing to do with it?
This question is related to this question https://datascience.stackexchange.com/questions/37022/intuition-importance-of-intermediate-supervision-in-deep-learning but it does not answer my question sufficiently. In my case, A and B are unrelated modules. In the aforementioned question, A and B would be identical. The targets would be the same, too.
(Additional information) The reason why I'm asking is that I'm trying to understand LCNN (https://github.com/zhou13/lcnn) from this paper. LCNN is made up of an Hourglass backbone, which then gets fed into MultiTask Learner (creates loss1), which in turn gets fed into a LineVectorizer Module (loss2). Both loss1 and loss2 are then summed up here and then back propagated through the entire network here.
Even though I've visited several deep learning lectures, I didn't know this was "allowed" or makes sense to do. I would have expected to use two loss.backward(), one for each loss. Or is the pytorch computational graph doing something magical here? LCNN converges and outperforms other neural networks which try to solve the same task.
ANSWER
Answered 2021-Jun-09 at 10:56From the question, I believe you have understood most of it so I'm not going to details about why this multi-loss architecture can be useful. I think the main part that has made you confused is why does "loss1" back-propagate through "B"? and the answer is: It doesn't. The fact is that loss1 is calculated using this formula:
QUESTION
I tried to apply zeller's convergence simplified method to get day name from a user input date.
simplified algorithm from
...ANSWER
Answered 2021-Jun-08 at 19:21You need to fetch the data from the year variable twice, year @ 100 .... I think after that ?adaptday will work. There is forth word within \ n lo hi -- flag ; flag is True if lo <= n < hi for checking numbers within ranges,
In Forth it's unusual to use so many variables. The values are normally stored on the stack. j as a variable could override the j used as the outer do loop counter. I've seen k used for the next outer loop too!!
I'd implement it something like this. I can then run the words in the console with stack input to see what is happening to help debug.
QUESTION
I have a data having 3 features and 1 target variable. I am trying to use gradient descent and later minimize the RMSE
While trying to run the code, I am getting nan as the cost/error term Tried a lot of methods but can't figure it out.
Can anyone please tell me where I am going wrong with the calculation.
Here's the code:
m = len(y)
ANSWER
Answered 2021-Jun-07 at 19:01The only reasonable solution which we came up was since the cost was high.. it was not possible to use this approach for this solution. We tried using a different approach like simple linear regression and it worked.
QUESTION
I am an engineering student and I have to turn in projects that run code for simulations. The calculations are all carried out in Python, but the derivations/ setup is done on paper and included in the report. I sometimes find myself copying and pasting code for repeat graphs or numerical simulations, so I want to write functions for these (trying to be better about DRY).
When writing functions to do these things, I'm worried that I'm "hiding" to much of the code behind the functions. For example, this function would plot two simulations differing only by tolerance level. This would be used to check for convergence in a numerical simulation of an ode.
...ANSWER
Answered 2021-Jun-07 at 16:13In my experience the dry principle is more important when writing libraries and code that you want to reuse. However my experience is that if you want to make a report then sometimes making things to dry can actually make things harder to maintain. I.e. sometimes you want to be able to change an individual graph/plot/piece of data in one place without it affecting the rest of the report. It takes a bit of practice and experience to find out what works best for you. In this particular use case be less focussed on following the DRY rule then when writing a library or an application.
Additionally if I had to make such a report and the situation would allow it. I would make in in a Jupyter notebook. Here you can nicely mix code with text and graphical output.
QUESTION
At the below link, I asked, why I am getting error using neuralnet package:
[https://stackoverflow.com/questions/67854153/getting-requires-numeric-complex-matrix-vector-arguments-error-using-neuralnet/67854278#67854278][1]
@akrun explained and solved the problem. The problem was default value of threshold. It's default value is 0.01. If we let that value to be 0.05, the algorithm converges.
But, I want to use default threshold value in general. Bu when I get error, I want to use 0.05 as threshold value instead of the default value.
For that aim I revised the code as below:
...ANSWER
Answered 2021-Jun-06 at 13:02Note that you actually get a warning (and not error) while applying neuralnet function so you can try this -
QUESTION
I need to find the value of a function given its unknown by interpolation. The problem is that the one I created is way too inefficient.
Firstly, I read a data file that contains both y=g(T) and T, but in discrete form. And I store their values in a std::vector.
After this, I convert T (std::vector Tgdat) to x (std::vector xgdat). This will be the x-axis that will accompany the y-axis, (std::vector gdat).
Then, I create a function to interpolate my vector std::vector gdat, so that, given some x (which its value is in between two elements of the vector std::vector xgdat), the program can spit some value for g(x). This function receives the vectors by reference, not because I want to modify them (that's why I also pass them as const), but so that the computer doesn't have to create copies of it.
ANSWER
Answered 2021-May-17 at 22:40Some tips on the code:
Declare variables where needed, not all at the top.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install converge
You can use converge like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
