quade | The friendly QA tool for Django
kandi X-RAY | quade Summary
kandi X-RAY | quade Summary
The friendly QA tool for Django
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Top functions reviewed by kandi - BETA
- Execute test
- Context manager to connect to QObjectRecord
- Execute the scenario
- Set the given exception
- Register a function
- Register a new function
- Get the version string
quade Key Features
quade Examples and Code Snippets
Community Discussions
Trending Discussions on quade
QUESTION
Here is a snippet from this answer to a related question:
...ANSWER
Answered 2020-Sep-19 at 17:28I will give an algorithm run with the example, and let you write the general form. Let max=5 and element=42nd
It's a recusion, that goes one layer down each recursive step. Each step you are in a high level array that 42 belongs to.
You start by the top layer array. How much elements it can contain 125=5x5x5 (to generalize max^number_of_sub_layers). 42 is smaller than 125 so it is contained in this array. You have the first 0 of the result [0]
Now to know in which sub layer the next step will look in, you compute 42 // 25 (25=5x5 being the number of elements that each sub array can contain). You get 42 // 25 = 1, so 42 is in the second array (of index 1), you have now [0, 1].
Now you do the same thing with this second array. But with the number 42 % 25 = 17, because 25 elements are contained in the first array. You compute 17 // 5 (5 being the number of elements that each sub array contain). You get 17 // 5 = 3, so 42 will be in the forth sub array of this array (of index 3). So now you have [0, 1, 3]
And then once you are at the array of final layer, the element is in 17 % 5 = 2nd position.
Update
As I am not very familiar with javascript, here is how I would do it in python. The code can be more concise but it does the job.
QUESTION
I'm trying to generate a linear and quadratic regression of some data I have using vba. Simple enough right? The problem is when I use the linest function, I'm not getting the results I was hoping for (a 2d array containing the x values in the first column and the y values in the second column), and instead I'm receiving "Error 2015".
I know that linest is supposed to return the coefficients of a linear/quadratic regression, so I tried just creating a y=mx+b in my code to generate the arrays I want. I have yet to find success doing this.
Avg & P2 are the variables for the input data.
...ANSWER
Answered 2019-Oct-21 at 02:13Regarding the code you have in your question: When dealing with regressions, you have to be aware that by default VBA arrays are starting at 0 and you need to specify when you (re)dim them that you want them to start at 1 which is the convention when doing regressions.
In you code, when you were running the line below, you had an empty value for nAvg(0) and nP2(0) which gave you the Error 2015 (#Value cell error).
QUESTION
I have a very simple program that maps a dummy red texture to a quad.
Here is the texture definition in C++:
...ANSWER
Answered 2018-Sep-27 at 18:35GL_UNPACK_ALIGNMENT
specifies the alignment requirements for the start of each pixel row in memory. By default GL_UNPACK_ALIGNMENT
is set to 4.
This means each row of the texture is supposed to have a length of 4*N bytes.
You specify a 2*2 texture with the data: 255, 0, 0, 255, 0, 0, 255, 0, 0, 255, 0, 0
With GL_UNPACK_ALIGNMENT
set to 4 this is interpreted as
QUESTION
I am looking to recreate various analyses in R that can compute several types of Non-Parametric ANCOVA.
Let's use the mtcars
data from the datasets
package in R for example purposes. Let's say I wanted to predict MPG
from Transmission
while controlling for Cylinders
. I would conduct a normal ANCOVA in R with the following code:
ANSWER
Answered 2018-Jul-18 at 19:04After a day of reading about the procedures, I have about 2/3 of an answer. According to Chapter 5 of Bonate's (2000) text, Quade's Non-Parametric ANCOVA is calculated as follows:
QUESTION
I'm writing a program in Assembly that has has 2 arrays declared at the beginning and 3 functions, which are:
...ANSWER
Answered 2018-Apr-19 at 02:23I was losing the array in printQArray
It was just one line!!
QUESTION
I am working on Panama dataset using Neo4J graph database 1.1.5 web version. I identified Ion Sturza, former Prime Minister of Moldova on the database and want to make a map of his related network. I used following code to query using Cypher (creating a variable 'IonSturza'):
...ANSWER
Answered 2017-Apr-11 at 14:56The cartesian product warning will appear whenever you're matching on two or more disconnected patterns. In this case, however, it's fine, because you're looking up both of them by what is likely a unique name, s your result should be one node each.
If each separate part of that pattern returned multiple nodes, then you would have (rows of a
) x (rows of b
), a cartesian product between the two result sets.
So in this particular case, don't mind the warning.
As for why you're not seeing changes, note that you're reusing variables for different parts of the graph: you're using variable b
for both the uppercase version of the officer, and for the :Entity in your WHERE. There is no node that matches to both.
Instead, use different variables for each, and include the :Entity in your match. Also, once you match to nodes and bind them to variables, you can reuse the variable names later in your query without having to repeat its labels or properties.
Try this:
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You can use quade like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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