sumy | Module for automatic summarization of text documents and HTML pages | Natural Language Processing library
kandi X-RAY | sumy Summary
kandi X-RAY | sumy Summary
Simple library and command line utility for extracting summary from HTML pages or plain texts. The package also contains simple evaluation framework for text summaries. Implemented summarization methods are described in the documentation. I also maintain a list of alternative implementations of the summarizers in various programming languages.
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Top functions reviewed by kandi - BETA
- Stem a word
- Removes punctuation
- Helper function for converting a word into a string
- Remove case characters from a word
- Handles command line arguments
- Fetch a given URL
- Get stop words
- Build a new summarizer
- Return the sentence tokenizer for the given language
- Convert an object to bytes
- Convert an object to bytes
- Build a summary summarizer
- Evaluate the cosine similarity between two documents
- Build a TextRank summarizer
- Compute the unit overlap between two documents
- Build lsa
- Build a Luhn summarizer
- Build a lex rank summarizer
- Build a basic summarizer
- Rate each sentence in a document
- Calculates the rating of a chunk
- The list of words in the paragraph
- List of significant words
- Compare two sentences
- Calculate ROUGE - 1
- Create a document document from the document
- Return a paragraph representation of the article
sumy Key Features
sumy Examples and Code Snippets
export PATH=/usr/local/cuda/bin:$PATH
THEANO_FLAGS=mode=FAST_RUN,device=gpu,floatX=float32 python lstm_text_generation.py
python summarize.py --url https://en.wikipedia.org/wiki/George_W._Bush --num_sentences 10
THEANO_FLAGS=mode=FAST_RUN,device=gpu,floatX=float32 python generate.py --name patriotAct --url http://www.genekogan.com/txt/patriotAct.txt --nb_epochs 1 --max_epochs 50 --rnn_size 512 --num_layers 2
def getPolygon(quad, scale=1):
[sumX, sumY] = [0, 0]
for point in quad:
sumX += point[0]
sumY += point[1]
avgX = sumX/4
avgY = sumY/4
# Scale the rectange using Quad.morph(): https://pymupdf.readthedocs
s = df.groupby('id').apply(lambda x: pd.Series([x.loc[x['e'], 'year'].min(),x['val'].sum()],index=['myear','sumy']))
Out[321]:
myear sumy
id
1 2002 600.0
2 2014 400.0
3 NaN 300.0
if open:
knotVector = [x for x in range(len(controlPoints) - degree + 1)]
for _ in range(degree):
knotVector.insert(0, knotVector[0])
knotVector.insert(-1, knotVector[-1])
[0, 0, 0, 1, 2
import matplotlib.pyplot as plt
import random
import sys
x = 1
y = 1
sumx = 0
sumy = 0
max_x = 0
max_y = 0
x_values = []
y_values = []
for i in range(5000):
rand = random.uniform(0,1)
if rand <= 0.5:
x = ((-0.4 * x) -
norm = mpl.colors.Normalize(np.min(ytrain), np.maxn(ytrain))
plt.scatter(x, y, c=ytrain, norm=norm, cmap='rainbow')
n = 5
list_= [0] * n # [0, 0, 0, 0, 0]
string.join(iterable)
sumX = 2
sumY = 5
print ('*'.join([str(sumX)] * sumY))
2*2*2*2*2
array1[i][0]= ...
array1[i][1]= ... array[i][0] ...
x = array1[i][0]
array1[i][0]=((array[i][0]-centerArray[0])*math.cos(angle)-(array[i][1]-centerArray[1])*math.sin(angle))+centerArray[0] #rotate x cordiate around
Community Discussions
Trending Discussions on sumy
QUESTION
I’m new to regex and I can’t find a way to do what I want. Let me explain. I have some piece of code that looks like this in Notepad++:
...ANSWER
Answered 2022-Feb-19 at 15:42You can use
Find What: (\[expr\s+)((?:(\[(?:[^][]++|(?3))*])|[^][{}])*)(])
Replace With: $1{$2}$4
See the regex demo. Details:
(\[expr\s+)
- Group 1:((?:(\[(?:[^][]++|(?3))*])|[^][{}])*)
- Group 2: zero or more occurrences of(\[(?:[^][]++|(?3))*])
- Group 3:[
, then zero or more sequences of any one or more chars other than[
and]
or Group 3 pattern recursed, and then a]
char|
- or[^][{}]
- a char other than[
,]
,{
and}
(])
- Group 4: a]
char.
Demo screenshot:
QUESTION
im working on a macro to average all GPS coordinates that fall within a specified distance. I cant think of a way to loop through the list of coordinates to check if any of the other coordinates in the list are within 0.05 then average the coordinate.
I have played around using if statements and the distance between two coordinates formula
...ANSWER
Answered 2022-Jan-10 at 15:57I'm curious where you go with this.
I made up some similar appearing data and built a matrix on a separate worksheet. Maybe this gives you an idea where to go next, as I am not sure.
QUESTION
I'm trying to create a function using some dplyr
functions and I think I'm running into issues with NSE. The below functions works when I use the actual name of the variables in the argument but when I try to call to the elements of the vectors that I made, it doesn't.
I think I need to something about the quoting/unquoting of the arguments but I'm kind of stumped:
Works:
...ANSWER
Answered 2021-Dec-08 at 14:26You need to distinguish if you have variable name as symbol (not sure if this is good term) or as string. NSE refers to symbols, i.e. you do not write quotes. In your first example you use symbols, in second - strings. And for string another syntax is necessary. Instead of {{variable}}
you need to use .data[[variable]]
:
QUESTION
sorry for the long code, I know you are not here to write code but answer questions, but could someone please point me in the right direction with this error before I pull out the little bit of hair I have left:
The error I'm getting is : Conversion failed, reason: line 19: line 69: Function hma already defined.
Thank you in advance
...ANSWER
Answered 2021-Nov-01 at 21:16hma
is a built-in function. Just remove line 69 from your original code and try to convert again.
Line 69:
QUESTION
To list all of the packages in my active environment in a format that resembles pip freeze
:
ANSWER
Answered 2021-Mar-28 at 09:05conda
only keeps track of the packages it installedpip freeze
will give you the packages that were either installed using pip package manager or they used setuptools in their setup.py soconda
build generated the egg information.
Downgrading the pip may fix this issue, you can check this out: conda issues
QUESTION
This is C, can't use anything but C.
So I was given the equation here:
I am trying to calculate the 'b' in the formulae. The formula is Regression slope done via Lease Squares Formulae
My code takes in a list of numbers called 'arr[]' and the amount of elements in that list being 's'. I go through the calculations and I get the wrong number. If anyone can help me out that would be awesome and if I'm not allowed to ask this here, please point me in the direction to where I can ask this.
calcMean is a function that calculates the mean. An Example of what I need: With a list of numbers being: 1 1 1 2 2 3 3 3 4 5 5 6 7 I need to get a: 0.429 My code currently gives me an answer that is quite off.
My code:
...ANSWER
Answered 2021-Mar-08 at 10:22Since, you have not given the implementation of the calcMean(arr, s)
function, I am assuming that you are able to implement it without any logical errors.
The problem I sense here is that the summation in the least squares formula is from i = 1
till i = n
. But you have looped from i = 0
till i=n-1
.
Here you just need to run the loop from i = 1
till i = s
and access arr
elements through as arr[i-1]
.
Try this code with the change implemented and let me know if the error still persists.
QUESTION
My azure function is using python module pywavelets
which requires dependency to numpy
. Here is my requirements.txt
ANSWER
Answered 2021-Feb-01 at 03:35I test in my side with same modules as yours in my requirements.txt
and run the function with Ctrl + F5. It shows same error message as you mentioned.
It seems there are some conflicts of the two modules(in the versions which you specified in your requirements.txt
). To solve this problem, just remove the version of the two modules in requirements.txt
. Below is my requirements.txt
:
If we do not specify the version, it will install the latest version automatically. In my function app, it intalls numpy 1.20.0
and PyWavelets 1.1.1
, and the function runs success when I use Ctrl + F5.
QUESTION
I'am connecting my flask-app to a MySQL-Database like this:
...ANSWER
Answered 2020-Dec-25 at 00:17Decimal is the python way of representing fixed decimal values. The SQL is returning a decimal probably because the sumy
is decimal. Its likely all implementation will handle this the same way.
Leaving the python application to handle it as a Decimal
is probably the best way to maintain the database being responsible for retrieval and the application for presentation.
QUESTION
So I was working with implementing B-spline curves in python (and I am aware there are existing libraries, but I wanted to do it myself) and it worked well for non-open uniform B-spline curves as shown here:
The graph on the right showing the Basis Function (Cox de Boor's recursion formula) calculations correspond really well with what is shown in this video with the only difference being the number of control points. (https://www.youtube.com/watch?v=qhQrRCJ-mVg&t=2136):
As soon as I try to make this an open uniform B-Spline curve. I expect a graph like this (https://www.youtube.com/watch?v=qhQrRCJ-mVg&t=2501):
But instead, I get a ZeroDivisionError:
...ANSWER
Answered 2020-Jul-05 at 08:53There are two errors in your code:
The knot vector for uniform closed B-Splines is supposed to count up to the number of segments, not the number of control points. The number of segments is the number of control points minus the degree. I.e., if you have three points for a degree-2 spline (i.e., a simple Bezier curve), you get a single segment. For each additional point, you get one more segment. Hence, the knot vector has to be:
QUESTION
I am using a simple dataset to calculate the linear regression between x and y values. I wrote the code both in python and c++. However the output differs a lot due to rounding(I believe) during the operations. The minimum runnable products:
cpp code:
...ANSWER
Answered 2020-May-06 at 08:47You have an integer overflow issue in the code: 60'300 * 60'300 = 3'636'090'000 while usually an int
are 4-bytes long and can hold only values in range [-2^31, 2^31-1] = [-2'147'483'648, 2'147'483'647].
Python's integer does not overflow.
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