playground | Place where I play with code when adults | Frontend Framework library

by miso-belica Python Version: Current License: No License

X-Ray Key Features Code Snippets(1)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | playground Summary

playground is a Python library typically used in User Interface, Frontend Framework, React applications. playground has no bugs and it has low support. However playground has 1 vulnerabilities and it build file is not available. You can download it from GitHub.

Place where I play with code when adults sleep :)

Support

Quality

Security

License

Reuse

Support

playground has a low active ecosystem.

It has 8 star(s) with 6 fork(s). There are 3 watchers for this library.

It had no major release in the last 6 months.

playground has no issues reported. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of playground is current.

Quality

playground has no bugs reported.

Security

playground has 1 vulnerability issues reported (0 critical, 0 high, 1 medium, 0 low).

License

playground does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

playground releases are not available. You will need to build from source code and install.

playground has no build file. You will be need to create the build yourself to build the component from source.

Top functions reviewed by kandi - BETA

kandi has reviewed playground and discovered the below as its top functions. This is intended to give you an instant insight into playground implemented functionality, and help decide if they suit your requirements.

Convert a JKS file to PEM format
Print a PEM encoded PEM encoding
Merge two iterables
Generate a random string
Recursively delete empty folders
Returns True if files are ignored
Copy data from source to destination
Convert seconds to humanize
Copy schema to destination
Convert a number of seconds into humanized time
Test for join text
Copy data from src_postgres to destination
Copy sequence state from source to destination database
Execute a query against the database
Compare two texts
Print timing information
Test for the least squares
Generate a random airline group
Test for regexp
Returns True if there is a next item in the iterable
Test if the response is a chatbot response
Create a birthday event
Set public and protected attributes
Return True if the cycle is odd
Test if bytes to be str
True if the matrix is odd
True if the cycle is an integer

Get all kandi verified functions for this library.

playground Key Features

No Key Features are available at this moment for playground.

playground Examples and Code Snippets

The playground code .

javascript

Lines of Code : 4

License : Permissive (MIT License)

Copy

function playground() {
  // Replace the next line with your playground code.
  return factorial(5);
}

Community Discussions

Trending Discussions on playground

Convert interface with nullable string property to string property

Lifetime of async closure return type

Swift 5.5 async let - error: expression is 'async' but is not marked with 'await'

Can a function take both IntoIterator and IntoIterator<&T>?

How to convert JSON to DirectionsRoute

Scala sortWith for java.sql.Timestamp sometimes will or won't compile when using two underscores

Cannot modify the field in recursive structure

Using multiple files in SwiftUI playground

'Token has been expired or revoked' - Google OAuth2 Refresh token gets expired in few days

Google Drive API Listing Files with Field Paramter Not Working

QUESTION

Convert interface with nullable string property to string property

Asked 2021-Jun-15 at 18:49

I have the following two interfaces, one which allows a nullable vin, the other that doesn't:

...

ANSWER

Answered 2021-Jun-15 at 18:49

You can use a type predicate to define a user-defined type guard like this:

Source https://stackoverflow.com/questions/67989014

QUESTION

Lifetime of async closure return type

Asked 2021-Jun-15 at 18:22

Consider the following code:

...

ANSWER

Answered 2021-Jun-15 at 18:22

i think you are looking for this:

Source https://stackoverflow.com/questions/67991159

QUESTION

Swift 5.5 async let - error: expression is 'async' but is not marked with 'await'

Asked 2021-Jun-15 at 17:30

WWDC21 introduces Swift 5.5, with async/await. Following the Explore structured concurrency in Swift and Meet async/await in Swift WWDC21 sessions, I'm trying to use the async let function.

Here's my Playground code:

...

ANSWER

Answered 2021-Jun-11 at 00:14

My advice would be: don't try this in a playground. Playgrounds aren't ready for this stuff yet. Your code compiles and runs fine in a real project. Here's an example:

Source https://stackoverflow.com/questions/67927688

QUESTION

Can a function take both IntoIterator and IntoIterator<&T>?

Asked 2021-Jun-15 at 12:28

I want a function that takes two arguments, both of which can be turned into an iterator of Foo. The snag is that I'd like to accept things which are both IntoIterator and also IntoIterator<&Foo>. Importantly Foo is Copy so I can cheaply create an owned copy from it's reference.

The solution I currently have is:

...

ANSWER

Answered 2021-Jun-15 at 12:22

First of all, you don't need exactly IntoIterator bound here. It's just enough for Iterator.

Source https://stackoverflow.com/questions/67985315

QUESTION

How to convert JSON to DirectionsRoute

Asked 2021-Jun-15 at 08:12

I'm developing a simple navigator with mapbox API for Android. I'm creating some routes using https://docs.mapbox.com/playground/directions/ playground and i would like to use the generated JSON to generate a DirectionsRoute object. So i call DirectionsRoute.fromJson() but when i do it, the application crashes with this error:

...

ANSWER

Answered 2021-Jun-15 at 08:12

The response from the mapbox API is not DirectionsRoute. It is DirectionsResponse, a structure that looks like this:

Source https://stackoverflow.com/questions/67788140

QUESTION

Scala sortWith for java.sql.Timestamp sometimes will or won't compile when using two underscores

Asked 2021-Jun-14 at 23:28

I'm confused why a type that implements comparable isn't "implicitly comparable", and also why certain syntaxes of sortWith won't compile at all:

...

ANSWER

Answered 2021-Jun-11 at 10:35

// Works but won't sort eq millis
val records = iter.toArray.sortWith(_.event_time.getTime < _.event_time.getTime)

Source https://stackoverflow.com/questions/67929439

QUESTION

Cannot modify the field in recursive structure

Asked 2021-Jun-14 at 12:14

I have a recursive structure, where field of a structure is a reference to other struct of same type:

...

ANSWER

Answered 2021-Jun-14 at 12:14

You are using a &, but want a &mut, rust references are immutable by default: Playground: https://play.rust-lang.org/?version=stable&mode=debug&edition=2018&gist=be82b8ba01dff60e106af9e59df8228e

Source https://stackoverflow.com/questions/67969945

QUESTION

Using multiple files in SwiftUI playground

Asked 2021-Jun-14 at 10:13

I am trying to use multiple files in SwiftUI playground. I added some code in a separate file in sources. I just want the sheet view to appear when the button is tapped. Even though I have made the struct public but I still get the error as " SecondView initializer is inaccessible due to internal protection level "

Here's the code:

...

ANSWER

Answered 2021-Jun-14 at 10:13

The default initialiser (the one generated by the compiler, since you didn't declare one explicitly) is actually internal.

This is documented here:

A default initializer has the same access level as the type it initializes, unless that type is defined as public. For a type that’s defined as public, the default initializer is considered internal. If you want a public type to be initializable with a no-argument initializer when used in another module, you must explicitly provide a public no-argument initializer yourself as part of the type’s definition.

So you should do:

Source https://stackoverflow.com/questions/67968340

QUESTION

'Token has been expired or revoked' - Google OAuth2 Refresh token gets expired in few days

Asked 2021-Jun-14 at 08:19

I am using google analytics api to fetch analytics data. I tried to authenticate it using following steps : -> created OAuth client id in https://console.developers.google.com/ credentials section. -> In consent screen I had set publishing status as testing -> In OAuth 2.0 Playground I got the refresh token using above generated client id and client secret -> Then I am using it to generate access token through it.

But After few days refresh token seem to expire again and again although it is mentioned that refresh token validity is life long.

...

ANSWER

Answered 2021-Feb-20 at 14:17

I needed to send mails from a gmail account that I have access to, using nodemailer. It works for a couple of days before my refresh token is mysteriously revoked, even though the account belongs to me. A google search brought me here and I had been watching for a while hoping someone would help with a solution.

As you mentioned, this seems to happen with only test/unverified apps and I'm guessing google revokes tokens for such applications in your account after a few days. After much trials and errors, here is what I did.

NOTE: This is solution is only applicable to accounts you own, otherwise you must verify your app to access other people's accounts

Generate a new refresh token (existing one is most likely revoked) as described in this SO post
Go to the security tab of your google account dashboard
Under the Recent security activity section, you should see a security alert for your app.
Click on the context menu next to the notification and click DISMISS
At this point you'll be presented with a dialog of options where you indicate the level of trust you have for the app. I just went ahead and said I trusted the developer/app, obviously. And that's it! The refresh token should persist after this.

I could not find anything related anywhere else. So, please, accept this answer if it works for you. It might help someone else

Source https://stackoverflow.com/questions/66058279

QUESTION

Google Drive API Listing Files with Field Paramter Not Working

Asked 2021-Jun-14 at 02:05

I am currently listing some files with the Google Drive API. However, the default list only lists id, name, and mimeType. I know that the fields parameter can list more than just the default, but when I put parents as a field in the Google API Playground, I get the error of Invalid field selection parents. However, when I use * in the fields parameter, it returns all the fields. Am I doing anything wrong by putting parents in the fields parameter? If so, does anyone have any idea how to include the parents field as a field in the list results?

Here is my current endpoint, which causes the error:

...

ANSWER

Answered 2021-Jun-14 at 02:05

From https://www.googleapis.com/drive/v3/files?fields=parents&key=[YOUR_API_KEY], in your situation, when parents is directly put to fields as follows,

such error of Invalid field selection parents occurs. Because the method of "Files: list" returns the file list which is an array including each file metadata. Ref I think that this is the reason of your issue.

Solution:

So in this case, please set files(parents) instead of parents.

Note:

In the case of files(parents), only parents is returned. When you want to retrieve id, name, mimeType and parents, please use files(id,name,mimeType,parents) to fields.

References:

Source https://stackoverflow.com/questions/67961796

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install playground

You can download it from GitHub.
You can use playground like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: