pup | Pluggable Micro Packager

 by   mu-editor Python Version: 1.0.0a9 License: MIT

kandi X-RAY | pup Summary

kandi X-RAY | pup Summary

pup is a Python library. pup has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install pup' or download it from GitHub, PyPI.

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            kandi-support Support

              pup has a low active ecosystem.
              It has 8 star(s) with 3 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 32 open issues and 80 have been closed. On average issues are closed in 69 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of pup is 1.0.0a9

            kandi-Quality Quality

              pup has no bugs reported.

            kandi-Security Security

              pup has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              pup is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              pup releases are not available. You will need to build from source code and install.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.

            Top functions reviewed by kandi - BETA

            kandi has reviewed pup and discovered the below as its top functions. This is intended to give you an instant insight into pup implemented functionality, and help decide if they suit your requirements.
            • List all directories
            • Create a context
            • Invoke a plugin
            • Returns a list of classes and their name
            • List of directories available on this plugin
            • Extract the version from the source package
            • Read a file
            • Start logging
            • Return a logging level object from a string
            • Download a file
            • Download a file from a given URL
            • Spawn a new command
            • Spawn a subprocess
            • Creates icon files
            • Find meta tag
            • Create an icon
            Get all kandi verified functions for this library.

            pup Key Features

            No Key Features are available at this moment for pup.

            pup Examples and Code Snippets

            No Code Snippets are available at this moment for pup.

            Community Discussions

            QUESTION

            Function app in Visual Studio 2019 16.10.0: no functions runtime
            Asked 2021-Jun-07 at 11:49

            Yesterday I updated Visual Studio to the latest (Professional 2019 16.10.0) But today suddenly my functionapp project isn't running anymore. A pup-up is shown with the exception: 'There is no Functions runtime available that matches the version specified in the project'. I'me still able to run my functionapp from command line, so I think the issue is with the new Visual Studio version.

            I've got TargetFramework netcoreapp 3.1 and AzureFunctionsVersion V3. Package Microsoft.Azure.EventGrid 3.2.0 and Microsoft.Azure.WebJobs 3.0.22, Microsoft.Net.Sdk.Functions 3.0.9

            Any suggestions?

            ...

            ANSWER

            Answered 2021-Jun-07 at 11:49

            Ok, so my colleague has found the solution. It turned out to be case sensitivity. When I changed the AzureFunctionsVersion from V3 to v3, the problem was solved!

            Source https://stackoverflow.com/questions/67808266

            QUESTION

            The argument type 'File?' can't be assigned to the parameter type 'File'
            Asked 2021-May-24 at 00:57

            After i do pup upgard, The error says "The argument type 'File?' can't be assigned to the parameter type 'File'."

            Maybe it is because

            element.id == id) .first .getFile()> is type 'File?'

            But i'm not sure how can i change this.

            ...

            ANSWER

            Answered 2021-May-24 at 00:57

            File? means that this object can be either File or null, while the File type can't be null and it will throw an error if you try to make it null. To solve your problem you can either change type of the parameter of your function (the function where you pass data from this Future) from File to File? or if you can guarantee that .getFile() won't ever return null, you can put an bang operator (!) after your function call like this:

            Source https://stackoverflow.com/questions/67665494

            QUESTION

            JavaScript Linking Select Options to Snippets of Code
            Asked 2021-May-23 at 17:53

            I'm brand new to JavaScript, so please be patient. I've searched online the last few days looking for a solution, but I'm not finding one. A big reason for that is I don't really know what I'm supposed to be looking for.

            With that being said, help with code would be great. If you don't care to write any code in response, but would be willing to point me in the right direction as to what would be a solution for my problem, that would be fantastic as well.

            What I'm trying to do: User chooses an option from the second dropdown box which then displays the 'SHOW ME WHERE TO GO' button. When the button is clicked, a div is displayed over the top with a video embedded in it to provide them directions.

            My problem: I feel like I need an array or object of some kind to link select options to snippets of embed code for dropping into the directions_container div. I don't know how to link options selected by the user to the appropriate code snippets. Clicking the SHOW ME WHERE TO GO button should trigger the appropriate snippet of code to be inserted into the div tag.

            Below is my current project code.

            HTML

            ...

            ANSWER

            Answered 2021-May-23 at 17:53

            I think it would be a good idea to have the data about what to select in an array/object.

            I guess there are a lot of new stuff here, but notice especially that the data item is inserted into the option element as itemdata. This is a trick for passing around data.

            Source https://stackoverflow.com/questions/67660159

            QUESTION

            Responsive menu won't pop up
            Asked 2021-May-22 at 02:12

            my code is here

            https://codepen.io/bunea-andrei/pen/ZEeeWPK

            I'm talking about the mobile view of the website , please make the screen smaller until it changes to the stance I'm referring to

            I assume it's something wrong with my JavaScript code and I spent the last 3 hours trying to figure out what is it

            Code is here

            ...

            ANSWER

            Answered 2021-May-22 at 02:12

            The specificity for the selector .wrapper-active that is applying the transform to show the navigation has a lower specificity value than menu .wrapper, which is also defining a transform. This is causing the transform: translateX(-100%); to take over.

            Adding more specificity to the active class should do the trick:

            Source https://stackoverflow.com/questions/67644984

            QUESTION

            JavaScript: Show If Any Option Has Assigned Value
            Asked 2021-May-20 at 16:33

            I'm new to this forum. I tried checking some previous solutions, but they didn't quite fit. I have conditional dropdown boxes that work as intended. However, I only want the SHOW ME WHERE TO GO button to show once the user selects from one of the secondary (child) menus. It doesn't matter which option they select so long as it isn't the default value showing in the box.

            I tried to set it up so that all the secondary menus are in an array that gets checked over in the function. Basically if whatever option is selected and is assigned a value, the button should show.

            Here is my code. What am I doing wrong? I'm just learning JavaScript, so please bear with me.

            ...

            ANSWER

            Answered 2021-May-20 at 16:20

            There are a couple of issues I see on your code.

            In your showbtn() function, your using the getElementsById function, but as far as I am aware, this doesn't exist. Were you trying to execute getElementsByName instead?

            Either way, that would return a NodeList that you'd have to iterate over, and I see that you're trying to check the onchange, which in itself is an assignable property. That wouldn't work as expected.

            I feel like you could simplify your logic by checking if at least one of your tags has a selected value that isn't "". Below is a simple suggestion - you can simplify if you want to by creating easier-to-select elements (either by names or class names, which would work with getElementsBy) // Array of select IDs. var arrayOfSelects = ['DHOps', 'LUOps', 'LTLOps', 'FEDEXOps']; // Iterate on each one. for (let select of arrayOfSelects) { var e = document.getElementById(select); // Checking if there is a selected value that isn't null, undefined, 0 or empty. if (e.value) { document.getElementById("submit").style.display = "block"; break; } }

            Source https://stackoverflow.com/questions/67624067

            QUESTION

            Google API OAuth 2 sign in something went wrong with new OAuth 2 client
            Asked 2021-Apr-29 at 09:07

            I am trying to make a discord bot that interacts with the google API specifically the Google Classroom API, so therefore I made a new project from the google console and created a new OAuth client for a web application. I enabled the Classroom API as well and selected all the scopes that I wanted to use:

            ...

            ANSWER

            Answered 2021-Jan-26 at 14:41

            I can't reply to the above issue (need more reputation) but can confirm that I am seeing the same behaviour. What makes it even more weird is that the issue only presents itself when the user attempts to perform the OAuth integration with an account that is already signed in. The user is presented with a generic “Sorry, something went wrong there. Try again.” error before even seeing the required scopes list. However if the user is not logged into their account, and logs in as part of the OAuth integration, then there is no error and integration can be completed successfully. The fact that this issue doesn't affect users who aren't logged in shows that the setup (callback API, credentials.json, etc.) is all correct. I believe this issue has been introduced in the last month or so.

            Source https://stackoverflow.com/questions/65821740

            QUESTION

            Jetpack Compose – LazyColumn not recomposing
            Asked 2021-Mar-29 at 12:49

            My LazyColumn is not recomposing but the value is getting updated.

            If I scroll down the list and scroll back up I see correct values for the UI

            MainActivity

            ...

            ANSWER

            Answered 2021-Mar-02 at 23:58

            The Flow pups is producing updated values as you can see in my logcat

            Not exactly.

            The Flow is emitting the same List of the same Puppy objects. I believe that Compose sees that the List is the same List object as before and assumes that there are no changes.

            My suggested changes:

            • Make Puppy be an immutable data class (i.e., no var properties)

            • Get rid of changeFlow and have getPuppies() return a stable MutableStateFlow> (or make that just be a public property)

            • In toggleAdoption(), create a fresh list of Puppy objects and use that to update the MutableStateFlow>:

            Source https://stackoverflow.com/questions/66448722

            QUESTION

            Bash + Pup printing only attribute
            Asked 2021-Mar-27 at 06:06

            I'm wgeting a webpage src code then using pup to grab the tag that I need. Now I want to print only the value of the content field.

            In this case, the output I want is: https://example.com/my/folder/first.jpg?foo=bar

            ...

            ANSWER

            Answered 2021-Mar-27 at 06:06
            wget -O /tmp/output.html --user-agent="user-agent: Whatever..." https://example.com/somewhere
            IMAGE_URL=$(cat /tmp/output.html | pup --plain 'meta[property*="og:image"]' | sed -n 's/.*content=\"\([^"]*\)".*/\1/p')
            

            Source https://stackoverflow.com/questions/66542545

            QUESTION

            NodeJS check typeOf node/module (Puppeteer)
            Asked 2021-Mar-20 at 21:06

            i am struggling with type checking at nodejs. I plan to use the library Puppeteer to test my own web pages. For this I would like to check in the methods that the function arguments have the correct type.

            How do I access the type "Page" from the module "Puppeteer"?

            Here's a code example

            ...

            ANSWER

            Answered 2021-Mar-20 at 21:06

            i did this to get the class name :

            Source https://stackoverflow.com/questions/66725940

            QUESTION

            How to solve 'could not find package integration_test in the Flutter SDK' error
            Asked 2021-Feb-15 at 12:57

            I have an app, it is very simple and I keep getting this error:

            pub get failed (server unavailable) -- attempting retry 1 in 1 second... Because bascis depends on integration_test any from sdk which doesn't exist (could not find package integration_test in the Flutter SDK), version solving failed.

            I have tried

            Pup upgrade, Pub get.

            How can I get rid of this error?

            ...

            ANSWER

            Answered 2020-Dec-31 at 09:49

            It is likely due to your network problem. Because the output says (server unavailable).

            Ways to debug this:

            1. Try curl https://google.com to see whether your command line can connect to network.
            2. Also try, for example, curl https://flutter.dev (or, try to curl the actual url your pub get is trying to access.

            This may due to, for example, your network is broken. Or because you have a broken VPN, broken proxy, etc.

            Source https://stackoverflow.com/questions/65518024

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install pup

            You can install using 'pip install pup' or download it from GitHub, PyPI.
            You can use pup like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            Install
          • PyPI

            pip install pup

          • CLONE
          • HTTPS

            https://github.com/mu-editor/pup.git

          • CLI

            gh repo clone mu-editor/pup

          • sshUrl

            git@github.com:mu-editor/pup.git

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