rfcs | repository contains proposals , standards | SDK library
kandi X-RAY | rfcs Summary
kandi X-RAY | rfcs Summary
This repository contains proposals, standards and documentations related to Nervos Network. The RFC (Request for Comments) process is intended to provide an open and community driven path for new protocols, improvements and best practices, so that all stakeholders can be confident about the direction of Nervos network is evolving in. RFCs publication here does not make it formally accepted standard until its status becomes Standard.
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Top functions reviewed by kandi - BETA
- Builds a keccak hash
- Performs the Keccak algorithm
- Performs Keccak F1600 on a given lane
- Calculate Keccak F1600
- Left - bit unsigned integer
- Load 64 bit unsigned integer
- Convert a 64 bit integer to a list of integers
- Calculate the Bloom hash of the input bytes
- Greater round
- Simplies a given sequence of input_bytes
- Permutation
- Creates a Keccak hash from input bytes
- Creates a keccak hash
- Builds a SHA3 hash of the input bytes
- Calculate the SHA256 hash of input bytes
rfcs Key Features
rfcs Examples and Code Snippets
def function(func=None,
input_signature=None,
autograph=True,
jit_compile=None,
reduce_retracing=False,
experimental_implements=None,
experimental_autograph_options=None,
def dynamic_rnn(cell,
inputs,
sequence_length=None,
initial_state=None,
dtype=None,
parallel_iterations=None,
swap_memory=False,
time_majo
def snapshot(path, compression="AUTO", reader_func=None, shard_func=None):
"""API to persist the output of the input dataset.
The snapshot API allows users to transparently persist the output of their
preprocessing pipeline to disk, and materi
Community Discussions
Trending Discussions on rfcs
QUESTION
I've been tinkering around with Rust's macro system for a while now, and recently got interested in nesting two macros together, like this:
...ANSWER
Answered 2022-Apr-11 at 04:22Yes, however...
You cannot insert the $
sign, as it is reserved for metavariables.
You have two options to tackle that.
On stable, you need to pass $
to the macro. Then it can refer to it using the metavariable.
QUESTION
I encountered this strange behaviour when reading this post, and the core question of this post is when you matching (&k, &v) = &(&String, &String)
, k
and v
will get the type String
.
To figure out what's happending, I wote the following test code, and the result is much more shocking and confusing to me:
...
ANSWER
Answered 2022-Apr-04 at 04:23This is called "destructuring". It's used commonly in pattern matching like with if let Some(val) = option
.
Essentially, this:
QUESTION
#r "nuget: DiffSharp.Core, 1.0.7-preview1873603133"
#r "nuget: DiffSharp.Backends.Reference, 1.0.7-preview1873603133"
#r "nuget: DiffSharp.Backends.Torch, 1.0.7-preview1873603133"
open DiffSharp
open DiffSharp.Util
let t3 = dsharp.tensor [[1.1; 2.2]; [1.1; 2.2]; [1.1; 2.2]]
1 + t3 //Does work!!
open System.Linq.Expressions
let addB = Expression.Parameter(typeof, "b")
let addC = Expression.Parameter(typeof, "c")
Expression.Add(
addC,
addB
) //=> Throw exception...
(*
System.InvalidOperationException: The binary operator Add is not defined for the types 'DiffSharp.Tensor' and 'System.Int32'.
at System.Linq.Expressions.Expression.GetUserDefinedBinaryOperatorOrThrow(ExpressionType binaryType, String name, Expression left, Expression right, Boolean liftToNull)
at System.Linq.Expressions.Expression.Add(Expression left, Expression right, MethodInfo method)
at System.Linq.Expressions.Expression.Add(Expression left, Expression right)
at .$FSI_0048.main@()
Stopped due to error
*)
...ANSWER
Answered 2022-Mar-18 at 16:00@panagiotis
QUESTION
Following the setup guide for Vuejs and Pin
...ANSWER
Answered 2022-Mar-16 at 16:47A bit of confusion on my end it seems. The docs talk about adding
Method 2:
QUESTION
I'm wading through a codebase full of code like this:
...ANSWER
Answered 2022-Feb-25 at 15:31There's an unstable feature that will introduce let-else statements.
RFC 3137Introduce a new
let PATTERN: TYPE = EXPRESSION else DIVERGING_BLOCK;
construct (informally called a let-else statement), the counterpart of if-let expressions.If the pattern match from the assigned expression succeeds, its bindings are introduced into the surrounding scope. If it does not succeed, it must diverge (return
!
, e.g. return or break).
With this feature you'll be able to write:
QUESTION
The offical RFC
There is a example for effect
ANSWER
Answered 2022-Jan-18 at 08:47What would making a coffee look like in code?
QUESTION
I would like to play around XMPP to learn and test some RFCs. But writing app to test them is just something I want ro avoid because of limited time.
For rest APIs Postman and the like have been time savers. So the question is, is there anything similar or at least closer that I can use to send XMPP requests and receive responses?
...ANSWER
Answered 2022-Jan-10 at 06:20PSI+ (Qt, C++ ) client (github.com/psi-im/psi), allows to send raw XMPP stanzas...
XMPP JS (github.com/xmppjs/console) might offer similar functionality
QUESTION
I'm trying to use computed
fields in VueJs.
Previously it was achievable with:
...ANSWER
Answered 2021-Dec-23 at 06:37In the new setup syntax, you use computed
to create a computed property:
QUESTION
I'm on windows and have
a Rust cdylib
...ANSWER
Answered 2021-Dec-10 at 13:32Rust is meant to compile to a single program, which is one of the arguments that C++ users use against Rust. Rust binaries are much larger because all the libraries are statically linked instead of dynamically linked. Is there a specific reason that you need to dynamically link instead of statically link?
The target/*/deps folder contains the compiled libraries that are statically linked to your binary.
QUESTION
One email provider rejected an email containing special characters (e.g. umlaute). They say that they are RFC-5321 and RFC-5322 compliant. Now I browsed those standards however they are not supporting international emails (thus no umlaute). Only ASCII-127 is supported. Now there is an extension called RFC-6532 which standardizes international emails. Our emails are UTF-8 (quoted-printable) encoded and sent like this:
"=?UTF-8?Q?B=C3=B6rge_M=C3=B6ller?="
Is this an RFC-6532 compliant address? Or is it some other/older RFC (like RFC-2054)? After all there are so many mail related RFCs that I might have missed 10 or 20 ;-)
...ANSWER
Answered 2021-Nov-08 at 15:07It's on the right track, but it's wrong.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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