Password_Generator | Password Generator in python GUI
kandi X-RAY | Password_Generator Summary
kandi X-RAY | Password_Generator Summary
Password Generator in python GUI. This is an simple pasword generator made in python. This is a stupid idea but i like to make this project. Modules i use for making this project: Tkinter String random. This project is made in python 3.9 and only tested in windows 10. How to use it? Open the main.py file and then you will see this window. Just type your password lenght in the text box and click on generate and than your password will generate you can copy it from the bottom one text box :). If you like my small project you can give me a small star :).
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Password_Generator Key Features
Password_Generator Examples and Code Snippets
Lines of Code : 15License : Permissive (MIT License)
Copydef password_generator(length=8):
"""
>>> len(password_generator())
8
>>> len(password_generator(length=16))
16
>>> len(password_generator(257))
257
>>> len(password_generator(length Community Discussions
Trending Discussions on Password_Generator
QUESTION
import random
import PySimpleGUI as sg
def password_generator(pw_len):
password = "".join(random.sample(chars, pw_len))
return password
chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789|!\"£$%&/()=?^é*ç°§;:_è+òàù,.-[]@#{}"
sg.theme('DarkPurple3')
layout = [[sg.Text('Password Generator', font=('Roboto', 20), justification='center')],
[sg.Text('Set password length: ', size=(15, 1)), sg.InputText(size=(15, 1), key='length')],
[sg.Text(size=(40,1), key='-OUTPUT-'), ],
[sg.Button('Generate', size=(15, 1)), sg.Button('Exit', size=(15, 1))]]
window = sg.Window('Password Generator', layout)
while(True):
event, values = window.read()
if event == 'Exit':
break
elif event == 'Generate' or sg.WINDOW_CLOSED:
pw_len = int(values['length'])
window['-OUTPUT-'].update('Your password: ' + password_generator(pw_len))
window.close()
ANSWER
Answered 2022-Apr-08 at 16:57The content of Text element cannot be selected and not copyable.
Using Input or Multiline element for it and set disabled=True.
For example
QUESTION
import itertools
def password_generator():
with open("D:\Password Hacker\Password Hacker\\task\passwords.txt", "r") as passfile:
for word in passfile:
if not word.isdigit():
for var in itertools.product(*([letter.lower(), letter.upper()]for letter in word.strip("\n"))):
yield ("".join(var))
else:
yield (word.strip("\n"))
g = password_generator()
for i in range(10):
print(g.__next__()) #prints same result everytime...
ANSWER
Answered 2022-Mar-28 at 18:36try :
QUESTION
I am developing a Kivy password generator. The user is required to input a number (digit) into the app for password generate depending on how many characters are intended. Then, the app will generate a random character from the randint, finally, the output will be displayed into the output entry for a copy to the click board. Following are my code:
password_generator.py
...ANSWER
Answered 2022-Feb-09 at 22:32Try changing pw_length in your password() function to:
QUESTION
I am fairly new to Python and am trying this project. I need to store usernames and passwords in a text file ( to create a database). I have used the pickle module. The code I've tried erases previously-stored data every time I run the code.
I have understood that I have to append data to the file instead of writing to it but I don't know how. How can I correct the code?
...ANSWER
Answered 2021-May-25 at 12:22It appears you were using "wb" instead of "ab" in this function, which caused the file to reset everytime you wished to save to it. Also, The filename should be "UserDict", instead of "UserText".
QUESTION
I forgot my password and I wrote this code with Selenium to try to recover my pass, but I don't know how to continue. The button new password doesn't work. Can someone help me? I try different ways to continue but I don't know. Is any way to enter?
I am trying to remember my password using the function. Something like force brute. So, I dont know how to make a loop generating a new password, with the function, enter it in the box "Contraseña: " until it is correct
...ANSWER
Answered 2021-May-27 at 02:581 The locator you used is not unique (there are two of them). So I replaced it with xpath locator //input[@name='form_email'].
2 You are using time.sleep everywhere. It may be slower then using Selenium's explicit/implicit wait and also it's very unstable
So, I added wait = WebDriverWait(driver, 30) to your code and applied explicit waits.
3 Also, I noticed that page-try id is not unique, so I replaced it with css selector. If you are using find_element..., not find_elements... then your locators have to be unique.
Solution
QUESTION
I am making a password generator which requires me to enter the length of the password and the website for which i am saving that password. the password and website name are stored in an excel sheet. so in this project i am using tkinter and openpyexcel. when i run the code everything goes well, i enter the website name, the length of the password and the password is generated. but when is open the spreadsheet, the password and website name is not saved there. here is the code:
...ANSWER
Answered 2021-Mar-21 at 17:05Does the sheet have a header?
If it does you should use this.
QUESTION
I use actix-web and want to generate pairs of (password, password hash).
It takes some time (0.5s).
Instead of generating each pair on demand:
...ANSWER
Answered 2021-Feb-10 at 12:58You can just use a regular thread (as in std::thread::spawn): while actix probably has some sort of blocking facility which executes blocking functions off the scheduler, these are normally intended for blocking tasks which ultimately terminate. Here you want something which just lives forever. So an stdlib thread is exactly what you want.
Then set up a buffered, blocking channel between the two, either an mpsc or a crossbeam mpmc (the latter is more convenient because you can clone the endpoints). With the right buffering, the procuder thread just loops around producing entries, and once the channel is "full" the producer will get blocked on sending the extra entry (21st or whatever).
Once a consumer fetches an entry from the channel, the producer will be unblocked, add the new entry, generate a new one, and wait until it can enqueue that.
QUESTION
I am creating a flask program which generates a certain number of passwords depending on the user's demand. The user gets the freedom of editing the password. The source code is mentioned below.
Password_creator.py
...ANSWER
Answered 2020-Aug-02 at 18:41Ok, so after looking through you code I think I figured out your issue.
However I want to say there is a lot of bad practices in your code. One of the biggest ones is using globals in a web app. You should never do this. If you plan to run multiple instances of this app to handle more requests then the other instances will not have access to other instances globals so you will have many bugs that will be difficult to trace down.
Anyways the issue I see in your generate function.
When you submit a change to the password it does get saved. But that save is completely destroyed because in your generate function you don't check for previous passwords you also have no way of knowing if something did change or if you really do want to generate a new set of passwords.
My advice
Learn the proper setup and structure for a web app.
Don't use globals ever in a web app. Too many bugs will come from this and will be a pain to find.
Your app looks like it will just be a normal web app with no javascript or ajax, so don't use PATCH or DELETE for form methods. Use GET and POST and use differing urls to decide how to handle those requests.
If there's not a good tutorial out there for flask on how to setup endpoints/urls for your app, then look at the setup for Django projects. Flask mimics Django in a lot of ways on how it handles endpoints/urls.
QUESTION
a = False
while a == False:
quant = int(input("Input the size:\n"))
if type(quant) == int:
a = True
else:
print('Please use numbers:\n')
a = False
ANSWER
Answered 2020-Mar-16 at 19:13There are a number of ways you can tackle this issue. Firstly your error comes because you are trying to convert the string to an int. when the string has chars those cannot be converted to an int so you get a ValueError. You could utilise this behaviour to validate the input
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No vulnerabilities reported
Install Password_Generator
You can use Password_Generator like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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