paramiko | The leading native Python SSHv2 protocol library
kandi X-RAY | paramiko Summary
kandi X-RAY | paramiko Summary
The leading native Python SSHv2 protocol library.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Connect to the specified host and port .
- Parses the kex .
- Parses the user auth request .
- Process a message .
- Read the message .
- Read a line from the file .
- Parse signing key data .
- Handles a request .
- Read an OpenSSH private key .
- Creates a tar file with the given base name .
paramiko Key Features
paramiko Examples and Code Snippets
Lines of Code : 187License : Non-SPDX (GNU Lesser General Public License v2.1)
Copy#!/usr/bin/env python
# Copyright (C) 2003-2007 Robey Pointer
#
# This file is part of paramiko.
#
# Paramiko is free software; you can redistribute it and/or modify it under the
# terms of the GNU Lesser General Public License as published by the #!/usr/bin/env python
# Copyright (C) 2008 Robey Pointer
#
# This file is part of paramiko.
#
# Paramiko is free software; you can redistribute it and/or modify it under the
# terms of the GNU Lesser General Public License as published by the Free #!/usr/bin/env python
# Copyright (C) 2003-2007 Robey Pointer
#
# This file is part of paramiko.
#
# Paramiko is free software; you can redistribute it and/or modify it under the
# terms of the GNU Lesser General Public License as published by the Community Discussions
Trending Discussions on paramiko
QUESTION
I want to check the reachability of about 100 ips addresses and set a limit of concurrent tasks with semaphore. But now I'm not sure how this works exactly or why it doesn't work in the code example. As I could observe the function "task_reachable" is still executed correctly. if no address is reachable, then in the "try_ssh_connection" "all" tasks are executed in parallel and this makes the code incredibly slow.
...ANSWER
Answered 2022-Mar-22 at 14:05Your problem is each running instance of boundary_task has its own semaphore.
QUESTION
I have a intermittent issue with execute remote operations using Paramiko.
...ANSWER
Answered 2022-Mar-17 at 18:05It's probably a race condition. The exit_status_ready can return true if the command has finished, even if you have not read its complete output yet.
The correct code is like:
QUESTION
I try to use library cv2 for changing picture. In mode debug I found out that problem in function cv2.namedWindow:
...ANSWER
Answered 2021-Nov-07 at 00:17I reverted back to Xorg from wayland and its working, no more warnings
Here are the steps:
- Disbled Wayland by uncommenting
WaylandEnable=falsein the/etc/gdm3/custom.conf - Add
QT_QPA_PLATFORM=xcbin/etc/environment - Check whether you are on Wayland or Xorg using:
QUESTION
As part of a larger task I want to move some files, work on them and return the new files to the sftp server. Due to restrictions laid upon me I am only able to use Python 3.4, which excludes me from any nice and fancy modules like Paramiko and pysftp.
Connection to the server fails, according to the stdout pipe the hostkey is incorrect. The returned "incorrect" key is not identical to the one that was passed to the function. It has an additional, leading backslash and is cut short. The originally passed key is "ssh-XXXXXXX 256 XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX". The "incorrect" key is "\ssh-XXXXXXX".
The presumption is, that subprocess.Popen mangles the string in a way.
- hostkey, passphrase, and privatekey are all necessary
- the hostkey has been generated directly by the server and matches the fingerprint returned by the stdout pipe
- the connection works when done in a windows shell, but implementation in python is desired.
- the connection works when accepting any given Key through usage of
*, but that would obviously be insecure, therefore not viable.
Code is as follows:
...ANSWER
Answered 2022-Feb-23 at 07:11I believe it's Windows Python issue.
Just format the commandline yourself, instead of having Popen doing (incorrectly) it for you:
QUESTION
I'm trying to connect to am SFTP server through Paramiko. I don't have a host key. The following code is my attempt and it's giving me an error that says:
paramiko.ssh_exception.SSHException: Error reading SSH protocol banner
I notice that port is usually 22 in other given examples, but the SFTP port I was given is 21. And when I tried 22, it gave me another error saying
Unable to connect to port 22
Thank you in advance for your guidance and insight. Please let me know if I could provide more information.
...ANSWER
Answered 2022-Feb-09 at 17:05Paramiko is an SFTP client. The SFTP uses port 22.
If you were given port 21, then it's most likely NOT SFTP. The port 21 is used by FTP. Encrypted variant of FTP, called also FTPS, uses 21 too. And people sometimes mistake it for SFTP.
For FTP use FTP class from ftplib. For FTPS use FTP_TLS class from ftplib.
QUESTION
I tried translate command
ssh -R 80:localhost:8080 nokey@localhost.run (It works as it should, problem not in server)
to Paramiko with help of https://github.com/paramiko/paramiko/blob/master/demos/rforward.py
My code:
...ANSWER
Answered 2022-Feb-05 at 17:30-R 80:localhost:8080
QUESTION
The principle of the script is that it should connect from one virtual machine to another via an SSH connection and generate a certain number of folders. The script runs, but when executed, generates folders on the host machine.
...ANSWER
Answered 2022-Jan-29 at 19:35Jane, its making dirs on your local box because that is where the python script is running.
I suggest you look at this question and answer.
In that QandA, they show how to use ssh on the local box to execute commands on a remote box. You could use your existing code as the code which is run on the remote box using the above as your guide.
Specifically this this one
QUESTION
I'm trying to open a file which got created as part of the Paramiko exec_command. The file gets created, but when I check if the file exists, it always returns false. How do I check if the file exists and then open the file for reading?
The code written is:
...ANSWER
Answered 2022-Jan-26 at 09:54First, you are not waiting for the command to complete.
For that see:
Wait to finish command executed with Python Paramiko
Once the command completes, you can retrieve its exit code using Channel.recv_exit_status():
How can you get the SSH return code using Paramiko?
If it returns 0, you know that everything went fine and no additional check is needed.
Anyway, if you want to check, use SFTP (SFTPClient.stat):
QUESTION
I have ec2 instance with ubuntu v20.04 and it has python v3.8.10 and pysftp 0.2.9.
I have generate .pem file from .ppk file using below command
puttygen sftp_server.ppk -O private-openssh -o sftp_server.pem
I am able to connect successfully to sftp server using command line-
...ANSWER
Answered 2022-Jan-28 at 09:18The error comes form underlying Paramiko and is discussed here:
Paramiko authentication fails with "Agreed upon 'rsa-sha2-512' pubkey algorithm" (and "unsupported public key algorithm: rsa-sha2-512" in sshd log)
Though pysftp does not expose the disabled_algorithms parameter.
You better switch to using Paramiko directly. The pysftp is abandoned project. See pysftp vs. Paramiko.
QUESTION
I am trying to connect to some SFTP using a private key file that looks like:
...ANSWER
Answered 2022-Jan-21 at 12:40You have a private key in rarely used ssh.com format. Paramiko does not support it. You have to convert it to the OpenSSH format.
You can use ssh-keygen like this:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install paramiko
You can use paramiko like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
