bigO | Symbolic representation of big-O notation
kandi X-RAY | bigO Summary
kandi X-RAY | bigO Summary
I was looking for something like this but couldn't find it. So I wrote it, and it turned out to be much simpler than I expected. Note that much of this functionality can now be achieved using sympy.series.order, if you're careful to specify that your limits go to infinity.
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Top functions reviewed by kandi - BETA
- Return a sympy ratio .
- Initialize the expression .
- Return True if other is equal .
- Return True if self is greater than self .
- Return True if self is less than self .
- Create a BigO .
- Returns the maximum occurrence of the given sequence .
- String representation .
bigO Key Features
bigO Examples and Code Snippets
Lines of Code : 16License : Permissive (MIT)
Copyimport sympy
from bigO import O, n
f_time = O(n)
g_time = O(n**2)
h_time = O(sympy.sqrt(n))
fastest_asymptotically = min(f_time, g_time, h_time)
# = h_time
total_time = f_time.inside(g_time).followed_by(h_time)
# = O(n**3)
# If you prefer a less Community Discussions
Trending Discussions on bigO
QUESTION
My question stems from this: https://leetcode.com/problems/search-a-2d-matrix/
In math Log A + Log B = Log AB
Is this still valid for BigO notation?
Are two log searches Log A + Log B equal to one search of Log AB?
ANSWER
Answered 2021-May-01 at 20:54Yes, since you can manipulate the terms in Big-O notation in familiar algebraic ways, O(Log A + Log B) = O(Log AB).
When talking about two sequential searches, though, it might be more intuitive to leave it at O(Log A + Log B). You might want to simplify that to O(Log AB) if you're comparing to some other algorithm, or trying to find dominant terms.
QUESTION
Consider an algorithm that uses no extra variables except the given input.
How to represent the space complexity in BigO Notation?
...ANSWER
Answered 2021-Apr-22 at 18:26O(1)
Where it requires a constant amount of additional space namely 0.
QUESTION
if wrote the following algorithm to generate all permutations without repetition but I have a hard time figuring out the BigO if it. I'm mostly interested in the time-complexity.
...ANSWER
Answered 2021-Apr-19 at 17:36Pretty sure it filters down to O(n^3), since you have 3 major loops in your initial for loop and 2 map calls. I think we ignore the slices since they add complexity linearly, while the nested loops are exponential.
I'm not positive that we include the variable.map, so it could be O(n^2), but I don't think that's the case. In most cases I would just simplify it to polynomial complexity, unless it's a case where the degree matters.
QUESTION
int find_peak (int n, int A []) {
int left, right, lmid, rmid;
left = 0;
right = n - 1;
while (left + 3 <= right) {
lmid = (2 * left + right) / 3;
rmid = (left + 2 * right) / 3;
if (A[lmid] <= A[rmid])
left = lmid;
else
right = rmid;
}
int x = left;
for (int i = left + 1; i <= right; i ++)
if (A[i] > A[x])
x = i;
return A[x];
}
ANSWER
Answered 2021-Mar-15 at 10:03Yes, the loop is cut roughly in half at each iteration
QUESTION
Hi I have written the below code to find the first pair of numbers that match the sum of the target. I have a fair idea about BigO notation but I am finding it difficult in the below scenario.
...ANSWER
Answered 2021-Mar-05 at 07:49The time complexity of your code is O(n^2). Here is your code:
QUESTION
This is a method i wrote that checks if two strings are premutations of each other:
...ANSWER
Answered 2021-Jan-23 at 06:17You haven't considered the time complexity for the replace() method. It takes O(N) time complexity.
Agreed that you are processing the strings depending upon certain conditions, but the 2 for loops anyway make the time complexity O(N^2).
Therefore, overall time complexity = O(N^2 * N) = O(N^3).
To be precise, if the length of str1 is N and the length of str2 is M, then the time complexity ~ O (N * M * (N + M)).
QUESTION
Using the following ANTLR grammar: https://github.com/bkiers/python3-parser/blob/master/src/main/antlr4/nl/bigo/pythonparser/Python3.g4 I want to parse from a given expression, lets say:
...ANSWER
Answered 2021-Jan-21 at 12:21I didn't look too closely at it, but after inspecting the parse tree for the Python code:
QUESTION
ANSWER
Answered 2021-Jan-18 at 07:45create a computed property that transform your object in list of objects like {text: 'something', value: 2}, which is required in v-select.
Do it like this:
QUESTION
As per docs ConcurrentModificationException states: ConcurrentModificationException occurs when an object is tried to be modified concurrently when it is not permissible.
I'm trying to de-rust my java brain and make a huffman compression jawn. I have a helper function that is probably causing this? When I pass in root and set it to the new root which is returned by huffmanHelper
(my code probably isn't doing what I want it to yet, I don't need help with huffman stuff or a breakdown of my bigO) My question: I'm simply curious behind the scenes why what I am doing is a problem in java.
thank you
...ANSWER
Answered 2020-Dec-27 at 05:11This line removes an element from the priority queue:
QUESTION
I want to get a value from an API. However I am unable to tell Python what I want to do.
This is my current code:
...ANSWER
Answered 2020-Dec-21 at 02:02You have a list of dict in your first example. So first you need to select which dict you want. For instance, if your query is called 'json_list'
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Install bigO
You can use bigO like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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