mhi | commandline style mailreader in the tradition of mh and nmh
kandi X-RAY | mhi Summary
kandi X-RAY | mhi Summary
mhi is a commandline style mailreader in the tradition of mh and nmh, but mutated to support IMAP.
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Top functions reviewed by kandi - BETA
- Read a LISP expression
- Read a single character
- Parse an atom
- Unget a character
- Skip comments
- Skip whitespace
- Read a string
- Read atom from the file
- Read a list from the stream
- Parse a string
- Return the next token
- Unget a character
- Convert token to T_int and float
- Get the current character
- Read a symbolic expression from text
- Read LISP expression
- Read requirements file
mhi Key Features
mhi Examples and Code Snippets
Lines of Code : 5License : Strong Copyleft (CC BY-SA 4.0)
Copy [new_list] = [['a','b','c','d']]
print(new_list)
['a','b','c','d']
def flatten(container):
for i in container:
if isinstance(i, (list,tuple)):
for j in flatten(i):
yield j
else:
yield i
str = """
[
{
"_fpmlVersion": "5-6",
"ids = [x['m:assetPricing'][0]['m:instrumentId'][0]['#value'] for x in data]
print(ids)
['100001380992', '100001380993', '100001380994', '100001380995', '100001380996', '100001380997', '100001380999', '100001381000' account_ids = [i['accountId'] for i in data['identifiers']['identifier']if i['accountIdType']=="ACCOUNTID"]
accs = {
"identifiers": {
...
account_id_list = []
for acc in accs.get("identifiers", {}).get("identifier", []):
account_id_list.append(acc.get("accountId", ""))
['MHI', 'DKEPBNPGIV', 'DKEPLLP SG', 'DAVKEMdf= pd.DataFrame(esponse_parsed['dividends'])
df_grouped = df.groupby('metric')
mhi_dict = {}
for key in df_grouped.groups:
group = df_grouped.get_group(key)
mhi_dict[key] = group
import re
with open('abc.txt', 'r') as file:
raw = file.readlines()
for line in raw :
if re.search(r'^From:', line):
print line
with open('abc.txt', 'r') as f:
for l in f.readlines():
if re.search(r'\bFrom\b', l):
print(l)
From: CN=deepak sethi/O=MHI
Community Discussions
Trending Discussions on mhi
QUESTION
so this is what i get from the API, but I really dont need the first "dividends" heading
...ANSWER
Answered 2021-May-05 at 09:30You are close, select data by key dividends:
QUESTION
So the issues is that I have a large dataframe (some millions of rows) and I need to split it into separate dfs based on a value of metric (which can have several thousand unique values in the df) and then put all individual dfs into a dictionary.
The data looks like this:
...ANSWER
Answered 2021-Feb-17 at 04:29df_grouped = df.groupby('metric')
mhi_dict = {}
for key in df_grouped.groups:
group = df_grouped.get_group(key)
mhi_dict[key] = group
QUESTION
Given a graph where members of an organisation, have one or several relationships to that organisation, and members have incidents, I'm am attempting to return a list of incidents, each including the associated member and a list of their relationships to the organisation.
the graph structure:
(org)<-[MEMBER_OF|ADMIN_OF|MANAGER_OF|VISITOR_OF]-(member)-[:HAS]->(incidents)
The query I'm current attempting:
...ANSWER
Answered 2020-Aug-27 at 13:44You could use the type() and collect() functions to extract the type of relationship from rels and have them as a list.
collect(DISTINCT type(rels)) will leave you with distinct roles as an array of strings.
You might want to consider ensuring that you have DISTINCT in your collect() of incidents so that you don't have duplicate results when you unwind.
Your query when then look something like the following:
QUESTION
There are so many different numeric data types in PL/1. And I want to know when there is an integer devision, and where is not. For instant, I've written a small example that shows (at least for me) that PL/1 is very entangled in it:
...ANSWER
Answered 2018-Jan-12 at 11:23The difficult point about your question is that the results depend on the compile-options used (at least with Enterprise PL/I 4.5 which we are using).
Under RULES(ANS) it is using integer-division as expected and both expressions evaluate to 34.
Under RULES(IBM) it is using neither integer nor floating-point division but fixed-point binary division with a scale factor!
The full table of datatype-conversions in arithmetic expressions can be found here (for Enterprise PL/I 5.2).
So let's analyze the datatypes used:
BIN15 is BIN FIXED(15,0) and the literal 11 is DEC FIXED(2,0).
According to the PL/I Language Reference under RULES(IBM) the result for BIN15/11 will be BIN FIXED(31,16) (assuming the maximum precision for binary is 31).
So before division the first operand is shifted right by 16 bits resulting in a hex-value of 26 00 00. Division by 11 results in hex 03 74 5D which converts to (approximately) 3,45454.
Multiplying by 11 results in 37,99994 which is truncated to 37 before the addition.
As for your finaly question when PL/I is using integer-division and when not:
Under RULES(IBM) PL/I will never use integer-division.
Under RULES(ANS) PL/I will use integer-division when both operands are unscaled FIXED (i.e. FIXED(x,0)) and at least one of them is BINARY.
As an addition, here is the assembly-code generated with RULES(IBM):
QUESTION
i have a custom login dialog box largely copied from here it works fine, but i am facing problem with getting it to show and get userdata at most 3 times before allowing the user forward if credentials are true or closing the program if wrong credentials are entered 3 times in a row. Heres my code....
...ANSWER
Answered 2017-Sep-29 at 10:11I tried with standard JavaFX dialogs, and this works:
QUESTION
Recently, my IBM PCOMM had been upgraded at my job to version 12.0.0.1. Ever since, if I'm trying to detect blank space, and something was already there previously, that text will show up when I use autECLPS.GetText even though all I see is black. I need a way to see if there is hidden text so I know I can go onto the next procedure. I've been using autECLPS.GetTextRect to see if I can match entire blocks of text, but that's becoming tedious. Any suggestions?
UPDATED
Here's what I have so far:
...ANSWER
Answered 2017-Aug-16 at 14:28After receiving advice from the talented people on SO, and doing a bit more research, I've changed my code to a solution that works. It's not much different from the original, but it's more reliable.
QUESTION
In order to deal with validation of fields with multiple optional checkboxes I used webshims polyfill.
The form has checkboxes that hide/unhide sections of the form.
Initial task was to only validate/require the hidden sections if they became visible.
My initial idea was to use the features of webshims polyfill to only require a hidden field if the checkbox associated with making that field visible was checked.
Problem #1: Some of the hidden sections include these multi-checkbox type fields that need validation. How do I get these fields to make use of webshims' data-grouprequired="" feature so I can validate these multi-checkbox fields?
Problem #2: There is one hidden section (Registries/id=div3) with 5 input text fields - the end user only needs to fill in at least one of these fields. How do I make it so that when this hidden section becomes visible, only a minimum of one of the 5 fields is required in order to validate the form?
Alternatively, if there is a better solution I'd love to learn. I am very new to this.
Here's the relevant code from the form:
...ANSWER
Answered 2017-Jul-12 at 16:36Eventually figured this out myself. Disabled all hidden fields. Had them become enabled on becoming visible. For the multiple text fields was able to use data-grouprequired from webshims polyfill but had to create a custom error message.
QUESTION
Text file:
...ANSWER
Answered 2017-Jun-30 at 08:35Regexp's word boundary is presented with \b, not /b:
QUESTION
I am using beautiful soup with requests package in python 2.7 for web news scrapping.When I debug the below code I get the error.
...ANSWER
Answered 2017-May-10 at 02:01In your classCrawler, the function getNextUrls() return list:
QUESTION
I have a folder of images and I d like to proceed on them the treatment of (Motion History Image) MHI. So I didn't know how to take 2 images successively in FOR LOOP to work on them.
Any help pls, Thank you!
...ANSWER
Answered 2017-Apr-21 at 09:18the following code will open the first 2 files, then the second pair of new files, and so on so forth
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install mhi
You can use mhi like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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