z3 | Backup your ZFS snapshots to S3 | Continuous Backup library
kandi X-RAY | z3 Summary
kandi X-RAY | z3 Summary
Backup your ZFS snapshots to S3.
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Top functions reviewed by kandi - BETA
- Backup a backup
- Backup a snapshot
- Create a pipe that runs cmd1 and cmd2
- Run a shell command
- Lists backups for a given bucket
- Calculate the widths of a line
- List all S3 Snapshots
- Prepare a summary line
- Synchronize two snapshots
- Sends snapshots to remote host
- Pull out and send snapshots
- Prepare and send command and recv
- Restore a snapshot
- Restore the specified snapshot
- Generate the decompress command
- Parse command line arguments
- Get the configuration
- Return a dictionary of S3Snapshot objects
- Wrapper for pipe
- Determine the pair of snapshots to send to the destination
z3 Key Features
z3 Examples and Code Snippets
Lines of Code : 30License : Strong Copyleft (CC BY-SA 4.0)
Copydv/dt = a(x)
lambda t, xv: np.concantenate([xv[2:], dvdt(xv[:2]) ])
z_1 = 0.5*exp(2*pi*i*t), z_2 = -z_1 ==> z_1-z_2=2*z_1, abs(z_1-z_2)=1
z_1'' = -GM * (z_1-z_2)/abs(z_1-z_2)^3
-0.5 Graph X Kth Operation on Graph X Graph Z3 Kth Operation on Graph Z3
0 [0] [0] [0] [0]
1 0 [] 1 []
2 1 [1] foo = expr1
if cond:
foo = expr2
foo0 = expr1
foo1 = If(cond, expr2, foo0)
>>> import itertools
>>> list(itertools.chain(*[[1,2,3],[4,5,6],[7,8,9]]))
[1, 2, 3, 4, 5, 6, 7, 8, 9]
from z3 import *
s = Solver()
Buckets = [ 3, 2, 5, 1, 4]
B_Weights = [7.3, 5.7, 4.25, 3.77, 6.02]
pick = 3
X = [Int('B%d' % b) for b in range (pick)]
s.add(Distinct(X))
total_weight = 0
for p in range(pick):
s.add(Orfrom z3 import *
R = 3
H = 4
Dest = [[2,3,4], [0,3,2,5], [1,4,5], [1,4,2], [3,1], [2,3,1]]
s = Solver()
T = [[Int('r%d_t%d' % (k,t)) for k in range (R)] for t in range (H)]
# Symbolically walk over a list, grabbing the ith element of X = Array('x', IntOrCT, IntOrCT)
print(Store(X, IntV(0), IntV(4)))
Store(x, IntV(0), IntV(4))
with open('path/snip.txt', 'r') as f_input, open('path/snip_output.txt', 'w') as f_output:
for line in f_input:
xyz = line.split()
x, y, z = xyz[0:3], xyz[3:6], xyz[6:9]
for triple in zip(x, y, z):
fn = 3
values = []
with open("log.txt") as f, open("output.txt", 'w') as g:
for line in f:
lst = line.rstrip().split()
for i in zip(*[lst[i:i + n] for i in range(0, len(lst), n)]):
print(*i, file=g)
for la, z2, z3 in zip(layers, lz2, lz3):
# first row
ABD[0][0] += la.Q̅11 * la.thickness # Hyer:1998, p. 290
ABD[0][1] += la.Q̅12 * la.thickness
ABD[0][2] += la.Q̅16 * la.thickness
ABD[0][3] += Community Discussions
Trending Discussions on z3
QUESTION
I have created a list whose elements are themselves a list of matrices. I want to be able to extract the vectors of observations for each variable
...ANSWER
Answered 2022-Feb-13 at 14:13Here you have a list of matrix with scenario in row and n columns.
QUESTION
I have a dataframe like:
...ANSWER
Answered 2022-Feb-13 at 12:11You could use groupby+agg:
QUESTION
In Z3 (Python) is there any way to 'bias' the SAT search towards a 'criteria'?
A case example: I would like Z3 to obtain a model, but not any model: if possible, give me a model that has a great amount of negated literals.
Thus, for instance, if we have to search A or B a possible model is [A = True, B = True], but I would rather have received the model [A = True, B = False] or the model [A = False, B = True], since they have more False assignments.
Of course, I guess the 'criteria' must be much more concrete (say, if possible: I prefer models with the half of literals to False ), but I think the idea is understandable.
I do not care whether the method is native or not. Any help?
...ANSWER
Answered 2022-Jan-19 at 13:56Z3py features an optimizing solver Optimize. This has a method add_soft with the following description:
Add soft constraint with optional weight and optional identifier. If no weight is supplied, then the penalty for violating the soft constraint is 1. Soft constraints are grouped by identifiers. Soft constraints that are added without identifiers are grouped by default.
A small example can be found here:
The Optimize context provides three main extensions to satisfiability checking:
QUESTION
I have a set of equations (z1) x+y+z=6, (z2) x+2y+2z=9 and (z3) x+3y+4z=13 and would like to plot the planes using plotly.
Method1: using mesh3d
...ANSWER
Answered 2022-Jan-17 at 02:29When x <- seq(from=-10, to=10, by=1); y<-seq(from=-10, to=10, by=1), x+y+z=6 is not plane but line.
You need to prepare more data points.
QUESTION
In Z3 (Python), imagine I get a model with the following shape:
[c_0 = True, c_3 = False, c_1 = False, c_2 = False]
How can I order the variables, so that the assignment is alphabetically ordered?
[c_0 = True, c_1 = False, c_2 = False, c_3 = False]How can I access any element of the model? I mean, if I do:
ANSWER
Answered 2021-Dec-30 at 17:02If you want to sort the model by its keys, you have to convert it to a different data-structure. (This really doesn't have much to do with z3, but rather how dictionaries are internally done.) What you tried is almost there, you just need to make sure to keep both the variable and the value. Here's an example:
QUESTION
I am trying to crack the problem of finding the player(s) with the longest streak of winning using Python's 3.2. I am only able to work out an unscalable solution, but I could not come up with a better one yet. Can anyone please help me with a better solution? Also, I am curious how to adapt such solution to output the player(s) with the longest winning streak per month or year?
Below is the sample dataframe players_results
ANSWER
Answered 2021-Dec-27 at 07:57Filter groups crated by cumulative sums with compare not equal W with SeriesGroupBy.value_counts and then get max value with player_id by Series.agg with Series.idxmax and max:
QUESTION
I have a question about a vectorized operation with logical vectors. In my problem, there are two vectors: main and secondary. They're both of the same length. I want to replace some elements in the main vector to NA, based on insights I gather from the secondary vector.
- The main vector is comprised of
TRUEandFALSEthat can appear in any random order. - The secondary vector is either:
- a sequence of
TRUEthen a sequence ofFALSEwith/withoutNAas the last element; or - all
TRUE; or - all
FALSE; or - all
FALSEwith last element asNA; or - all
TRUEwith last element asNA
- a sequence of
I'll provide several examples below and explain the desired algorithm.
A - The most common case
replace x values with NA for positions that are FALSE in y
ANSWER
Answered 2021-Dec-27 at 12:07This seems to work as expected:
QUESTION
I'm trying to parse and translate a string to its equivalent z3 form.
...ANSWER
Answered 2021-Dec-22 at 01:35Where's the definition of parse_expr_to_z3 coming from? It's definitely not something that comes with z3 itself, so you must be getting it from some other third-party, or perhaps you wrote it yourself. Without knowing how it's defined, it's impossible for anyone on stack-overflow to give you any guidance.
In any case, as you suspected its results are not something you can feed back to z3. It fails precisely because what you can add to the solver must be constraints, i.e., expressions of type Bool in z3. Clearly, none of those constituents have that type.
So, long story short, this parse_expr_to_z3 doesn't seem to be designed to do what you intended. Contact its developer for further details on what the intended use case is.
If you're trying to load assertions from a string to z3, then you can do that using the so called SMTLib format. Something like:
QUESTION
I have a Python function that takes a real number and returns a string, e.g.
...ANSWER
Answered 2021-Dec-13 at 21:01There's no out-of-the box way to do this in z3, unless you're willing to modify the definition of fun so z3 can understand it. Like this:
QUESTION
I'm trying to learn Z3 and the following example baffles me:
...ANSWER
Answered 2021-Dec-09 at 17:40Long story short, z3 (or SMT solvers in general) cannot deal with non-linear constraints like this. Exponentiation/Logs etc are difficult to deal with, and there are no decision procedures for them over the integers. Even over reals they are difficult to handle. That is, the solver will apply some heuristics, which may or may not work. But for these sorts of constraints, SMT solvers are just not the right tool.
For an earlier answer on non-linear arithmetic in z3, see this answer: https://stackoverflow.com/a/13898524/936310
Here're some more details if you are interested. First, there is no power-operator for integers in SMTLib or z3. If you look at the generated program, you'll see that it's actually over real values:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install z3
You can use z3 like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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