screenshare | Share screen in local network | File Sharing library
kandi X-RAY | screenshare Summary
kandi X-RAY | screenshare Summary
For some reasons, I wanted to share my computer screen to other computers in the same local network (LAN or WLAN). I could not find an easy way to do it. All free and pricey screen sharing services need the computers in the same local network to connect to the Internet. They incur tremendous network traffic on my Internet connection. So, I created this small screen sharing tool in Python. All computers in the same local network only need local network connections for screen sharing. Now, I have zero Internet access concerns while I share my screen to all other computers in my network. In short, the computer to share screen runs this Python script that captures screenshots periodically and hosts screenshots as a streaming web service. Other computers then browse the screenshots with any web browser. Of course, if you want to share your screen on the Internet, all you need to do is offering this service on the Internet as any other regular services. Security reminder Do not run this service if you do not need to share screen.
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Top functions reviewed by kandi - BETA
- Login .
- Implementation of grab .
- Initialize the screen .
- Initialize login .
- Generate screen buffer
- Handler for screenlive .
screenshare Key Features
screenshare Examples and Code Snippets
Community Discussions
Trending Discussions on screenshare
QUESTION
I am using fetch in a NodeJS application. Technically, I have a ReactJS front-end calling the NodeJS backend (as a proxy), and then the proxy calls out to backend services on a different domain.
However, from logging errors from consumers (I haven't been able to reproduce this issue myself) I see that a lot of these proxy calls (using fetch) throw an error that just says Network Request Failed, which is of no help. Some context:
- This only occurs on a subset of all total calls (lets say 5% of traffic)
- Users that encounter this error can often make the same call again some time later (next couple minutes/hours/days) and it will go through
- From Application Insights, I can see no correlation between browsers, locations, etc
- Calls often return fast, like < 100 ms
- All calls are HTTPS, non are HTTP
- We have a fetch polyfill from
fetch-ponyfillthat will take over iffetchis not available (Internet Explorer). I did test this package itself and the calls went through fine. I also mentioned that this error does occur on browsers that do supportfetch, so I don't think this is the error. - Fetch settings for all requests
- Method is set per request, but I've seen it fail on different types (GET, POST, etc)
- Mode is set to 'same-origin'. I thought this was odd, since we were sending a request from one domain to another, but I tried to set it differently and it didn't affect anything. Also, why would some requests work for some, but not for others?
- Body is set per request, based on the data being sent.
- Headers is usually just
AcceptandContent-Type, both set to JSON.
I have tried researching this topic before, but most posts I found referenced React native applications running on iOS, where you have to set some security permissions in the plist file to allow HTTP requests or something to do with transport security.
I have implement logging specific points for the data in Application Insights, and I can see that fetch() was called, but then() was never reached; it went straight to the .catch(). So it's not even reaching code that parses the request, because apparently no request came back (we then parse the JSON response and call other functions, but like I said, it doesn't even reach this point).
Which is also odd, since the request never comes back, but it fails (often) within 100 ms.
My suspicions:
- Some consumers have some sort of add-on for there browser that is messing with the request. Although, I run with uBlock Origin and HTTPS Everywhere and I have not seen this error. I'm not sure what else could be modifying requests that would cause it to immediately fail.
- The call goes through, which then reaches an Azure Application Gateway, which might fail for some reason (too many connected clients, not enough ports, etc) and returns a response that immediately fails the
fetchcall without running the.then()on the response.
For #2, I remember I had traced a network call that failed and returned Network Request Failed: Made it through the proxy -> made it through the Application Gateway -> hit the backend services -> backend services sent a response. I am currently requesting access to backend service logs in order to verify this on some more recent calls (last time I did this, I did it through a screenshare with a backend developer), and hopefully clear up the path back to the client (the ReactJS application). I do remember though that it made it to the backend services successfully.
So I'm honestly not sure what's going on here. Does anyone have any insight?
...ANSWER
Answered 2022-Jan-25 at 15:48Based on your excellent description and detective work, it's clear that the problem is between your Node app and the other domain. The other domain is throwing an error and your proxy has no choice but to say that there's an error on the server. That's why it's always throwing a 500-series error, the Network Request Failed error that you're seeing.
It's an intermittent problem, so the error is inconsistent. It's a waste of your time to continue to look at the browser because the problem will have been created beyond that, either in your proxy translating that request or on the remote server. You have to find that error.
Here's what I'd do...
Implement brute-force logging in your Node app. You can use Bunyan, or Winston or just require(fs) and write out to some file when an error occurs. Then look at the results. Only log it out when the response code from the other server is in the 400 or 500 ranges. Log the request object and the response object.
Something like this with Bunyan:
QUESTION
First off, I'm trying to do something like screenshare, I'm confronting an error. I tried to send the image row by row than I figured out that it could work only in LAN since the connection speed was far better. Then I transmitted exclusively each pixel and constructed the array on my own which would be pretty slow. Here is the code: Server side:
...ANSWER
Answered 2021-Aug-12 at 11:49You need to pass the new shape as tuple instead for reshape, eg. arr.reshape((y,x,3)). You might also get another error if OpenCV expects different data type (8 bits per channel, unsigned) than what it got from your program (32 bit signed integer), see documentation for cvtColor(). You can specify the data type when you create the array np.array(..., dtype=np.uint8).
Regarding performance, in Python for loops over large amounts of data can be slow and often you can make your code significantly faster if you can avoid the loop and use library routine instead. Also, you should read and write larger chunks with send() and recv(). If you are not familiar with socket programming, you should at minimum check out the python documentation Socket Programming HOWTO. You eliminate the loops over the image data by directly interpreting the data as bytes. The socket code follows the examples in linked documentation page.
QUESTION
I am new to RTCPeerConnection (WEbRTC), so please bear with me.
So far I am able to get to the point where I can replace tracks on the run by switching camera or screen sharing in my app. But I noticed it in 2 browser tabs that newly replaced track stream is captured in partner/remote peer only, not on initiator's tab. It just keep showing old stream even though stream has been replaced.
It should've been nice if initiator can also see what he/she is sharing. I tried but no luck so far. Looking for some assistance.
My code looks like:
...ANSWER
Answered 2021-Jul-27 at 18:07By design replaceTrack replaces the stream on the RTCPeerConnection. This does not affect the local video object. Reset the srcObject on the local video element to change it.
QUESTION
I would like to return a response code of 400 to the client after throwing an error in my Lambda function. (via REST API - GET)
Here is the response from the Lambda function:
...ANSWER
Answered 2021-May-06 at 04:30For anyone coming across the same problem in the future. I have found out the following 2 things:
After trying again to set
.*400.*a little later it worked fine. Of course, this may not be a good idea, because if you return any results, that contain 400 anywhere in their response, they could incorrectly trigger a 400 HTTP response.The workaround I found was to use
.*Invalid Input.*. Since it is not expected that regular results returned from the API would contain this phrase, this should work reliably.
QUESTION
livecode is a R package for broadcasting code for live code demonstrations. I would like to use it for teaching R in online classrooms. The package can be installed from github and runs excellent on my computer and the result is very promising. Once installed from github:
ANSWER
Answered 2021-Apr-23 at 13:08I contacted the package author and he suggested to follow this blogpost:
It suggests to use ngrok, a service that provides tunnels to localhost. This acutally worked for me for some seconds, killing my livecode package in the next moment. At the moment, I can no longer use livecode not even as a localhost. I assume this error may just be my fault. The blogpost provides an easy answer to my question.
QUESTION
We have built a front-end with React and a back-end with Django Rest Frameworks and channels. We are using Heroku Redis as our Redis provider. Our users connect to Channels via a ReconnectingWebSocket.
We are using Python 3.6 and Channels 2.4
The issue is that our API calls are attempting to pass info to the sockets and they're not always making it to the consumer. I logged the steps of the call out via prints, printed the channel_name it's about to attempt to send it to and confirm it's what was returned to the user on connect, but the prints in the consumer don't get called meaning the message never gets sent to the user.
If I increase the number dynos to more or less a 1-1 with the users connected to sockets then it seems to solve the problem (or at least makes it much more reliable). From my understanding, 1 dyno should be able to handle many socket connections. Is there a reason that my consumer is not receiving the signals? Is there a reason scaling up the number of dynos resolved the problem?
On connect, I have the user join a group called "u_{their id}" to allow for potentially sending the signals to multiple computers logged in as the same user. I have tried sending the message through their channel_name directly and through that group, and when messages aren't going through neither seem to go through. the prints verify the channel_names are correct and the consumer still doesn't receive the messages. There doesn't seem to be any errors occuring. It may not work, then I'll refresh the recipient and it'll work, then I'll refresh the recipient again and it's back to not working.
The socket connection is certainly alive - I made a simple function on the front end that pings the socket and when I do it (even if the consumer isn't getting signals from API calls), it responds.
I also notice that if I restart my dynos, when they load up and the sockets reconnect, the first user has signals working through API calls for a short time then they start not coming through again. Also, if I don't use the sockets for a while then refresh they also seem to start working briefly again.
Procfile
...ANSWER
Answered 2021-Mar-18 at 20:10The issue ended up being the Redis. I converted from channels-redis to channels-rabbitmq and all of my issues went away. I don't know if it was with my Redis provider or with channels-redis, but simply changing the backend resolved all issues.
QUESTION
I am trying to create a video conference web app using peer/getUserMedia.
Currently, when I send the unique ID to the video conference, I am able to hear/see anyone who joins my session.
However, only the first person who joins my session can communicate/see me.
I want to make it so the other users can see/hear every user thats in the video conference too.
So far this is what I have working so far. Also the code that is currently written, whenever a new user joins, my video gets added again so I see two videos of myself (if im the host), but that will be an easy fix for me
...ANSWER
Answered 2020-Oct-30 at 16:12I think you will need to create a "mesh". So with 3 peers, each user(peer) sets up two connections, one to each of the other two users. At each client's end, there are two entirely different connections.
The user @daGrevis asked this question on the PeerJs GitHub. Ultimately this is the implementation they used for a multi-peer chat that might help:
QUESTION
I am using dolby.io
Till now I have implemented join conference, leave conference, start and stop video, start and stop recording, start and stop screen sharing. What I am facing issue is about multiple conference. I want to implement multiple conferences with unique conference IDs so that every user specified for relevant conference should join its own. I am not getting any idea from its official documentation.
here is my code
...ANSWER
Answered 2020-Aug-25 at 16:19When you call create() a new conference id is generated which is a guid specific for your account. You can call get_id() to find it. You can also specify an alias to help for readability when there may be multiple conferences active at any given time.
If you want to have multiple conferences, you should call create() multiple times. That is, the expectation is the typical app initializes only a single conference but there are multiple running instances each having its own conference and/or to invite others to an existing conference. For webapps, that may be a separate user session rather than a separate deployed mobile application. You may want to do some book keeping for what ids are generated for each user in your own services.
You may be looking for all of the conferences that are active on an account at any given time while testing or monitoring your deployed apps. You can use the Monitor API getConferences to get that list.
If you have additional questions, it is probably best to use Dolby.io Support for more personal answers and guidance.
QUESTION
I am a beginner at node.js and need to host an application that I didn't personally write on an azure server for some testing. The site runs fine locally hosted, as well as hosted using ngrok. Yet, when I host it on azure, I get the following error:
...ANSWER
Answered 2020-Aug-24 at 11:34First, make sure what services you use, AWS or Azure Web App Services ?
Whatever services you use, I recommand you use git to deploy your web app.
You just make sure your web app can run successfully in local. And the port you use like app.set('port', process.env.PORT || 3000); or const port = process.env.PORT || 3000. Which means you can success run in local with 3000 port.
For more details, you can see my answer in another post.
You can refer to the way of troubleshooting when deploy web app by Action. Hope my answer can help you.
QUESTION
I recently got a small 300mm bed CNC Machine that has it's issues, which isn't really relevant, but to fix those issues I need to ask my friend. He has quite a lot of experience working with CNC Machines, but even when I screenshared the GRBL Software, he couldn't fix some problems that he said should be a simple fix, hence, the node.js app. I would like to connect a Raspberry Pi up to the CNC Driver board, host a server on Heroku, and have him connect to the server. The server would then pick up his input, translate it into GCode, and push it to the Raspberry Pi (which would send it to the driver board). I know how to set up the server, even code it so that he can press a button and it translates to GCode, but my question is, how could the Raspberry Pi get the Node equivalent of a message telling it the GCode the user wants to push? I have some experience with Node.js and have made a Chat Application, but this seems a little different. Thanks in advance.
...ANSWER
Answered 2020-Aug-12 at 14:14I believe all the answers you'll need will be in this video
If you have issues with any of that, then we'll have a good reference point. Best of luck.
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Vulnerabilities
No vulnerabilities reported
Install screenshare
pip install Flask-Bootstrap pyscreenshot
In a directory, run "git clone https://gitlab.com/qijungu/screenshare.git". You will have a new directory "screenshare" with code inside.
To start the screen sharing service, run "python screenshare.py [port]". The default service port is 18331. Example commands are below. # host screenshots on port 18331 python screenshare.py # host screenshots on port 80 python screenshare.py 80
On other computers, open a web browser and browse "http://serverip:port". For example, if the server ip is 192.168.0.101 and the service port is 18331, then the URL to browse is "http://192.168.0.101:18331".
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