password-checker | it 's a python gui program to check password strength

by rubenshibu Python Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(2)Vulnerabilities Install Support

kandi X-RAY | password-checker Summary

password-checker is a Python library. password-checker has no bugs, it has no vulnerabilities and it has low support. However password-checker build file is not available. You can download it from GitHub.

it is a password strength checker. Tkinter is user for GUI.

Support

Quality

Security

License

Reuse

Support

password-checker has a low active ecosystem.

It has 2 star(s) with 1 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

password-checker has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of password-checker is current.

Quality

password-checker has 0 bugs and 0 code smells.

Security

password-checker has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

password-checker code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

password-checker does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

password-checker releases are not available. You will need to build from source code and install.

password-checker has no build file. You will be need to create the build yourself to build the component from source.

It has 40 lines of code, 1 functions and 1 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed password-checker and discovered the below as its top functions. This is intended to give you an instant insight into password-checker implemented functionality, and help decide if they suit your requirements.

check the password

Get all kandi verified functions for this library.

password-checker Key Features

No Key Features are available at this moment for password-checker.

password-checker Examples and Code Snippets

No Code Snippets are available at this moment for password-checker.

Community Discussions

Trending Discussions on password-checker

Why should "aaaaAAAAAA000000123456"take 5 steps and not 6

Checking for a strong password fails for a case it shouldn't

QUESTION

Why should "aaaaAAAAAA000000123456"take 5 steps and not 6

Asked 2021-Dec-23 at 06:17

I was doing this problem on leetcode: https://leetcode.com/problems/strong-password-checker/ and I came across an edge case where "aaaaAAAAAA000000123456" was expected to take 5 steps to become a good password, according to the somewhat vague description:

deleting a character takes one step,
adding a character takes one step,
replacing a character takes one step.

The max allowed number of characters is 20 in a "strong" password, and "aaaaAAAAAA000000123456" has 22 characters. Repeating 3s like "aaa" or "OOO" are considered insecure, so to make a password secure, you'd remove, replace or add a new char to one of the characters in the repeating 3s. You also have to make sure there are capital letters, small letters, and numbers in the password to be truly secure.

According to my logic, "aaaaAAAAAA000000123456" or "aaa"+"a" +"AAA"+"AAA"+"000"+"000"+"123456" (noting the repeating 3s) should take 6 steps to become "secure", not 5:

Step 1: the string is 22 characters, so remove a char from one repeating 3 making; "aa"+"a"+"AAA"+"AAA"+"000"+"000"+"123456"

Step 2: it's now 21 chars, so remove another repeating 3 char; "aa"+"AAA"+"AAA"+"000"+"000"+"123456"

Step 3: (now 20 chars) replace a repeating 3 char; "aa"+"A1A"+"AAA"+"000"+"000"+"123456"

Step 4: replace another repeating 3 (I have to remove all of them); "aa"+"A1A"+"A2A"+"000"+"000"+"123456"

Step 5: replace another repeating 3; "aa"+"A1A"+"A2A"+"030"+"000"+"123456"

Step 6: remove the last repeating 3; "aa"+"A1A"+"A2A"+"030"+"040"+"123456"

Why should this take 5 steps and not 6?

I don't think it's necessary to add my code for this.

...

ANSWER

Answered 2021-Dec-23 at 00:16

aaaaAAAAAA000000123456
delete A
delete 0
aaaaAAAAA00000123456
replace a
replace A
replace 0
aazaAAzAA00z00123456

Source https://stackoverflow.com/questions/70456271

QUESTION

Checking for a strong password fails for a case it shouldn't

Asked 2021-Apr-19 at 09:20

I am working through Leetcode problem 420. Strong Password Checker. This is the problem statement:

A password is considered strong if the below conditions are all met:

It has at least 6 characters and at most 20 characters.

It contains at least one lowercase letter, at least one uppercase letter, and at least one digit.

It does not contain three repeating characters in a row (i.e., "...aaa..." is weak, but "...aa...a..." is strong, assuming other conditions are met).

Given a string password, return the minimum number of steps required to make password strong. if password is already strong, return 0.

In one step, you can:

Insert one character to password,

Delete one character from password, or

Replace one character of password with another character.

Example 1: ...

ANSWER

Answered 2021-Apr-19 at 09:19

It requires only one step which resolves two problems:

Source https://stackoverflow.com/questions/67158503

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install password-checker

You can download it from GitHub.
You can use password-checker like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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