Lasso | implementation Lasso with Coordinate Descent | Machine Learning library

 by   satopirka Python Version: Current License: MIT

kandi X-RAY | Lasso Summary

kandi X-RAY | Lasso Summary

Lasso is a Python library typically used in Artificial Intelligence, Machine Learning applications. Lasso has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However Lasso build file is not available. You can download it from GitHub.

This is implementation of Lasso. See the following blog entries written in Japanese for details of algorithm.
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            kandi-support Support

              Lasso has a low active ecosystem.
              It has 51 star(s) with 21 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              Lasso has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Lasso is current.

            kandi-Quality Quality

              Lasso has 0 bugs and 0 code smells.

            kandi-Security Security

              Lasso has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Lasso code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Lasso is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Lasso releases are not available. You will need to build from source code and install.
              Lasso has no build file. You will be need to create the build yourself to build the component from source.
              Lasso saves you 52 person hours of effort in developing the same functionality from scratch.
              It has 137 lines of code, 7 functions and 2 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed Lasso and discovered the below as its top functions. This is intended to give you an instant insight into Lasso implemented functionality, and help decide if they suit your requirements.
            • Compute the soft thresholding
            • Soft thresholding operator
            • Fit the covariance model
            Get all kandi verified functions for this library.

            Lasso Key Features

            No Key Features are available at this moment for Lasso.

            Lasso Examples and Code Snippets

            No Code Snippets are available at this moment for Lasso.

            Community Discussions

            QUESTION

            Automate Machine Learning process with R on multiple datasets
            Asked 2022-Jan-10 at 17:18

            I have multiple datasets with different lengths. I want to apply a correlation function to delete correlated variables with 98%. How can I use a loop to apply a correlation function on multiple datasets in the same time and store the variables selected in new dataframes?

            How can I also use lasso regression on multiple datasets, also using loop functions? Thank you

            ...

            ANSWER

            Answered 2022-Jan-10 at 15:52

            Here's one way (of several) to do this:

            Source https://stackoverflow.com/questions/70577006

            QUESTION

            Custom Transformer to add additional column
            Asked 2022-Jan-09 at 07:22

            I am trying to replicate my lambda function into my pipeline

            ...

            ANSWER

            Answered 2022-Jan-09 at 07:22

            The first issue is actually independent from the ColumnTransformer usage and it is due to a bug in method transform's implementation in your HealthyAttributeAdder class.

            In order to get a consistent result you should modify line

            Source https://stackoverflow.com/questions/70638171

            QUESTION

            Updating Python sklearn Lasso(normalize=True) to Use Pipeline
            Asked 2021-Dec-28 at 10:34

            I am new to Python. I am trying to practice basic regularization by following along with a DataCamp exercise using this CSV: https://assets.datacamp.com/production/repositories/628/datasets/a7e65287ebb197b1267b5042955f27502ec65f31/gm_2008_region.csv

            ...

            ANSWER

            Answered 2021-Nov-24 at 09:45

            When you set Lasso(..normalize=True) the normalization is different from that in StandardScaler(). It divides by the l2-norm instead of the standard deviation. If you read the help page:

            normalize bool, default=False This parameter is ignored when fit_intercept is set to False. If True, the regressors X will be normalized before regression by subtracting the mean and dividing by the l2-norm. If you wish to standardize, please use StandardScaler before calling fit on an estimator with normalize=False.

            Deprecated since version 1.0: normalize was deprecated in version 1.0 and will be removed in 1.2.

            It is also touched upon in this post. Since it will be deprecated, I think it's better to just use the StandardScaler normalization. You can see it's reproducible as long as you scale it in the same way:

            Source https://stackoverflow.com/questions/70085731

            QUESTION

            logistic regression and GridSearchCV using python sklearn
            Asked 2021-Dec-10 at 14:14

            I am trying code from this page. I ran up to the part LR (tf-idf) and got the similar results

            After that I decided to try GridSearchCV. My questions below:

            1)

            ...

            ANSWER

            Answered 2021-Dec-09 at 23:12

            You end up with the error with precision because some of your penalization is too strong for this model, if you check the results, you get 0 for f1 score when C = 0.001 and C = 0.01

            Source https://stackoverflow.com/questions/70264157

            QUESTION

            Meaning of `penalty` and `loss` in LinearSVC
            Asked 2021-Nov-18 at 18:08

            Anti-closing preamble: I have read the question "difference between penalty and loss parameters in Sklearn LinearSVC library" but I find the answer there not to be specific enough. Therefore, I’m reformulating the question:

            I am familiar with SVM theory and I’m experimenting with LinearSVC class in Python. However, the documentation is not quite clear regarding the meaning of penalty and loss parameters. I recon that loss refers to the penalty for points violating the margin (usually denoted by the Greek letter xi or zeta in the objective function), while penalty is the norm of the vector determining the class boundary, usually denoted by w. Can anyone confirm or deny this?

            If my guess is right, then penalty = 'l1' would lead to minimisation of the L1-norm of the vector w, like in LASSO regression. How does this relate to the maximum-margin idea of the SVM? Can anyone point me to a publication regarding this question? In the original paper describing LIBLINEAR I could not find any reference to L1 penalty.

            Also, if my guess is right, why doesn't LinearSVC support the combination of penalty='l2' and loss='hinge' (the standard combination in SVC) when dual=False? When trying it, I get the

            ValueError: Unsupported set of arguments

            ...

            ANSWER

            Answered 2021-Nov-18 at 18:08

            Though very late, I'll try to give my answer. According to the doc, here's the considered primal optimization problem for LinearSVC: ,phi being the Identity matrix, given that LinearSVC only solves linear problems.

            Effectively, this is just one of the possible problems that LinearSVC admits (it is the L2-regularized, L1-loss in the terms of the LIBLINEAR paper) and not the default one (which is the L2-regularized, L2-loss). The LIBLINEAR paper gives a more general formulation for what concerns what's referred to as loss in Chapter 2, then it further elaborates also on what's referred to as penalty within the Appendix (A2+A4).

            Basically, it states that LIBLINEAR is meant to solve the following unconstrained optimization pb with different loss functions xi(w;x,y) (which are hinge and squared_hinge); the default setting of the model in LIBLINEAR does not consider the bias term, that's why you won't see any reference to b from now on (there are many posts on SO on this).

            • , hinge or L1-loss
            • , squared_hinge or L2-loss.

            For what concerns the penalty, basically this represents the norm of the vector w used. The appendix elaborates on the different problems:

            • L2-regularized, L1-loss (penalty='l2', loss='hinge'):
            • L2-regularized, L2-loss (penalty='l2', loss='squared_hinge'), default in LinearSVC:
            • L1-regularized, L2-loss (penalty='l1', loss='squared_hinge'):

            Instead, as stated within the documentation, LinearSVC does not support the combination of penalty='l1' and loss='hinge'. As far as I see the paper does not specify why, but I found a possible answer here (within the answer by Arun Iyer).

            Eventually, effectively the combination of penalty='l2', loss='hinge', dual=False is not supported as specified in here (it is just not implemented in LIBLINEAR) or here; not sure whether that's the case, but within the LIBLINEAR paper from Appendix B onwards it is specified the optimization pb that's solved (which in the case of L2-regularized, L1-loss seems to be the dual).

            For a theoretical discussion on SVC pbs in general, I found that chapter really useful; it shows how the minimization of the norm of w relates to the idea of the maximum-margin.

            Source https://stackoverflow.com/questions/68819288

            QUESTION

            How to add an L1 penalty to the loss function for Neural ODEs?
            Asked 2021-Nov-10 at 22:54

            I've been trying to fit a system of differential equations to some data I have and there are 18 parameters to fit, however ideally some of these parameters should be zero/go to zero. While googling this one thing I came across was building DE layers into neural networks, and I have found a few Github repos with Julia code examples, however I am new to both Julia and Neural ODEs. In particular, I have been modifying the code from this example:

            https://computationalmindset.com/en/neural-networks/experiments-with-neural-odes-in-julia.html

            Differences: I have a system of 3 DEs, not 2, I have 18 parameters, and I import two CSVs with data to fit that instead of generate a toy dataset to fit.

            My dilemma: while goolging I came across LASSO/L1 regularization and hope that by adding an L1 penalty to the cost function, that I can "zero out" some of the parameters. The problem is I don't understand how to modify the cost function to incorporate it. My loss function right now is just

            ...

            ANSWER

            Answered 2021-Nov-10 at 22:54

            I've been messing with this, and looking at some other NODE implementations (this one in particular) and have adjusted my cost function so that it is:

            Source https://stackoverflow.com/questions/69833351

            QUESTION

            glmnet caret in R - How to check binary logistic LASSO model performance without error?
            Asked 2021-Oct-18 at 19:32

            I'm trying to use R's caret and glmnet packages to run LASSO to determine the best predictors for a binary outcome of interest.

            I get all the way to checking the trained model's performance (pulling root mean squared error and R-squared values from the predictions), and I get the following error:

            Error in cor(obs, pred, use = ifelse(na.rm, "complete.obs", "everything")) : 'x' must be numeric

            Will anyone please help me figure out why my code is throwing this error? How can I successfully pull the RMSE and R^2 values?

            The example code below throws the same error. I'm including all my steps, so you can see how I'm thinking through the LASSO regression. If you want to skip to the end, the final chunk is the problem.

            ...

            ANSWER

            Answered 2021-Oct-18 at 19:32

            This happens just because RMSE and R-squared are meaningless for factor outcomes. You have to use caret::confusionMatrix or convert factor to integer (not a so good option in my opinion):

            Source https://stackoverflow.com/questions/69486882

            QUESTION

            Match both dicitonary key-values with pandas dataframe rows
            Asked 2021-Oct-15 at 12:58

            I can match each row with each diciotnary key but I am wondering if there's a way I can get the related value (string) in a different column as well.

            ...

            ANSWER

            Answered 2021-Oct-15 at 12:58

            Use DataFrame.stack with convert first level to column by reset_index, so possible join values in GroupBy.agg, for unique values in order is used dict.fromkeys trick:

            Source https://stackoverflow.com/questions/69584828

            QUESTION

            How to loop glm
            Asked 2021-Oct-13 at 16:28

            I want to loop ridge & lasso for 100 times to get 100 mse and mspe. My final goal is draw a boxplot to compare those 100 values. I made one regression model but I don't know how to repeat this model. How could I get the values and boxplots?

            ...

            ANSWER

            Answered 2021-Oct-04 at 08:11

            You can try the following:

            Source https://stackoverflow.com/questions/69431768

            QUESTION

            How to use BIC and AIC score for Lasso-GridSearchCV in sklearn?
            Asked 2021-Oct-05 at 16:34

            I want use AIC & BIC to select the parameter alpha for lasso. However sklearn only has LassoLarsIC to do this which does not accept sparse matrix and thus does not fit my case. As a result I decide to use GridSearchCV and create a customized scorer. Below is my try:

            ...

            ANSWER

            Answered 2021-Oct-05 at 16:34

            The output of make_scorer (and the expected form of a scoring method for a grid search) is a callable with signature estimator, X, y; you should skip make_scorer and define such a callable directly. Then you can use the estimator's fitted attribute coefs_ directly. (The greater_is_better=False option of make_scorer just negates the score, so you should probably define this alternate custom scorer as negative BIC.)

            Note however that in a GridSearchCV, you'll always be computing the score on the test folds, which deviates from the intention behind BIC.

            Source https://stackoverflow.com/questions/69454018

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            Lasso 2.2.1 and earlier does not properly check the return value from the OpenSSL DSA_verify function, which allows remote attackers to bypass validation of the certificate chain via a malformed SSL/TLS signature, a similar vulnerability to CVE-2008-5077.

            Install Lasso

            You can download it from GitHub.
            You can use Lasso like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            gh repo clone satopirka/Lasso

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