genpass | Generate secure , random and memorable passwords

 by   ssrathi Python Version: Current License: Unlicense

kandi X-RAY | genpass Summary

kandi X-RAY | genpass Summary

genpass is a Python library. genpass has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install genpass' or download it from GitHub, PyPI.

Includes various options to generate different combinations. Use "-h" to view all of them.
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            kandi-support Support

              genpass has a low active ecosystem.
              It has 13 star(s) with 0 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 0 have been closed. On average issues are closed in 1999 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of genpass is current.

            kandi-Quality Quality

              genpass has 0 bugs and 0 code smells.

            kandi-Security Security

              genpass has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              genpass code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              genpass is licensed under the Unlicense License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              genpass releases are not available. You will need to build from source code and install.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              genpass saves you 45 person hours of effort in developing the same functionality from scratch.
              It has 120 lines of code, 6 functions and 2 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed genpass and discovered the below as its top functions. This is intended to give you an instant insight into genpass implemented functionality, and help decide if they suit your requirements.
            • Generates a random password .
            • Print a list of passwords .
            • Generate passwords .
            • Generate a password .
            • Get a list of words from DEFAULT_WORD_FILE .
            • Return the content of the README . md file .
            Get all kandi verified functions for this library.

            genpass Key Features

            No Key Features are available at this moment for genpass.

            genpass Examples and Code Snippets

            No Code Snippets are available at this moment for genpass.

            Community Discussions

            QUESTION

            Function to generate random password in PLSQL
            Asked 2021-Nov-18 at 09:58

            Function to create random password Genpass(p integer, p uppercase p lowercase p special characters) return password varchar2; select Genpassword(2,2,1,2) It contain 2 numbers,2 uppercase characters ,special character like # and 2 numbers;

            ...

            ANSWER

            Answered 2021-Nov-18 at 09:58

            The Oracle DBMS_RANDOM.STRING functionality does not allow you to state you want special characters expressly. Also, when you use DBMS_RANDOM.STRING for each type of character, you end up with a series that always has the same structure (which might even be a security issue again).

            But if you do not want to have the same structure all the time, you would have to write something that would (in yet another random way) distribute the characters of your structured password.

            Another option is to use an example I adopted from an AskTom entry; you leverage the existing functionality and try until you have a result:

            Source https://stackoverflow.com/questions/70006103

            QUESTION

            Modify protected file with bash alias
            Asked 2021-Sep-17 at 12:10

            I have the following alias in my .bashrc file,

            ...

            ANSWER

            Answered 2021-Sep-17 at 12:10

            If your unprivileged user can alter the file, why do you store it with root permissions? This does not give you any benefit. Store the file with the user id of the user who needs to read and write it and stop using sudo.

            The problem in your solution is, that echo is run with root permissions. But the redirection is still done by the shell running the sudo. And that shell does not have root permissions.

            If you still want to keep your approach, you have to run tee -a by sudo. For this you have to put the sudo in the alias. But now it might be better to write a function instead of an alias.

            Source https://stackoverflow.com/questions/69221709

            QUESTION

            Mongoose/MongoDB not saving objects
            Asked 2020-Jun-29 at 00:37

            In my last commit, I have my POST route working perfectly, but after starting implementing PassportJS I'm not able to save new users anymore. I have been deleting the db and the collections in a couple of occasions mainly because I've been changing the structure of the schema, so I want to ask if any kind of corruption is possible, knowing that I always have been manipulating Mongo through MongoDB Compass.

            ...

            ANSWER

            Answered 2020-Jun-27 at 04:30

            It seems like you user is saved to the database, save won't return the inserted document

            Source https://stackoverflow.com/questions/62605612

            QUESTION

            Check password with 3 attempts, password is automatically generated
            Asked 2020-May-17 at 12:54
            #include 
            #include 
            #include 
            #include 
            #include 
            
            void genpass(int, int);
            void check(int, int, int);
            int main ()
            {
            srand(time(NULL));
            
            int i, c = 0, password, EnteredPassword;
            
            genpass(i, password);
            check(c, EnteredPassword, password);
            
            return 0;
            
            
            }
            
            
            void genpass (int i, int password)
            {
                FILE *pf;
                pf = fopen("sifra.txt", "w");
                fprintf(pf, "");
                for (i=0;i<4;i++){
                    password = ( rand()%10 );
                    fprintf(pf, "%d", password);
                }
            
            
                printf("\n New password has been generated \n");
                fclose(pf);
            
            }
            
            void check(int c, int EnteredPassword, int password)
            {
            
            
                printf("\n Enter your password: ");
            
                scanf("%d", &EnteredPassword);
            
                printf("\n You entered %d password \n", EnteredPassword);
            
                if(password == EnteredPassword)
                {
                    printf("\n Successfully logged in \n");
            
                }
            
                else
                {
                    printf("\n Password incorrect \n Please try again \n");
            
                    for ( c = 0; c < 3; c++)
            
                        {
                             printf("\n Enter your password: ");
            
                             scanf("%d", &EnteredPassword );
            
            
                              if(password == EnteredPassword)
                               {
                                    printf("\n Successfully logged in \n");
                                    break;
                               }
            
                        }
                }
            
            }
            
            ...

            ANSWER

            Answered 2020-May-17 at 11:33

            The way you pass password to genpass, it is only a local variable to genpass. It is a copy of password in main, whose value is indeterminate, because it wasn't initialized. Changing the local variable password will not affect the value of password in main. (And what is i for`?)

            You want to fill password, of course. There are basically two strategies.

            return the password

            Source https://stackoverflow.com/questions/61850904

            QUESTION

            I am developing an authentication program in python but I am having database problems
            Asked 2020-May-05 at 17:30

            I am developing a login system but im having trouble with the user and password storage part. I made a list and i outsourced it to a text file and it writes everything in it but every time i run the program again it erases everything it stored previously. Here is the code i wrote until now. Anything else i am doing wrong, please let me know, i am happy to get a more skilled person's opinion on this.

            ...

            ANSWER

            Answered 2020-May-05 at 17:29

            You open the files user.txt and pw.txt in write mode (the second parameter in the open function), which recreates the file each time, instead of append mode, which will allow you to append data to your files.

            Try:

            Source https://stackoverflow.com/questions/61619208

            QUESTION

            writing output from void into a .txt file
            Asked 2020-Mar-29 at 19:01

            I try to make a password generator that takes input from the user. When the user key in the details. The system will take the input & generate a password.

            ...

            ANSWER

            Answered 2020-Mar-29 at 18:30

            getPass() should return a String so the method should be of type String. On an unrelated note, your try-catch is likely catching an IndexOutOfBoundsException/NullPointerException that would indicate there is a problem with your logic. It's almost never a good idea to fail silently.

            Source https://stackoverflow.com/questions/60918906

            QUESTION

            Get list of file from directory
            Asked 2020-Mar-10 at 10:11

            I have simple app where I upload .pdf file then using qpdf to encrypt it.

            There is my 'put' route in express.

            ...

            ANSWER

            Answered 2020-Mar-10 at 10:11

            In order to share data between routes

            Source https://stackoverflow.com/questions/60615317

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install genpass

            You can install using 'pip install genpass' or download it from GitHub, PyPI.
            You can use genpass like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            CLONE
          • HTTPS

            https://github.com/ssrathi/genpass.git

          • CLI

            gh repo clone ssrathi/genpass

          • sshUrl

            git@github.com:ssrathi/genpass.git

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