brigitte | This is a mirror of http : //brigitte.io/steph/brigitte/
kandi X-RAY | brigitte Summary
kandi X-RAY | brigitte Summary
This is a mirror of http://brigitte.io/steph/brigitte/
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Top functions reviewed by kandi - BETA
- Return the contents of the tree
- Build a breadcrumb
- Parse a media blob
- Render a tree
- Execute a git command
- Lookup a repository by name
- Execute git command
- Execute a git command
- Get the last commit date
- Called when the repo settings has changed
- Overrides save method
- List of files that have changed
- Get line numbers from a diff
- Get the merged tree changes
- Check credentials
- Check if key exists
- Return a File object for the given path
- Returns a list of branches
- Return the repository object
- Deletes the repository with the given slug
- Try to parse a diff
- Render public profile
- Return a dict of all the files in the diff
- List of Tag objects
- Delete a repository
- Delete a key
brigitte Key Features
brigitte Examples and Code Snippets
Community Discussions
Trending Discussions on brigitte
QUESTION
I created a „.htaccess“ file to redirect the website visitors from an old page (example.com) to a new page (example.org). The challenge is that I want to redirect most old pages to a specific url address. As I read I can do it with the following code:
...ANSWER
Answered 2021-Mar-09 at 16:59QUESTION
I'm stuck with this recursion which doesn't work as I expect.
Where is my mistake?
...ANSWER
Answered 2020-Sep-24 at 21:07Let's do this interactively (in SWI Prolog) instead of in a script which prints the answers at the end using format/2
.
We want all possible ancestors of eve
in a list.
So we have to
- query the Prolog program for all possible solutions to the goal
ancestor(A,eve)
- and then collect them into a list
This is done using one of the predicates bagof/3
, setof/3
or findall/3
, which backtrack over answers to a goal and unify a variable with a list containing all the answers (with duplicate answers for bagof/3
, without duplicate answers for setof/3
, and with "no possible answer" yielding []
instead of failure for findall/3
).
So we just need to make sure the goal to find any ancestor is correct.
We can state that A
is an ancestor of C
if
A
is a parent ofC
orA
is a parent of someD
, andD
is an ancestor ofC
(Note: just 'if', not 'if an only if'. However, it is assumed there are no other ways in which A
could possibly be an ancestor of C
... a reasonable "closed world assumption")
The above formulation is well adapted to the search strategy of Prolog, which attempts to resolve a leftmost sub-goal in the body first:
QUESTION
EDIT : I've just compiled gprolog
from sources.
It works fine. The version 1.4.5 in the Debian repo is bugged.
It's my first program in GNU Prolog (gprolog) without any success. :-(
I found these exercises in a Prolog tutorial.
...ANSWER
Answered 2020-Sep-23 at 13:38It seems that invoked with a file name, gprolog
validates it but does not load its content into the interpreter. In order to load the file content you have to use the --consult-file
command line option:
QUESTION
I have a mysql table with 11 columns. I exported it to .csv with:
...ANSWER
Answered 2020-Sep-12 at 22:30Your parameters don't look right especially
escaped by ""
Please use these for csv, they work usually
QUESTION
I apologize in advance if my question is too basic. I have also tried to find answers in previous posts, but they are not exactly what I am looking for.
I am struggling with this exercise :
Write a program that analyzes all the elements of a word list one by one (for example example: ['Jean', 'Maximilien', 'Brigitte', 'Sonia', 'Jean-Pierre', 'Sandra']) for generate two new lists. One will contain words with less than 6 characters, the other is words of 6 characters or more.
...ANSWER
Answered 2020-Jun-28 at 09:49liste1 = ['Jean', 'Maximilien', 'Brigitte', 'Sonia', 'Jean-Pierre', 'Sandra']
moins6 = []
plus6 = []
for word in liste1:
if len(word) > 6:
moins6.append(word)
else: plus6.append(word)
print(moins6)
print(plus6)
QUESTION
I wrote a exam last week and had a really hard task to solve and didn't got the point. I had a .txt with a Text.
The Text is like this:
Der zerbrochne Krug, ein Lustspiel,
von Heinrich von Kleist.
Berlin. In der Realschulbuchhandlung. 1811.
[8] PERSONEN.
WALTER, Gerichtsrath. ADAM, Dorfrichter. LICHT, Schreiber. FRAU MARTHE RULL. EVE, ihre Tochter. VEIT TÜMPEL, ein Bauer. RUPRECHT, sein Sohn. FRAU BRIGITTE. EIN BEDIENTER, BÜTTEL, MÄGDE, etc.
Die Handlung spielt in einem niederländischen Dorfe bei Utrecht.
[9] Scene: Die Gerichtsstube. Erster Auftritt.
And i got the Main with this code:
...ANSWER
Answered 2020-Jun-10 at 12:38Try the below function :
QUESTION
I have a tsv file like this:
...ANSWER
Answered 2020-Apr-14 at 12:47This awk one-liner should help:
QUESTION
I want to update State variable on react, when i set it by default my map function work well. But now when i update my state variable with setState i have the response map is not a function here is my code.
...ANSWER
Answered 2019-Nov-26 at 23:44The trouble is that .map
is a method which can only be called on an array. When you are calling setState
in your case you are actually setting annonces
to be the return of array.push
which I am pretty sure is the length of the array, which is a number. A number is of course not an array which is why you no longer can call .map
.
What you want to do is set announces
to be a new array that contains the new value and the old values. You can use the spread operator for this and your code would look something like this.
QUESTION
In an exercise, I have an array with several items.
If each item has 6 or more than 6 characters, these items will go into the arrayList named list1
. The others items into the list2
.
I have tried this but my 2 arrayList are inaccurate.
...ANSWER
Answered 2019-Nov-11 at 20:09The source of your issue here is on the line if(tab.length() > 6){
.
What you're currently doing here is comparing the length of the String array tab
to 6. What you want to be doing is comparing each element of the String array tab
to 6.
For example, if(tab[i].length() > 6)
QUESTION
I have an assignment where I must use perfect hashing to hash names from an input array, with the number of names given.
This is my code:
Dictionary.h
...ANSWER
Answered 2019-Oct-30 at 02:34Your assertion that the program fails before reaching main
is false. In fact, it crashes here:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install brigitte
You can use brigitte like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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