strawberry | A GraphQL library for Python that leverages type annotations 🍓 | GraphQL library
kandi X-RAY | strawberry Summary
kandi X-RAY | strawberry Summary
Python GraphQL library based on dataclasses.
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Top functions reviewed by kandi - BETA
- Return a list of dataclass attributes .
- Get the fields of a given cls .
- Create a function from a resolver .
- Create an error type for a model .
- Execute the given query against the given schema .
- Return an HTTP response .
- Execute a request .
- Determine the depth of a node .
- Handle a subscribe message .
- Adds a static method to the class .
strawberry Key Features
strawberry Examples and Code Snippets
import strawberry
from strawberry_django_plus.optimizer import DjangoOptimizerExtension
schema = strawberry.Schema(
Query,
extensions=[
# other extensions...
DjangoOptimizerExtension,
]
)
# models.py
class Artist(models
pip install strawberry-sqlalchemy-mapper
# models.py
from sqlalchemy import Column, Integer, String
from sqlalchemy.ext.declarative import declarative_base
Base = declarative_base()
class Employee(Base):
__tablename__ = 'employee'
id = Col
# schema.py
from strawberry_django_plus import gql
from strawberry_django_plus.gql import relay
@gql.type
class Fruit(relay.Node):
name: str
def resolve_node(cls, node_id, info, required=False):
...
def resolve_nodes(cls, node_
Community Discussions
Trending Discussions on strawberry
QUESTION
Good Day everyone!
I need help with alternatives or a workaround for explode() in pandas 0.19.0 I have this csv files
...ANSWER
Answered 2022-Mar-29 at 08:22Convert ouput of function to Series
and use DataFrame.stack
:
QUESTION
This is part of my doubly linked list deque python code.
The 'appendleft' function written almost similar to the 'append' function is normally output. Why is the last 'append('apple')' code not output normally in the 'Group_of_append' function?
...ANSWER
Answered 2022-Mar-28 at 12:28Your appends work fine. Problem lies in your print_list
function which stops when p.next
is None
. Which means your last element will not be printed because its next is None
.
All in all, your logic for this list is very strange and could use a lot of rework, it would make finding mistakes like this one a lot easier for you. For example, this iterating through the whole list when appending even though you have both head and tail readily available in the deque
object.
QUESTION
I have two examples of foldLeft
that I cannot really grasp the logic.
First example:
...ANSWER
Answered 2022-Mar-27 at 21:07Does not
foldLeft
accumulate value that was earlier?
yes it does. It uses result of previous iteration and current element and produces new result (using the binary operator you have provided) so for the first example next steps are happening:
the start value of accumulator -
""
acc = ""
,curr = "Plain"
->" , Plain Donut "
acc = " , Plain Donut "
,curr = "Strawberry"
->" , Plain Donut , Strawberry Donut "
acc = " , Plain Donut , Strawberry Donut "
,curr = "Strawberry"
->" , Plain Donut , Strawberry Donut , Glazed Donut"
For the second example current value is simply ignored - i.e. multi
can be rewritten as def multi(acc:Int, curr:Int):Int = acc*10
where curr
is not actually used so foldLeft
simply multiplies starting value (1
) by 10 n
times where n
is number of elements in the sequence (i.e. (1 until 3).length
which is 2).
Why does it not take any input variables (num and num1)?
foldLeft
is a function which accepts a function. It accepts
a generic function which in turn accepts two parameters and returns result of the same type as the first parameter (op: (B, A) => B
, where B
is the the result type and A
is sequence element type). multi
matches this definition when B
== A
== Int
and is passed to the foldLeft
which will internally provide the input variables on the each step.
QUESTION
I cannot find anywhere how to convert a pandas dataframe to type datasets.dataset_dict.DatasetDict
, for optimal use in a BERT workflow with a huggingface model. Take these simple dataframes, for example.
ANSWER
Answered 2022-Mar-25 at 15:47One possibility is to first create two Datasets and then join them:
QUESTION
I'm still young to coding and cannot figure out better functions or results to some tasks by myself very often.
I have a question on tracking the original string after using str_extract_all
for a specific pattern.
Here is an example data called "fruit".
index Fruit 1 apple 2 banana 3 strawberry 4 pineapple 5 bell pepperI used str_extract_all(fruit, "(.)\\1")
to extract duplicated consonants, and get "pp", "rr", "pp", "ll", "pp".
Also tracked the original string (of those extracted results) by str_subset(fruit, "(.)\\1")
. Here's what I get.
However, I want to know where "each" extracted result is from. Therefore, using str_subset
cannot capture those results which are from the same string. The following dataframe is what I expect to gain.
I'm not sure if I explain my question clearly. Any feedbacks and ideas will be appreciate.
...ANSWER
Answered 2022-Mar-24 at 11:24Your code already did what you want. You just need to create an extra column to store the output of str_extract_all
, like the following:
Since str_extract_all()
returns a list, we'll need to unnest
the list to become rows.
The final line of the code is to create a consecutive index (since "banana" is gone, index 2 will also be gone).
QUESTION
Given the user table as follow:
...ANSWER
Answered 2022-Mar-13 at 14:30Here's one way:
QUESTION
In my hypothetical example, people order ice-cream at a stand and each time an order is placed, the month the order was made and the number of orders placed is recorded. Each row represents a unique person who placed the order. For each flavor of ice-cream, I am curious to know the cumulative orders placed over the various months. For instance if a total of 3 Vanilla orders were placed in April and 4 in May, the graph should show one data point at 3 for April and one at 7 for May.
The issue I am running into is each row is being plotted separately (so there would be 3 separate points at April as opposed to just 1).
My secondary issue is that my dates are not in chronological order on my graph. I thought converting the Month column to Date format would fix this but it doesn't seem to.
Here is my code below:
...ANSWER
Answered 2022-Mar-01 at 20:46In these situations, it's usually best to pre-compute your desired summary and send that to ggplot, rather than messing around with ggplot's summary functions. I've also added a geom_line()
for clarity.
QUESTION
I am new to Python, and I am trying to use Python to query a Microsoft SQL Server database. The data is returned in this format:
(('orange,apple,coconut',), ('lettuce,carrot,celery',), ('orange,lemon,strawberry',))
What I am trying to do is check to find a match, to see if some data from another data table exists in that data from SQL Server.
When I try to use the "in" to check, it does not work for me. I thought if I could convert the data (a tuple of tuples) into a list, then I could more easily search and match. But that doesn't work because there are some brackets around each list element. At least, that is the what I think because, if I manually recreate the list without the extra brackets, then I can search successfully.
I am wondering if there is a way to remove that extra bracket. Or, maybe there is a better approach. I have read several posts here and other articles, and so far, I have not found an approach.
Here is what I have tried. As you can see, the final one works, but that is what i have created manually.
...ANSWER
Answered 2022-Feb-26 at 08:49QUESTION
I'm trying to create an object in a certain structure from data that I have. From:
...ANSWER
Answered 2022-Feb-08 at 12:12Convert the object to pairs of [key, value]
, and map them to a new object using R.applySpec
. Use R.nth
to take the key or value from the pair. Use R.objOf
to nest the array under data
.
QUESTION
I'm trying to create a type that accepts any combination of certain values separated by spaces. The order doesn't matter. I can't define each combination using string literals because the number of acceptable values is very long. How can I achieve this?
...ANSWER
Answered 2022-Jan-06 at 21:07You have a BaseVals
type consisting of a union of single words:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
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Install strawberry
Create a file called app.py with the following code:. This will create a GraphQL schema defining a User type and a single query field user that will return a hardcoded user.
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