examples | Example on how to use Strawberry | Machine Learning library
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kandi X-RAY | examples Summary
Example on how to use Strawberry.
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QUESTION
This question is about two MAUI controls (Switch
and ListView
) - I'm asking about them both in the same question as I'm expecting the root cause of the problem to be the same for both controls. It's entirely possible that they're different problems that just share some common symptoms though. (CollectionView
has similar issues, but other confounding factors that make it trickier to demonstrate.)
I'm using 2-way data binding in my MAUI app: changes to the data can either come directly from the user, or from a background polling task that checks whether the canonical data has been changed elsewhere. The problem I'm facing is that changes to the view model are not visually propagated to the Switch.IsToggled
and ListView.SelectedItem
properties, even though the controls do raise events showing that they've "noticed" the property changes. Other controls (e.g. Label
and Checkbox
) are visually updated, indicating that the view model notification is working fine and the UI itself is generally healthy.
Build environment: Visual Studio 2022 17.2.0 preview 2.1
App environment: Android, either emulator "Pixel 5 - API 30" or a real Pixel 6
The sample code is all below, but the fundamental question is whether this a bug somewhere in my code (do I need to "tell" the controls to update themselves for some reason?) or possibly a bug in MAUI (in which case I should presumably report it)?
Sample codeThe sample code below can be added directly a "File new project" MAUI app (with a name of "MauiPlayground" to use the same namespaces), or it's all available from my demo code repo. Each example is independent of the other - you can try just one. (Then update App.cs
to set MainPage
to the right example.)
Both examples have a very simple situation: a control with two-way binding to a view-model, and a button that updates the view-model property (to simulate "the data has been modified elsewhere" in the real app). In both cases, the control remains unchanged visually.
Note that I've specified {Binding ..., Mode=TwoWay}
in both cases, even though that's the default for those properties, just to be super-clear that that isn't the problem.
The ViewModelBase
code is shared by both examples, and is simply a convenient way of raising INotifyPropertyChanged.PropertyChanged
without any extra dependencies:
ViewModelBase.cs:
...ANSWER
Answered 2022-Apr-09 at 18:07These both may be bugs with the currently released version of MAUI.
This bug was recently posted and there is already a fix for the Switch to address this issue.
QUESTION
I'm using React Router v6 and am creating private routes for my application.
In file PrivateRoute.js, I've the code
...ANSWER
Answered 2021-Nov-12 at 21:20I ran into the same issue today and came up with the following solution based on this very helpful article by Andrew Luca
In PrivateRoute.js:
QUESTION
My current android application targets 12 and higher.
I do not want to allow backup of any type and currently have these manifest settings
...ANSWER
Answered 2022-Feb-10 at 15:28It's usually better to disable backups only for debug builds:
QUESTION
Haskell typeclasses often come with laws; for instance, instances of Monoid
are expected to observe that x <> mempty = mempty <> x = x
.
Typeclass laws are often written with single-equals (=
) rather than double-equals (==
). This suggests that the notion of equality used in typeclass laws is something other than that of Eq
(which makes sense, since Eq
is not a superclass of Monoid
)
Searching around, I was unable to find any authoritative statement on the meaning of =
in typeclass laws. For instance:
- The Haskell 2010 report does not even contain the word "law" in it
- Speaking with other Haskell users, most people seem to believe that
=
usually means extensional equality or substitution but is fundamentally context-dependent. Nobody provided any authoritative source for this claim. - The Haskell wiki article on monad laws states that
=
is extensional, but, again, fails to provide a source, and I wasn't able to track down any way to contact the author of the relevant edit.
The question, then: Is there any authoritative source on or standard for the semantics for =
in typeclass laws? If so, what is it? Additionally, are there examples where the intended meaning of =
is particularly exotic?
(As a side note, treating =
extensionally can get tricky. For instance, there is a Monoid (IO a)
instance, but it's not really clear what extensional equality of IO
values looks like.)
ANSWER
Answered 2022-Feb-24 at 22:30Typeclass laws are not part of the Haskell language, so they are not subject to the same kind of language-theoretic semantic analysis as the language itself.
Instead, these laws are typically presented as an informal mathematical notation. Most presentations do not need a more detailed mathematical exposition, so they do not provide one.
QUESTION
Background
I have a complex nested JSON object, which I am trying to unpack into a pandas df
in a very specific way.
JSON Object
this is an extract, containing randomized data of the JSON object, which shows examples of the hierarchy (inc. children) for 1x family (i.e. 'Falconer Family'), however there is 100s of them in total and this extract just has 1x family, however the full JSON object has multiple -
ANSWER
Answered 2022-Feb-16 at 06:41I think this gets you pretty close; might just need to adjust the various name
columns and drop the extra data (I kept the grouping
column).
The main idea is to recursively use pd.json_normalize with pd.concat for all availalable children
levels.
EDIT: Put everything into a single function and added section to collapse the name
columns like the expected output.
QUESTION
With the parent-child
relationships data frame as below:
ANSWER
Answered 2022-Feb-25 at 08:17We can use ego
like below
QUESTION
I am reading this book by Fedor Pikus and he has some very very interesting examples which for me were a surprise.
Particularly this benchmark caught me, where the only difference is that in one of them we use || in if and in another we use |.
ANSWER
Answered 2022-Feb-08 at 19:57Code readability, short-circuiting and it is not guaranteed that Ord will always outperform a ||
operand.
Computer systems are more complicated than expected, even though they are man-made.
There was a case where a for loop with a much more complicated condition ran faster on an IBM. The CPU didn't cool and thus instructions were executed faster, that was a possible reason. What I am trying to say, focus on other areas to improve code than fighting small-cases which will differ depending on the CPU and the boolean evaluation (compiler optimizations).
QUESTION
Consider a vector:
...ANSWER
Answered 2022-Feb-07 at 11:52Here f
is defined as a recursive function that calls itself over shorter tails of the lookup
vector:
QUESTION
I upgraded to Rails 7 and Ruby 3.1. While trying to run tests with rspec
I got the error below. How can I fix it?
ANSWER
Answered 2022-Jan-25 at 16:15UPD: on January 6th, 2022 Rails 7.0.1 was released:
The focus of this release is bring support to Ruby 3.1
Amongh other Ruby 3.1-related issues it brought a fix for this problem. So upgrade to Rails >= 7.0.1.
Add gem 'net-smtp', require: false
to your Gemfile and run bundle
.
Similarly I assume you may have problems with net-imap
and net-pop
and so have to add them until a new mail
gem version is released.
Related pull requests and issues:
QUESTION
Given a string S of length N, return a string that is the result of replacing each '?'
in the string S with an 'a'
or a 'b'
character and does not contain three identical consecutive letters (in other words, neither 'aaa'
not 'bbb'
may occur in the processed string).
Examples:
...ANSWER
Answered 2021-Sep-24 at 13:55I quickly tried out the solution I proposed in the comments:
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