prowler | Distributed Network Vulnerability Scanner

by tlkh Python Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(4)Vulnerabilities Install Support

kandi X-RAY | prowler Summary

prowler is a Python library typically used in Internet of Things (IoT), Raspberry Pi applications. prowler has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can download it from GitHub.

Prowler is a Network Vulnerability Scanner implemented on a Raspberry Pi Cluster, first developed during Singapore Infosec Community Hackathon - HackSmith v1.0.

Support

Quality

Security

License

Reuse

Support

prowler has a low active ecosystem.

It has 97 star(s) with 30 fork(s). There are 16 watchers for this library.

It had no major release in the last 6 months.

There are 3 open issues and 0 have been closed. On average issues are closed in 904 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of prowler is current.

Quality

prowler has 0 bugs and 0 code smells.

Security

prowler has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

prowler code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

prowler is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

prowler releases are not available. You will need to build from source code and install.

Build file is available. You can build the component from source.

Installation instructions are not available. Examples and code snippets are available.

prowler saves you 268 person hours of effort in developing the same functionality from scratch.

It has 650 lines of code, 15 functions and 12 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed prowler and discovered the below as its top functions. This is intended to give you an instant insight into prowler implemented functionality, and help decide if they suit your requirements.

compute nmap host

Get all kandi verified functions for this library.

prowler Key Features

No Key Features are available at this moment for prowler.

prowler Examples and Code Snippets

No Code Snippets are available at this moment for prowler.

Community Discussions

Trending Discussions on prowler

Django Defect-dojo: aws-prowler upload failed

Searching a file for multiple strings and output the data

Convert text snippets to dictionary key value pairs/JSON in python

Correct way to select a specific column from the last row of a Dataframe

QUESTION

Django Defect-dojo: aws-prowler upload failed

Asked 2020-Feb-10 at 12:49

I've implemented django-DefectDojo and trying to upload This sample-scan file but it throws me the following error in the logs.

Everything is perfectly installed and other files are being uploaded(whichever I require) but this file.
Error Thrown
Server Error (500)
Logs

...

ANSWER

Answered 2020-Feb-10 at 12:49

This is file parsing error, and DefectDoJo AWS Prowler Parser expects input file to be in .csv format with header row as in default prowler csv output - all capital letters.

Example .csv file (based on your .json file) to be imported (although not tested) - data in the same order as was in .json, timestamp removed, header row added with names as expected by DoJo and matching data types:

Accepted CSV format that matches (default) json data order, as some fields have different names in .json and .csv. Actual order does not matter for DoJo import.

Source https://stackoverflow.com/questions/60124657

QUESTION

Searching a file for multiple strings and output the data

Asked 2019-Nov-30 at 07:32

How can I search a .tsv file for multiple matches to a string and export them to a database?

What I'm trying to do is search a large file called mdata.tsv (1.5m lines) for a string given to it from an array. Afterwards output matching columns data.

The current code is what I've gotten stuck at:

...

ANSWER

Answered 2019-Nov-30 at 07:32

It looks as though you can simplify this code by using in_array() instead of the nested loops to see if the current line is in the list of required ID's. The one change needed to make sure this works is that you need to ensure that you store strings in the $movID array.

Source https://stackoverflow.com/questions/59114101

QUESTION

Convert text snippets to dictionary key value pairs/JSON in python

Asked 2018-Mar-28 at 14:14

I am trying to convert the output of Prowler in the following format to a dictionary, and then converting the dictionary into a JSON file.

...

ANSWER

Answered 2018-Mar-28 at 14:06

You can do this in one loop. For each line, if it is a header, update the current key, else append the line in the findings with current key:

Source https://stackoverflow.com/questions/49536208

QUESTION

Correct way to select a specific column from the last row of a Dataframe

Asked 2017-Sep-10 at 14:44

I have a dataframe stock_pick and trying to set last row of certain column like

...

ANSWER

Answered 2017-Sep-10 at 14:44

You can use get_loc for position of column and thn is posssible use DataFrame.iloc:

Source https://stackoverflow.com/questions/46141866

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install prowler

You can download it from GitHub.
You can use prowler like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: