cubed | memory serverless distributed N-dimensional array processing | Data Manipulation library

 by   tomwhite Python Version: 0.12.0 License: Apache-2.0

kandi X-RAY | cubed Summary

kandi X-RAY | cubed Summary

cubed is a Python library typically used in Utilities, Data Manipulation applications. cubed has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install cubed' or download it from GitHub, PyPI.

Bounded-memory serverless distributed N-dimensional array processing
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            kandi-support Support

              cubed has a low active ecosystem.
              It has 51 star(s) with 1 fork(s). There are 5 watchers for this library.
              There were 1 major release(s) in the last 6 months.
              There are 39 open issues and 67 have been closed. On average issues are closed in 44 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of cubed is 0.12.0

            kandi-Quality Quality

              cubed has no bugs reported.

            kandi-Security Security

              cubed has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              cubed is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              cubed releases are available to install and integrate.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of cubed
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            cubed Key Features

            No Key Features are available at this moment for cubed.

            cubed Examples and Code Snippets

            incorrect value outputting from while loop
            Pythondot img1Lines of Code : 16dot img1License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            cube = 0
            value = int(input("Enter a value to be cubed or 0 to quit: "))
            
            while value != 0:
                cube = value **3
                value = int(input("Enter a value to be cubed or 0 to quit: "))
                print (value, "cubed is", cube)
            
            Iterating over array and change row based on element wise
            Pythondot img2Lines of Code : 9dot img2License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            # 1xN could also be [3, 5], [2, 8], or any array of size N
            exponents_per_row = np.arange(2, 4)
            exponents = np.tile(exponents_per_row, (2, 1))
            res = np.power(arr, exponents)
            print(res)
            
            [[  1   8]
             [ 16 125]]
            
            Issue iterating through values of a previously made function in a new function
            Pythondot img3Lines of Code : 5dot img3License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            def cubics(n):
            
            def sum_of_cubics(n):
                return sum(cubics(n))
            
            Should we return and then print the result or just print the result inside the function?
            Pythondot img4Lines of Code : 4dot img4License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            def sixth_power(x):
                cubed = cube(x)
                return cubed * cubed
            
            why is my loop of cubed digits producing incorrect outputs?
            Pythondot img5Lines of Code : 12dot img5License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            m = 10
            n = 1
            
            while n <= m // 2:
              total_n = 0
              
              for i in range(0, n):
                total_n += (n - i) ** 3
            
              n += 1
              print(total_n)
            
            Printing python lists inside dictionary vertically
            Pythondot img6Lines of Code : 20dot img6License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            output_dictionary = {
                "inputs": [3,5,10],
                "squared": [9,25,100],
                "cubed": [27,125,1000],
            }
            
            headers = ["Number", "Square", "Cube"]
            values = output_dictionary.values()
            
            row_format ="{:>10}" * (len(headers) + 1)
            print(row_form
            Using a for loop to create cube integers
            Pythondot img7Lines of Code : 8dot img7License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            cubed = []
            
            for number in numbers_to_cube:
            
              cubed.append(number**3)
            
            print(cubed) # Prints [1331, 1728, 2197, 2744, 3375]
            
            copy iconCopy
            print("Table of Powers")
            print()
            start = int(input("Start number:\t"))
            end = int(input("Stop number:\t"))
            print()
            
            def printTable(start, end):
                result = 1
                for x in range(start, end):
                    print(x, x ** 2, x ** 3)
            
            # call your fun
            copy iconCopy
            for i in range(1, 12):
                print(f"no {i} squared is {i**2} and cubed is {i**4:4}"
            
            >>> 
            no 1 squared is 1 and cubed is    1
            no 2 squared is 4 and cubed is   16
            no 3 squared is 9 and cubed is   81
            no 4 squared is 16 and cubed is  
            How to implement Newton's method iteratively to estimate roots
            Pythondot img10Lines of Code : 8dot img10License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            y = int(input('Enter number for cubed root:'))
            x = 1
            n = 50
            
            for _ in range(n):
                x = 1/3 * (2*x + y/(x**2))
                print(x)
            

            Community Discussions

            QUESTION

            R: Is there a "Un-Character" Command in R?
            Asked 2022-Apr-10 at 17:37

            I am working with the R programming language.

            I have the following dataset:

            ...

            ANSWER

            Answered 2022-Apr-10 at 05:36

            Up front, "1,3,4" != 1. It seems you should look to split the strings using strsplit(., ",").

            Source https://stackoverflow.com/questions/71813866

            QUESTION

            Creating new columns based on data in row separated by specific character in R
            Asked 2022-Mar-15 at 08:48

            I've the following table

            Owner Pet Housing_Type A Cats;Dog;Rabbit 3 B Dog;Rabbit 2 C Cats 2 D Cats;Rabbit 3 E Cats;Fish 1

            The code is as follows:

            ...

            ANSWER

            Answered 2022-Mar-15 at 08:48

            One approach is to define a helper function that matches for a specific animal, then bind the columns to the original frame.

            Note that some wrangling is done to get rid of whitespace to identify the unique animals to query.

            Source https://stackoverflow.com/questions/71478316

            QUESTION

            Multiplying and Adding Values across Rows
            Asked 2022-Mar-10 at 08:24

            I have this data frame:

            ...

            ANSWER

            Answered 2022-Mar-10 at 04:12

            We can use stri_replace_all_regex to replace your color_1 into integers together with the arithmetic operator.

            Here I've stored your values into a vector color_1_convert. We can use this as the input in stri_replace_all_regex for better management of the values.

            Source https://stackoverflow.com/questions/71418533

            QUESTION

            How to make a rank column in R
            Asked 2022-Mar-07 at 16:19

            I have a database with columns M1, M2 and M3. These M values correspond to the values obtained by each method. My idea is now to make a rank column for each of them. For M1 and M2, the rank will be from the highest value to the lowest value and M3 in reverse. I made the output table for you to see.

            ...

            ANSWER

            Answered 2022-Mar-07 at 14:15

            Using rank and relocate:

            Source https://stackoverflow.com/questions/71381995

            QUESTION

            How to return the column title wherein the row contains the greatest value in Pandas Dataframe
            Asked 2022-Feb-24 at 20:56

            I working on a Python project that has a DataFrame like this:

            ...

            ANSWER

            Answered 2022-Feb-24 at 20:48

            You could use the idxmax method on axis:

            Source https://stackoverflow.com/questions/71258033

            QUESTION

            Split large csv file into multiple files based on column(s)
            Asked 2022-Feb-07 at 12:49

            I would like to know of a fast/efficient way in any program (awk/perl/python) to split a csv file (say 10k columns) into multiple small files each containing 2 columns. I would be doing this on a unix machine.

            ...

            ANSWER

            Answered 2021-Dec-12 at 05:22

            With your show samples, attempts; please try following awk code. Since you are opening files all together it may fail with infamous "too many files opened error" So to avoid that have all values into an array and in END block of this awk code print them one by one and I am closing them ASAP all contents are getting printed to output file.

            Source https://stackoverflow.com/questions/70320648

            QUESTION

            Get the first non-null value from selected cells in a row
            Asked 2022-Feb-04 at 09:55

            Good afternoon, friends!

            I'm currently performing some calculations in R (df is displayed below). My goal is to display in a new column the first non-null value from selected cells for each row.

            My df is:

            ...

            ANSWER

            Answered 2022-Feb-03 at 11:16

            One option with dplyr could be:

            Source https://stackoverflow.com/questions/70970158

            QUESTION

            pivot_longer with column pairs
            Asked 2022-Feb-03 at 14:02

            I am again struggling with transforming a wide df into a long one using pivot_longer The data frame is a result of power analysis for different effect sizes and sample sizes, this is how the original df looks like:

            ...

            ANSWER

            Answered 2022-Feb-03 at 10:59
            library(tidyverse)
            
            example %>% 
              pivot_longer(cols = starts_with("es"), names_to = "type", names_prefix = "es_", values_to = "es") %>%
              pivot_longer(cols = starts_with("pwr"), names_to = "pwr", names_prefix = "pwr_") %>% 
              filter(substr(type, 1, 3) == substr(pwr, 1, 3)) %>% 
              mutate(pwr = parse_number(pwr)) %>% 
              arrange(pwr, es, type)
            

            Source https://stackoverflow.com/questions/70969176

            QUESTION

            Simulating Random Draws From a "Hat"
            Asked 2021-Dec-28 at 21:50

            Suppose I have the following 10 variables (num_var_1, num_var_2, num_var_3, num_var_4, num_var_5, factor_var_1, factor_var_2, factor_var_3, factor_var_4, factor_var_5):

            ...

            ANSWER

            Answered 2021-Dec-26 at 10:11

            You may define a function FUN(n) that creates a data set as shown in OP.

            Source https://stackoverflow.com/questions/70483731

            QUESTION

            Break Apart a String into Separate Columns R
            Asked 2021-Dec-17 at 20:39

            I am trying to tidy up some data that is all contained in 1 column called "game_info" as a string. This data contains college basketball upcoming game data, with the Date, Time, Team IDs, Team Names, etc. Ideally each one of those would be their own column. I have tried separating with a space delimiter, but that has not worked well since there are teams such as "Duke" with 1 part to their name, and teams with 2 to 3 parts to their name (Michigan State, South Dakota State, etc). There also teams with "-" dashes in their name.

            Here is my data:

            ...

            ANSWER

            Answered 2021-Dec-16 at 15:25

            Here's one with regex. See regex101 link for the regex explanations

            Source https://stackoverflow.com/questions/70381064

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install cubed

            You can install using 'pip install cubed' or download it from GitHub, PyPI.
            You can use cubed like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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            Install
          • PyPI

            pip install cubed

          • CLONE
          • HTTPS

            https://github.com/tomwhite/cubed.git

          • CLI

            gh repo clone tomwhite/cubed

          • sshUrl

            git@github.com:tomwhite/cubed.git

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