omega | Specify and synthesize systems using symbolic algorithms
kandi X-RAY | omega Summary
kandi X-RAY | omega Summary
A package of symbolic algorithms using binary decision diagrams (BDDs) for synthesizing implementations from [temporal logic specifications][specs]. This is useful for designing systems, especially vehicles that carry humans.
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Top functions reviewed by kandi - BETA
- Make Rabin transducer
- Check if a win is realizable
- Warn if we are using mealy
- Compute a controllable action
- Computes the transducer for a given state
- Set up common vars
- Adds a set of values to the BDD
- Raise a ValueError if dvars are not in fresh
- Map a list of variables to their corresponding parameters
- Generate a list of expressions
- Dump a cover object
- Convert a graph to an automaton
- Fetch an expression from the BDD
- Optimizes two managers
- Create a semi - symbolic transition system
- Compute the comparison op
- Create bitmap table from data
- R Define component factory
- Specify component bar
- Enumerate mincovers below a set
- Raise an AssertionError if a
- Plot orthotopes
- Run setup parser
- Add an expression to the BDD
- Create a dictionary mapping vrs to functions
- Dump bdd to code
omega Key Features
omega Examples and Code Snippets
Community Discussions
Trending Discussions on omega
QUESTION
ANSWER
Answered 2021-Jun-10 at 16:24You can redraw parts of your first function:
QUESTION
I've been breaking my head over this for quite some time and hope to get some support here. I have an array containing multiple objects.
Every object represents a production process comprised of subprocesses made up of inputs and outputs. These processes run in line. Meaning, that the output of one process will become the input for another process. However, I have no idea in which order.
I am trying to figure out the sequence the main processes need to be run in. Our system can't tell me and now I have 5000interdependant processes that need sorting.
Here an example of how the array is formatted. As you can see Inputs have an origin flag. At least we know whether an input is taken from a warehouse or is produced somewhere upstream. If I were to sort this manually the order would be Process3, then Process 2, then Process 1. Process 1 requires the material with the id="ID3" as input, which is produced in process 2 (under subprocess 2). While Process 2 requires the material "ID5" which is produced in process 3. Anybody have an idea how to solve this nightmare?
Thank you sooo much!!!
...ANSWER
Answered 2021-Jun-10 at 13:20As I said in the comments, what you seem to have is a graph theory problem :-)
- The entire thingamabob is a directed acyclic graph – or in this case, basically a dependency tree.
- Each subprocess as a node in the graph.
- Edges point from processes outputting resources to processes requiring those resources.
- The topological ordering of the graph is the order in which the processes need to be complete.
This solution requires the toposort package for the heavy graph lifting.
QUESTION
I found this in another language. I am wondering if anyone could find this in a English book please. Or if anyone know how to prove this please. Preferably one could tell me a reference book. Thank you very much. Let $(\Omega, F, P)$ be a probability space. and let $g$ and $h $ be functions such that $\int_A g,dP\leqslant \int_A h,dP $ for all $A \in F$, then for $g,h \in \mathbb{L}^1(P)$, $g\leqslant h$
...ANSWER
Answered 2021-Jun-10 at 10:14You will need to use measure theory. If it is the opposite case, you can find a contradiction.
QUESTION
I am using spring-batch in spring-boot application. The Spring Boot version is 2.3.3.RELEASE.
What I intend to achieve
I have to read a xml file containing thousands of Transactions with header tag (fileInformation). Do some business logic on transaction and then write the file back with the updated values in transaction. I am using StaxEventItemReader for reading the file and StaxEventItemWriter for writing to the file. Then i have couple of ItemProcessors for handling the business logic. Xml file looks like :
ANSWER
Answered 2021-Jun-10 at 07:38You step is doing too much. I would beak things down to two steps:
- Step 1: extracts the file information header and puts it in the job execution context
- Step 2: reads the file information header from the execution context and uses it in whatever step-scoped bean needed for that step (for example the stax callback in your case)
Here is a quick example:
QUESTION
I am splitting my dataset by simulation ID and applying a runjags functions to each subsest simultaneously.
Right now, each simulation contains 1000 observations. I know that sometimes the number of observations will differ since I will be dropping rows that meet certain criteria. I don't know how many observations will be dropped but I can calculate that by using groupobs <- fulldata %>% count(SimulID, sort=TRUE).
Is there a way that I can change N=1000 during each simulation run. It would mean having to rewrite the tempModel.txt file with every simulation that is run.
Thank you.
...ANSWER
Answered 2021-Jun-09 at 07:31You have several options
You could construct the model string on the fly. [The model argument to run.jags can contain a character string instead of a file name, so there's no need to write to a file and then read it in again.]
You can add an element to your data list (x in your code) that contains the number of observations,
QUESTION
I have to dataframes. I need to perform a manipulation on dataframe A. It looks like this:
name score alpha 16 beta 12 gamma 24 delta 16The second dataframe, B, is a mapping.
name_in name_out weight beta beta_1 0.5 beta beta_2 0.3 beta beta_3 0.2 omega omega_1 0.9 omega omega_2 0.1If I perform the mapping on dataframe A, I need the following outcome:
name score alpha 16 beta_1 6 beta_2 3.6 beta_3 2.4 gamma 24 delta 16So, conceptually, I need an algorithm that checks if the name occurs in the mapping dataframe. If it does, I need to duplicate the row for as many values exist in the mapping. Also, I need to multiply the duplicated scores with the weight of the mapping.
The procedure basically adds a level of detail, given the mapping.
...ANSWER
Answered 2021-Jun-02 at 13:50QUESTION
Let R_1, ..., R_n be n rectangles for which the four corners of each rectangle are integers in {1..n}. I'm trying to write an algorithm (so code isn't necessary) that sorts the rectangles by increasing area in O(n) time. I've checked out this answer, but I think the algorithm actually runs in time O(n+k) = O(n+n^2) = O(n^2) time (you actually have to initialize the array and the prefix sum method takes O(k) time). I can't do comparison based sorting as that's in Omega(nlogn). So I think I have to do non comparison-based sorting like counting sort, but using a different technique.
...ANSWER
Answered 2021-May-28 at 17:12Radix sort does in O((n + base) * digits_in_maximum_number).
digits_in_maximum_number would be O(log_to_base(n))
=> O((n + base) * log_to_base(n)).
Now we want to do it in linear time. So, the only option I can think of is to convert the {1..n} numbers to base n so that we have:
=> O((n + n) * log_to_n(n))
=> O(n)
It is important to understand that for this idea to work, you've to limit n so that digits_in_maximum_number would become some constant. Apparently, if you don't keep any constraints on n beforehand, what you are asking is not possible. Also, I assume that conversion of number to a given base is O(1).
QUESTION
I'm doing exam review for an exam i have in a few days and i've come across this question. "Count the number of assignments in the following code (include all loop counter initializations and increments). now record your working in plain text on the exam page. give your answer as a polynomial function of n (do not simplify using O, Theta, or Omega notation).
...ANSWER
Answered 2021-May-26 at 08:32i j sum notes
0 0 +=a[0]
0 1 - break the inner loop
1 0 +=a[0]
1 1 +=a[1]
1 2 - break the inner loop
2 0 +=a[0]
2 1 +=a[1]
2 2 +=a[2]
2 3 - break the inner loop
... ...
n-1 n-1 +=a[n-1]
n-1 n - break the inner loop
n - - break the outer loop
QUESTION
I have data frame mydata that looks like this:
ANSWER
Answered 2021-May-25 at 21:57You could use dplyr's mutate function:
QUESTION
I would like to construct panel data in R. I know how to do do it in principle but not how to do it efficiently.
My desired outcome would look like:
...ANSWER
Answered 2021-May-22 at 13:12Collect all object names into a list lst and proceed as follows. I emptied my current folder and then proceeded.
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