metta | An information security preparedness tool to do adversarial simulation
kandi X-RAY | metta Summary
kandi X-RAY | metta Summary
Metta is an information security preparedness tool. This project uses Redis/Celery, python, and vagrant with virtualbox to do adversarial simulation. This allows you to test (mostly) your host based instrumentation but may also allow you to test any network based detection and controls depending on how you set up your vagrants. The project parses yaml files with actions and uses celery to queue these actions up and run them one at a time without interaction.
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Top functions reviewed by kandi - BETA
- Parse a yaml file
- Run UUIDs inside the ioc file
- Runs the scenario
- End the log
- Start a new document
- Write a log entry
metta Key Features
metta Examples and Code Snippets
Community Discussions
Trending Discussions on metta
QUESTION
I have two tables this one is old names
...ANSWER
Answered 2021-Dec-02 at 22:49You could use
QUESTION
I created a „.htaccess“ file to redirect the website visitors from an old page (example.com) to a new page (example.org). The challenge is that I want to redirect most old pages to a specific url address. As I read I can do it with the following code:
...ANSWER
Answered 2021-Mar-09 at 16:59QUESTION
We want the customers to only purchase the following quantities.
- 1 Bag
- 2 Bags
- 3 Bags
- 4 Bags
- 5 Bags
- 10 Bags
So, far; we've successfully managed to limit the number of quantities, that can be selected on the single product page,
We're currently using the following code to limit the user to a total of 10 Bags.
...ANSWER
Answered 2020-Sep-21 at 13:12This one :
QUESTION
I have 2 lists of Names of players from 2 different sources.
names1 = ['C.J. McCollum', 'Metta World', 'LeBron James', 'Stephen Curry']
names2 = ['Metta World Peace', 'Steph Curry', 'Kevin Durant', 'CJ McCollum']
The problem here is that though they are the same players, there are some difference in the way their names are mentioned in the 2 sources. I used the following code the find the similar names (all characters in names1
should exist in names2
):
ANSWER
Answered 2020-Feb-09 at 16:31you are getting error because of y in z: ,you can use y in w: also you can do some formatting like removing '.' before comparing , and then you can use any string similarity algo like Levenshtein distance , to find similar strings , "pip install python-Levenshtein"
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