IV | use User location in background so that they can be track | Frontend Framework library

by vijayshankarrealdeal Python Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | IV Summary

IV is a Python library typically used in User Interface, Frontend Framework applications. IV has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However IV build file is not available. You can download it from GitHub.

The app will use User location in background so that they can be track by their nominee or the user relative. And show zones based on National Crime Record Bureau for women crime. (show red, yellow and green zone based on data). The app will feature all necessary numbers of emergency. This app will include form where user can fill their compliant and at home, they can fire a FIR without reaching to police station, which will prevent them from unnecessary talk and wrong behaviour fake video and call service, so that they can trigger when feel unsafe in environment. and a beep sound trigger.

Support

Quality

Security

License

Reuse

Support

IV has a low active ecosystem.

It has 1 star(s) with 1 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

IV has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of IV is current.

Quality

IV has 0 bugs and 0 code smells.

Security

IV has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

IV code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

IV is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

IV releases are not available. You will need to build from source code and install.

IV has no build file. You will be need to create the build yourself to build the component from source.

It has 107615 lines of code, 7888 functions and 512 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed IV and discovered the below as its top functions. This is intended to give you an instant insight into IV implemented functionality, and help decide if they suit your requirements.

Decorator to collect the phase of a function
Deserialize from TOML .
Shortcut for urlopen .
Install a wheel .
Creates an Element Builder .
Add UI widgets .
Install the wheel .
Creates a DOM builder .
Read data from the buffer .
Create a rpm specification file .

Get all kandi verified functions for this library.

IV Key Features

No Key Features are available at this moment for IV.

IV Examples and Code Snippets

No Code Snippets are available at this moment for IV.

Community Discussions

Trending Discussions on IV

Crypto-js encryption and Python decryption using HKDF key

How to show a JSON value with numeric key in HTML table using AJAX

Perl numeric comparison of numeric strings understanding and debugging

iOS CryptoSwift AES Encryption to Python Decryption works - but not the inverse

Problems deploying a Vaadin App to production

How to improve the HTML Table Styling that is to be converted into a PDF File

Horizontally merge and divide cells in an HTML Table for Timetable based on the Data in Python File

How do I calculate a key check value for AES-128-CBC?

Problem Updating to .Net 6 - Encrypting String

Data Encryption static encrypt

QUESTION

Crypto-js encryption and Python decryption using HKDF key

Asked 2022-Mar-28 at 11:29

Based on the example provided here on how to establish a shared secret and derived key between JS (Crypto-JS) and Python, I can end up with the same shared secret and derived key on both ends.

However, when I try to encrypt as below, I cannot find a way to properly decrypt from Python. My understanding is that probably I am messing with the padding or salts and hashes.

...

ANSWER

Answered 2022-Mar-28 at 11:29

The issue is that the key is not passed correctly in the CryptoJS code.

The posted Python code generates LefjQ2pEXmiy/nNZvEJ43i8hJuaAnzbA1Cbn1hOuAgA= as Base64-encoded key. This must be imported in the CryptoJS code using the Base64 encoder:

Source https://stackoverflow.com/questions/71632056

QUESTION

How to show a JSON value with numeric key in HTML table using AJAX

Asked 2022-Mar-16 at 13:40

I'm new to web development and I´ve been trying out building tables with data from different API´s but have run into a problem with a response that has numeric keys within the object.

I get the response to show in log but can not get the data to a table.

I reused the code from a previous test (that was successful), but in this test the keys are numeric. Here is the response:

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ANSWER

Answered 2022-Mar-16 at 13:40

you can try this code

Source https://stackoverflow.com/questions/71495421

QUESTION

Perl numeric comparison of numeric strings understanding and debugging

Asked 2022-Jan-28 at 14:47

I have 2 variables, x, y with "numeric" data. Note, both of these come from different sources (mysql data and parsed file data), so I am assuming firstly that they have ended up as strings.

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ANSWER

Answered 2022-Jan-28 at 10:54

my $x = 14.000000000000001;
my $y = 14;

Source https://stackoverflow.com/questions/70892478

QUESTION

iOS CryptoSwift AES Encryption to Python Decryption works - but not the inverse

Asked 2022-Jan-28 at 10:30

I am using CryptoSwift 1.4.1, iOS 15.2, PyCryptodome 3.12.0, and XCode 13.2.1 to encrypt small string messages that I send to a Raspberry Pi Linux Device over BLE. It works when iOS encrypts the message and sends it to the Raspberry Pi. The Pi can successfully decrypt it. Now I want to do the inverse, encrypt a message on the Pi and have the iOS App read and decrypt it. This, however is not working and the decrypted value is the not the message I encrypted on the Pi.

Working iOS encryption:

...

ANSWER

Answered 2022-Jan-28 at 10:30

In the encrypt() method the IV is not considered. As in aesEncrypt(), the IV must be passed and used when creating the AES object.
Furthermore there are bugs in the encoding: The plaintext must be UTF8 encoded and the ciphertext must be hex encoded:

Source https://stackoverflow.com/questions/70809612

QUESTION

Problems deploying a Vaadin App to production

Asked 2022-Jan-27 at 20:20

I'm working with Java 8 and Vaadin 22. When I want to deploy my starter app to production by

...

ANSWER

Answered 2022-Jan-27 at 20:20

As Simon Martinelli said, running vaadin:dance in the command prompt and moving the folder out of the One Drive scope before mvnw clean package -Pproduction command was the solution to my problem

Source https://stackoverflow.com/questions/70869745

QUESTION

How to improve the HTML Table Styling that is to be converted into a PDF File

Asked 2022-Jan-25 at 00:43

I have a Python code that is creating HTML Tables and then turning it into a PDF file. This is the output that I am currently getting

This image is taken from PDF File that is being generated as result (and it is zoomed out at 55%)

I want to make this look better. Something similar to this, if I may

This image has 13 columns, I don't want that. I want to keep 5 columns but my major concern is the size of the td in my HTML files. It is too small in width and that is why, the text is also very stacked up in each td. But if you look at the other image, text is much more visible and boxes are much more bigger width wise. Moreover, it doesn't suffer from height problems either (the height of the box is in such a way that it covers the whole of the PDF Page and all the tds don't look like stretched down)

I have tried to play around the height and width of my td in the HTML File, but unfortunately, nothing really seemed to work for me.

Edit: Using the code provided by onkar ruikar, I was able to achieve very good results. However, it created the same problem that I was facing previously. The question was asked here: Horizontally merge and divide cells in an HTML Table for Timetable based on the Data in Python File

I changed up the template.html file of mine and then ran the same code. But I got this result,

As you can see, that there were more than one lectures in the First Slot of Monday, and due to that, it overlapped both the courses. It is not reading the

command properly in this HTML file now.

The modified template.html file has this code,

...

ANSWER

Answered 2022-Jan-25 at 00:43

What I've done here is remove the borders from the table and collapsed the space for them.

I've then used more semantic elements for both table headings and your actual content with semantic class names. This included adding a new element for the elements you want at the bottom of the cell. Finally, the teacher and codes are floated left and right respectively.

Source https://stackoverflow.com/questions/70807885

QUESTION

Horizontally merge and divide cells in an HTML Table for Timetable based on the Data in Python File

Asked 2022-Jan-15 at 06:02

Please note this question is an extension of this previously asked question: How to make Images/PDF of Timetable using Python

I am working on a program that generates randomized Timetable based on an algorithm. For the Final Output of that program, I require a Timetable to be stored in a PDF File.

There are multiple sections and each section must have its own timetable/schedule. Each Section can have multiple Courses whose lectures will be allocated on different slots from Monday to Friday by the algorithm. For my timetable,

There are 5 days in total (Monday to Friday)
Each day will have 5 slots (0 to 4 in indexes. With a "Lunch" Break between 3rd and 4th slot)

As an Example, I have created below a dictionary where key represents the Section and the items have a 2D Array of size 5x5. Each Index of that 2D array contains the course details for which the lecture will take place in that slot.

...

ANSWER

Answered 2022-Jan-15 at 06:02

I am not much familiar with Jinja, so this answer might not be the most efficient one.

By using basic hard coding in your Template.HTML file, I was able to achieve the results you are trying to. For this, I used the same code that was given by D-E-N in your previous question.

I combined all the attributes of your object into a string

An attribute is differentiated from another with @ (like Course and Teacher)
Instead of using space character, I used a _ character to represent space character in the attributes.
If one slot contains multiple objects, they are differentiated with space character (just like in the code provided by D-E-N)

Here's the updated code of yours with these changes,

Source https://stackoverflow.com/questions/70623210

QUESTION

How do I calculate a key check value for AES-128-CBC?

Asked 2022-Jan-13 at 16:47

I'm trying to implement a function in Java to calculate the key check value for a 128 bit AES encryption key. The AES128CBCEncryptor class is implementing AES/128/CBC with ISO 9797-1 M2 padding.

The only information I can find on the key check value algorithm for AES says "the KCV for an AES key is computed by encrypting 16 bytes, each with value '01'.". It does not specify how the IV should be constructed.

Here is what I have thus far, but it's not generating the expected result:

...

ANSWER

Answered 2022-Jan-13 at 16:47

For a Key Check Value (KCV) one generally uses single block encryption, without any mode such as ECB or CBC. As only a constant value of 16 bytes is used, there is no need for padding either.

If you just have a CBC class that performs ISO 9797-1 M2 padding then you could encrypt the static value of 01010101010101010101010101010101 (hex encoding of 16 bytes), using an all-zero IV and taking the first 16 bytes from the result (removing 16 bytes of ciphertext at the end that is just encryption of the mandatory padding).

As you can see in the image below, because the IV is all zero, the XOR with the plaintext leaves the input intact, basically making the first ciphertext identical to direct encryption with the block cipher.

By WhiteTimberwolf (SVG version) - PNG version, Public Domain, https://commons.wikimedia.org/w/index.php?curid=26434096

However, as you are using Java, it makes more sense to use a Cipher object using algorithm "AES/ECB/NoPadding" and use that to encrypt the value of 01010101010101010101010101010101 directly. ECB doesn't take an IV, so that problem is avoided. Also, no padding needs to be considered when "NoPadding" is specified.

If you need fewer bytes: those are usually taken from the left (lowest index) of the result.

Beware that these kinds of KCV's are somewhat dangerous as they show the ciphertext of one particular plaintext block. In the worst instances, this could lead to an adversary decrypting one ciphertext block, or for an authenticated scheme to lose its integrity/authentication properties.

Commonly KCV's are over an all-zero plaintext block. Using an all one-valued block makes the chance that this happens smaller, but that chance is still significant.

Source https://stackoverflow.com/questions/70683993

QUESTION

Problem Updating to .Net 6 - Encrypting String

Asked 2021-Dec-20 at 23:09

I'm using a string Encryption/Decryption class similar to the one provided here as a solution.

This worked well for me in .Net 5.
Now I wanted to update my project to .Net 6.

When using .Net 6, the decrypted string does get cut off a certain point depending on the length of the input string.

▶️ To make it easy to debug/reproduce my issue, I created a public repro Repository here.

The encryption code is on purpose in a Standard 2.0 Project.
Referencing this project are both a .Net 6 as well as a .Net 5 Console project.

Both are calling the encryption methods with the exact same input of "12345678901234567890" with the path phrase of "nzv86ri4H2qYHqc&m6rL".

.Net 5 output: "12345678901234567890"
.Net 6 output: "1234567890123456"

The difference in length is 4.

I also looked at the breaking changes for .Net 6, but could not find something which guided me to a solution.

I'm glad for any suggestions regarding my issue, thanks!

Encryption Class

...

ANSWER

Answered 2021-Nov-10 at 10:25

The reason is this breaking change:

DeflateStream, GZipStream, and CryptoStream diverged from typical Stream.Read and Stream.ReadAsync behavior in two ways:

They didn't complete the read operation until either the buffer passed to the read operation was completely filled or the end of the stream was reached.

And the new behaviour is:

Starting in .NET 6, when Stream.Read or Stream.ReadAsync is called on one of the affected stream types with a buffer of length N, the operation completes when:

At least one byte has been read from the stream, or The underlying stream they wrap returns 0 from a call to its read, indicating no more data is available.

In your case you are affected because of this code in Decrypt method:

Source https://stackoverflow.com/questions/69911084

QUESTION

Data Encryption static encrypt

Asked 2021-Dec-13 at 08:04

My hexidigit is changing on day by day basis. How can I change it back to static

Code

...

ANSWER

Answered 2021-Dec-13 at 08:04

I got the solution by encrypting the key using bytes() Use the byte method to store the key in secured config file or database and encrypt the byte string to get the key. After that use any cipher method with suitable algorithm to encrypt the data and mask it.

Source https://stackoverflow.com/questions/69521408

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install IV

You can download it from GitHub.
You can use IV like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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