Codejam | Solution to Google Code Jam questions in python
kandi X-RAY | Codejam Summary
kandi X-RAY | Codejam Summary
Solution to Google Code Jam questions in python.
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Top functions reviewed by kandi - BETA
- Solve linear equations
- Return a list of permutations
- Reload a node to the given distance
- Performs Bellman - Ford algorithm
- Return a subset of subsets
- Calculate attacks for a tribe
- Helper function to update tree
- Return the minimum value of the tree
- Insert attack into tree
- Solve the problem
- Solve the equation
- Checks if a matrix is possible
- Return whether N is on or off
- Find the index of the sum of the values in the given values
- Generate root roots
- Execute the solver
- Return a list of palindrome
- Calculate the indices of r and t
- Translate a message
- Return a list of subsets
- Computes the minimum product of two vectors
- Make a random number of integers
- Calculate the gain of a given period
- Test the test function
- Return the number of n values in a string
- Performs recurrences
- Calculate profit price
- A fibonacci number
Codejam Key Features
Codejam Examples and Code Snippets
Community Discussions
Trending Discussions on Codejam
QUESTION
This problem involves an arbitrary number of dice with each an arbitrary number of sides. We then find the maximal number of dice that can be put in a straight, see Google's Code Jam explanation. I've been trying to solve the problem in Haskell and I think the following solution works algorithmically. However, it is not fast enough to earn full points on the problem, so can this be optimized?
...ANSWER
Answered 2022-Apr-15 at 15:11What you are here doing is constructing a large expression tree that will look for a list [1, 2, 3, 4, 5, 6] as:
QUESTION
I'm trying to come up with a DP solution to Moons and Umbrellas from Code Jam's Qualification Round 2021. Below is my working recursive solution, based on their analysis:
...ANSWER
Answered 2021-Nov-01 at 07:56This solution works for all 3 Test sets:
QUESTION
I was trying to understand the solution to the codejam problem mentioned by the title. Specifically the third part for "extra credits". This is the solution by "kamyu104" from Github.
...ANSWER
Answered 2021-Apr-25 at 05:42This rather terse code implements a dynamic programming algorithm that has been optimised to reduce the space usage from O(n) to O(1). First I'll describe an equivalent DP and how it can be computed, and then show how the many separate cases it needs to handle can be viewed as instances of a smaller number of more general "case templates", which kamyu's code exploits for concision.
A correct but verbose DP algorithmThe question frames the problem as finding a minimum-cost way to replace each "?" character with a J or C, but we can alternatively frame it as finding a minimum-cost way to replace all characters of the input string S, provided that we never change a J to a C or vice versa -- that is, we can imagine ourselves "replacing" an existing J with another J, or an existing C with another C. In fact, that "provided" clause can even be removed: We can get what we want by permitting all possible replacements, including a J to be changed to a C or vice versa, but prevent these undesirable changes from actually appearing in any optimal solution by penalising them with enormous costs.
Let's define the function f(m, a) to be the minimum cost of a solution to the subproblem consisting of the first m+1 characters of the input string S, under the assumption that we replace the final (i.e., (m+1)-th) character with a, which must be either "J" or "C". (Why m+1 and not m? That just makes code with 0-based array indices simpler.) Replacements that leave this character unchanged (J->J or C->C) are allowed, as are replacements of "?" characters to either J or C. The way we will prevent changing an existing J to a C or vice versa is to assign infinite cost to such a replacement -- this will result in this choice never being taken, since another lower-cost choice is always available.
We can compute values of f(m, a) as follows. I'll use Python-like pseudocode that writes to a DP matrix dp[][].
The highest-priority rule is that we should always assign infinite cost to any attempt to change a hardwired letter to the other letter. Other than that, the cost of assigning a particular letter depends on the preceding letter -- unless there is no preceding letter because we are at the very start, in which case we know that the cost is zero:
QUESTION
I am populating the following vector with non-negative integers for a codejam problem:
...ANSWER
Answered 2021-Mar-30 at 13:43Your lambda only takes the first element into account, but obivously a pair consists of two elements. With your lambda pairs with identical first but different second elements will be considered as equal. Thus their relative order after sorting is unspecified.
If you want to sort data like the following:
QUESTION
This code is for the Google codejam competition. The below code is compiling correctly on my PC and gives the correct result for the sample code. However it is showing runtime error whenever I try to run it on the google website. I have been messing with it for one hour and still have no idea what's wrong with it.
...ANSWER
Answered 2021-Mar-26 at 19:12try this
QUESTION
What i am missing here in this code? It results in RE in Kickstart 2020 but when i test on my local machine or hackereath compiler(similar to codejam complier) code works fine.
problem link:
https://codingcompetitions.withgoogle.com/kickstart/round/000000000019ffc7/00000000001d3f56
ANSWER
Answered 2020-Aug-22 at 07:43At the print statement in which use of f is resulting in RE.
In the print statement, you should use format to output i+1 and j.
To pass all the test cases you have to sort the array to calculate number of houses by the greedy method.
QUESTION
Currently trying to learn and get better at Python through these kinds of exercises; the problem I'm trying to solve is a scheduling task, more specifically the Parent Partnering Returns task from Google Code Jam 2020.
My code passes the sample test cases, but outputs the wrong answer when submitted. I've tried to come up with many different kinds of test cases to find the cracks in my code, but none of them have led me to find the inherent issue.
My approach is to sort the list of tasks by increasing start time, then assign them to Jamie or Cameron. If one of them has an existing activity that ends before the start time to be assigned, then the other person will be assigned the activity at hand. If both do, then a valid schedule is impossible.
Screenshot of Sample taken from Code Jam Site (my code passes these test cases)
Below is the code I have, any help for finding the issue or a test case that fails would be greatly appreciated:
...ANSWER
Answered 2020-Jun-10 at 23:50I was able to break it. Test case:
QUESTION
I have gone through the below codejam question. I could not solve it on my own. So I have gone through the analysis. I know T(0,0) = 0, because sheep does not need to make any moves. But i did not understand how T(1,0)=T(0,1)=3? To solve the recurrence relation I need to know the value of T(1,0) or T(0,1) which is 3. Can any one explain me clearly? Any help will be appreciated.
https://codingcompetitions.withgoogle.com/codejamio/round/0000000000050fc5/0000000000054edd
...ANSWER
Answered 2020-May-07 at 18:13If the sheep is at (0, 1), one sheepdog will put itself at (0, 2), and the other at either (-1, 1) or (1, 1) (it doesn't matter). Then half the time the sheep will move to the target, the rest of the time to (1, 1) (or (-1, 1) if the sheepdog was on the other side).
From (1, 1), as the question says, the sheepdogs will put themselves at (2, 1) and (1, 2), and the sheep will move to either (1, 0) or (0, 1).
Let E0 be the expected number of steps from (1, 0) (or equivalently (0, 1)), and E1 be the expected number of steps from (1, 1) (or equivalently (-1, 1)).
Then E0 = 1/2 + (1+E1)/2, and E1 = 1+E0.
So E0=1/2 + (1+1+E0)/2 = 3/2 + E0/2, giving E0=3. This also gives E1=4, which agrees with the result in the question.
QUESTION
I tried downloading the example interactive problem number guessing problem. They offer a local testing tool in the Description tab, a python solution in the Analysis tab, a interactive_runner.py that runs both scripts simultaneously.
After saving the solution in a solution.py, I can run this on shell successfully with: python3 interactive_runner.py python3 local_testing_tool.py 0 -- python3 solution.py.
The problem is I can't debug it using VSCode. I tried putting all 3 files in one folder and using the following launch.json:
...ANSWER
Answered 2020-Apr-28 at 23:37The "program" argument expects only the path to a file, hence the error about there being "no such file or directory". What you want to do is take the rest of your execution line and make them arguments:
QUESTION
This is the code which I submitted in the second question of the Qualification Round of Google CodeJam but the compiler showed RunTime Error. But this runs on the Code Blocks just fine. Why is that?
Problem
Given a string of digits S, insert a minimum number of opening and closing parentheses into it such that the resulting string is balanced and each digit d is inside exactly d pairs of matching parentheses.Let the nesting of two parentheses within a string be the substring that occurs strictly between them. An opening parenthesis and a closing parenthesis that is further to its right are said to match if their nesting is empty, or if every parenthesis in their nesting matches with another parenthesis in their nesting. The nesting depth of a position p is the number of pairs of matching parentheses m such that p is included in the nesting of m.
For example, in the following strings, all digits match their nesting depth:
0((2)1),(((3))1(2)),((((4)))),((2))((2))(1). The first three strings have minimum length among those that have the same digits in the same order, but the last one does not since((22)1)also has the digits221and is shorter.
Given a string of digits S, find another string S', comprised of parentheses and digits, such that: all parentheses in S' match some other parenthesis, removing any and all parentheses from S' results in S, each digit in S' is equal to its nesting depth, and S' is of minimum length.
...ANSWER
Answered 2020-Apr-13 at 12:20I checked the description of the problem and found this:
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Install Codejam
You can use Codejam like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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