plyr | R package for splitting | Development Tools library
kandi X-RAY | plyr Summary
kandi X-RAY | plyr Summary
plyr is a set of tools for a common set of problems: you need to split up a big data structure into homogeneous pieces, apply a function to each piece and then combine all the results back together. For example, you might want to:.
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QUESTION
I am trying to find out if 3 datasets (df1, df2, df3) have any common rows (i.e. entire row is a duplicate).
I figured out how to do this for pairs of 2 datasets:
...ANSWER
Answered 2022-Apr-07 at 18:59Does this count?
QUESTION
I am a beginner in R and I am trying to solve a problem in R, which is I guess quite easy for experienced users.
The problem is the following: Customers (A, B, C) are coming in repeatedly using different programms (Prg). I would like to identify "typical sequences" of programs. Therefore, I identify the first programm, they consume, the second, and the third. In a next step, I would like to combine these information to sequences of programms by customer. For a customer first consuming Prg1, then Prg2, then Prg3, the final outcome should be "Prg1-Prg2-Prg3".
The code below produces a dataframe similar to the one I have. Prg is the Programm in the respective year, First is the first year the customer enters, Sec the second and Third the third.
The code produces columns that extract the program consumed in the first contract (Code_1_Prg), second contract (Code_2_Prg) and third contract (Code_3_Prg).
Unfortunately, I am not successful combining these 3 columns to the required goal. I tried to group by ID and save the frist element of the sequence in a new column called "chain1". Here I get the error message "Error in df %>% group_by(ID) %>% df$chain1 = df[df$Code_1_Prg != "NA", : could not find function "%>%<-", even though I am using the magrittr and dplyr packages.
...ANSWER
Answered 2022-Mar-22 at 11:08Are you looking for something like this?
QUESTION
I'm confused about the syntax of dplyr
when attempting to compute a weighted mean.
I am following David's suggestion here. The syntax is very transparent and therefore attractive, but it does not appear to work as I expected: Below the weigthed mean is computed for the whole data, rather than grouping by the B variable.
...ANSWER
Answered 2022-Feb-19 at 08:32This is very common thing that happens when package plyr
is loaded because plyr::summarise
can override dplyr::summarise
function. Just use dplyr::summarise
. It's the first thing to check if summarise
outputs unexpected results.
Another way is to detach the plyr
package before using dplyr
:
QUESTION
In the plot below, I'd like to dodge the colored shapes, but not the shape for 1
so that the dotted line would line up with 1
. The colored shapes need to be dodged so that they don't overlap one another for being at the same time point. Here's the code for generating dummy data and the plot. Is there a way to selectively dodge points that are in the same geom_point
?
ANSWER
Answered 2022-Feb-18 at 03:04One way to prevent one (or more) points from dodging would be to have two geom_point()
calls: one which is dodged (and excludes the point(s) in question, and one that is not dodged and includes the point
QUESTION
I have a data frame, with a column containing a list with different lengths:
...ANSWER
Answered 2022-Jan-05 at 00:06Update after clarification:
Another option is use stri_list2matrix
from stringi
, which is very fast.
QUESTION
I have a data table organized by id
and year
, with a frequency (freq
) value for every year where the frequency is at least 1. The start and end year may differ for every id.
Example:
...ANSWER
Answered 2021-Nov-02 at 18:20We can't use CJ
-based approaches because the missing rows need to be by-id
. An alternative is:
QUESTION
I'm an inexperienced R user and I am trying to pre-process some biological data before statistical analysis for differential expression, using linear modelling.
I want to impute values which == 1, by row in a dataframe, and I want to impute the values with the median of the row.
Here is some example data:
...ANSWER
Answered 2021-Aug-01 at 03:53You can use this Map
approach -
QUESTION
I have a list of cities and related information that I've placed in a dataframe, like so:
...ANSWER
Answered 2021-Jun-21 at 20:29# get min distance:
min_d <- sapply(dist_list, function(x) sort(x)[2])
places$min_dist <- min_d
# index:
i <- sapply(dist_list, function(x) which(sort(x)[2] == x))
# add name:
places$min_name <- places$cities[i]
QUESTION
I have the following dataframe:
...ANSWER
Answered 2021-Jun-09 at 14:53You can get shots conceded by subtracting shots
from the cumulative number of shots taken:
QUESTION
I am trying to order a table that has 3 variables, commonly known as a 3-way table.
I have attached a picture of the structure of the table the replicable code will produce.
Is it possible to order this table in a logical way, despite the fact it is essentially split into three sections/groups? For instance, could you order by the column "No" or the column "Yes" based on the values? For example, when ordering "No" England would be ordered as "Sertosa" (7), Virginica (8), Versicolour (16). Wales would be ordered Versicolor (11), Setoda (12), Virginica... and so on for each section of the table.
#Replicable code using the Iris data built into R:
...ANSWER
Answered 2021-Jun-01 at 20:07You should avoid using table()
and array()
in R, as they are hard to work with. Also, I recommend you focus on learning dplyr, rather than plyr, as plyr is no longer maintained.
Instead of using table()
, work directly with the original data frame:
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