plyr | R package for splitting | Development Tools library

 by   hadley R Version: v1.8.6 License: Non-SPDX

kandi X-RAY | plyr Summary

kandi X-RAY | plyr Summary

plyr is a R library typically used in Utilities, Development Tools applications. plyr has no bugs, it has no vulnerabilities and it has low support. However plyr has a Non-SPDX License. You can download it from GitHub.

plyr is a set of tools for a common set of problems: you need to split up a big data structure into homogeneous pieces, apply a function to each piece and then combine all the results back together. For example, you might want to:.
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            kandi-support Support

              plyr has a low active ecosystem.
              It has 482 star(s) with 118 fork(s). There are 50 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              plyr has no issues reported. There are 7 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of plyr is v1.8.6

            kandi-Quality Quality

              plyr has 0 bugs and 0 code smells.

            kandi-Security Security

              plyr has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              plyr code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              plyr has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              plyr releases are available to install and integrate.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of plyr
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            plyr Key Features

            No Key Features are available at this moment for plyr.

            plyr Examples and Code Snippets

            No Code Snippets are available at this moment for plyr.

            Community Discussions

            QUESTION

            Finding Identical Rows in Multiple Datasets
            Asked 2022-Apr-07 at 19:56

            I am trying to find out if 3 datasets (df1, df2, df3) have any common rows (i.e. entire row is a duplicate).

            I figured out how to do this for pairs of 2 datasets:

            ...

            ANSWER

            Answered 2022-Apr-07 at 18:59

            QUESTION

            Combine character variable over rows and columns by group in R
            Asked 2022-Mar-22 at 11:33

            I am a beginner in R and I am trying to solve a problem in R, which is I guess quite easy for experienced users.

            The problem is the following: Customers (A, B, C) are coming in repeatedly using different programms (Prg). I would like to identify "typical sequences" of programs. Therefore, I identify the first programm, they consume, the second, and the third. In a next step, I would like to combine these information to sequences of programms by customer. For a customer first consuming Prg1, then Prg2, then Prg3, the final outcome should be "Prg1-Prg2-Prg3".

            The code below produces a dataframe similar to the one I have. Prg is the Programm in the respective year, First is the first year the customer enters, Sec the second and Third the third.

            The code produces columns that extract the program consumed in the first contract (Code_1_Prg), second contract (Code_2_Prg) and third contract (Code_3_Prg).

            Unfortunately, I am not successful combining these 3 columns to the required goal. I tried to group by ID and save the frist element of the sequence in a new column called "chain1". Here I get the error message "Error in df %>% group_by(ID) %>% df$chain1 = df[df$Code_1_Prg != "NA", : could not find function "%>%<-", even though I am using the magrittr and dplyr packages.

            ...

            ANSWER

            Answered 2022-Mar-22 at 11:08

            Are you looking for something like this?

            Source https://stackoverflow.com/questions/71570900

            QUESTION

            calculate a weighted mean by group with dplyr (and replicate other approaches)
            Asked 2022-Feb-19 at 08:32

            I'm confused about the syntax of dplyr when attempting to compute a weighted mean.

            I am following David's suggestion here. The syntax is very transparent and therefore attractive, but it does not appear to work as I expected: Below the weigthed mean is computed for the whole data, rather than grouping by the B variable.

            ...

            ANSWER

            Answered 2022-Feb-19 at 08:32

            This is very common thing that happens when package plyr is loaded because plyr::summarise can override dplyr::summarise function. Just use dplyr::summarise. It's the first thing to check if summarise outputs unexpected results.

            Another way is to detach the plyr package before using dplyr:

            Source https://stackoverflow.com/questions/71183209

            QUESTION

            R selective ggplot geom_point(position = position_dodge())
            Asked 2022-Feb-18 at 03:04

            In the plot below, I'd like to dodge the colored shapes, but not the shape for 1 so that the dotted line would line up with 1. The colored shapes need to be dodged so that they don't overlap one another for being at the same time point. Here's the code for generating dummy data and the plot. Is there a way to selectively dodge points that are in the same geom_point?

            ...

            ANSWER

            Answered 2022-Feb-18 at 03:04

            One way to prevent one (or more) points from dodging would be to have two geom_point() calls: one which is dodged (and excludes the point(s) in question, and one that is not dodged and includes the point

            Source https://stackoverflow.com/questions/71167202

            QUESTION

            rbind a dataframe column containing list of different lengths
            Asked 2022-Jan-05 at 00:07

            I have a data frame, with a column containing a list with different lengths:

            ...

            ANSWER

            Answered 2022-Jan-05 at 00:06

            Update after clarification: Another option is use stri_list2matrix from stringi, which is very fast.

            Source https://stackoverflow.com/questions/70584064

            QUESTION

            data.table: is it possible to merge .SD and return a new 'sub data table' by group?
            Asked 2021-Nov-02 at 20:09

            I have a data table organized by id and year, with a frequency (freq) value for every year where the frequency is at least 1. The start and end year may differ for every id.

            Example:

            ...

            ANSWER

            Answered 2021-Nov-02 at 18:20

            We can't use CJ-based approaches because the missing rows need to be by-id. An alternative is:

            Source https://stackoverflow.com/questions/69815130

            QUESTION

            Imputing values which = 1, with the median of the other observations in a row. (R)
            Asked 2021-Aug-01 at 04:21

            I'm an inexperienced R user and I am trying to pre-process some biological data before statistical analysis for differential expression, using linear modelling.

            I want to impute values which == 1, by row in a dataframe, and I want to impute the values with the median of the row.

            Here is some example data:

            ...

            ANSWER

            Answered 2021-Aug-01 at 03:53

            You can use this Map approach -

            Source https://stackoverflow.com/questions/68607350

            QUESTION

            R - ggmap - calculate shortest distance between cities via geocoding
            Asked 2021-Jun-22 at 22:53

            I have a list of cities and related information that I've placed in a dataframe, like so:

            ...

            ANSWER

            Answered 2021-Jun-21 at 20:29
            # get min distance:
            min_d <- sapply(dist_list, function(x) sort(x)[2])
            places$min_dist <- min_d
            # index:
            i <- sapply(dist_list, function(x) which(sort(x)[2] == x))
            # add name:
            places$min_name <- places$cities[i]
            

            Source https://stackoverflow.com/questions/68037239

            QUESTION

            Create a column with shots conceded in R
            Asked 2021-Jun-09 at 14:53

            I have the following dataframe:

            ...

            ANSWER

            Answered 2021-Jun-09 at 14:53

            You can get shots conceded by subtracting shots from the cumulative number of shots taken:

            Source https://stackoverflow.com/questions/67905673

            QUESTION

            R, 3-way table, how to order
            Asked 2021-Jun-01 at 20:07

            I am trying to order a table that has 3 variables, commonly known as a 3-way table.

            I have attached a picture of the structure of the table the replicable code will produce.

            Is it possible to order this table in a logical way, despite the fact it is essentially split into three sections/groups? For instance, could you order by the column "No" or the column "Yes" based on the values? For example, when ordering "No" England would be ordered as "Sertosa" (7), Virginica (8), Versicolour (16). Wales would be ordered Versicolor (11), Setoda (12), Virginica... and so on for each section of the table.

            #Replicable code using the Iris data built into R:

            ...

            ANSWER

            Answered 2021-Jun-01 at 20:07

            You should avoid using table() and array() in R, as they are hard to work with. Also, I recommend you focus on learning dplyr, rather than plyr, as plyr is no longer maintained.

            Instead of using table(), work directly with the original data frame:

            Source https://stackoverflow.com/questions/67795135

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install plyr

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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