spatialEco | R package for spatial analysis | Development Tools library
kandi X-RAY | spatialEco Summary
kandi X-RAY | spatialEco Summary
spatialEco R package with utilities to support spatial data manipulation, query, sampling and modeling. Functions include models for species population density, download utilities for climate and global deforestation spatial products, spatial smoothing, multivariate separability, point process model for creating pseudo- absences and sub-sampling, polygon and point-distance landscape metrics, auto-logistic model, sampling models, cluster optimization and statistical exploratory tools.
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Community Discussions
Trending Discussions on spatialEco
QUESTION
I need to integrate the area under the curve for the O-ring statistic in Rstudio. However, the package spatialEco does not report the actual values of the O-ring statistic as you would see in the Ripley's K function from the package spatstat. Here is the code to get to the point where I am at.
...ANSWER
Answered 2021-Apr-08 at 19:01If you peek inside the o.ring function, you see this:
QUESTION
In R, there are deviations calculating the mean in function 'zonal.stats' of package 'spatialEco' compared to 'extract' in package 'raster'. For both I used a polygon as the zone field and a raster for the values.
Here is an example:
...ANSWER
Answered 2020-Jul-22 at 16:30Each algorithm is using a different number of pixels to calculate the zonal stats; thus, the difference is probably caused by that (z1 is higher than z2). According to this tiny example I would infer that zonal.stats
is less restrictive than extract
. Thus, probably zonal.stats
takes into account every value of the raster that falls inside the polygon; however, extract
only takes into account pixels whose center is found inside the polygon (check the function's documentation).
QUESTION
I am trying to apply a function to a list of data frames. The data frames are three lists of georeferenced points. I want to add one column to every data frame with information about the cell id of the cell where each point falls in.
Here is the function :
...ANSWER
Answered 2020-Jun-27 at 15:32According to the documentation of point.in.poly
, by default, it returns an sp
object. So you won't be able to assign this to a new column of your data.frames.
One approach would be to pre-initialize the a result
list and assign the output of point.in.poly
to elements of the list:
QUESTION
Outline of the Issue
I am sorry for asking a simple question, but I am new to R and I am experiencing difficulties performing tasks with maps.
I have a collection of longitude and latitude GPS points in decimal form, which were collected in the field. My aim is to plot these GPS points onto a map of Sri Lanka, which I extracted from GADM resources.
After running the code, the southern tip of Sri Lanka is protruding from the top middle of the longitude/latitude grid box rather than the whole image of Sri Lanka being visible within the longitude/latitude grid box (see image 2).
Problem:
I can produce the map of Sri Lanka independently (see image 2), and the longitude/latitude grid box separately (see image 1). However, I am having trouble plotting the map of Sri Lanka inside the latitude/longitude grid box, in conjunction with plotting the GPS points within the grid box in the correct positions that the data was collected in the field.
The desired output is evidenced in image 3 (see below). I am trying to place image 1 inside the grid box with the correct longitude/latitude scale for Sri Lanka on the edge of the grid box. Finally, I would like to plot the GPS points on the map, just like the provided example in image 3.
If anyone would be able to help me, I would be incredibly grateful!
I really cannot figure out what is going wrong here due to my lack of knowledge and after many hours of trying different R code combinations in order to solve the issue by attempting to reproduce this stack overflow question and by following this exercise on species distribution modeling.
Very kind regards.
R-code
...ANSWER
Answered 2020-May-13 at 10:48For Example 3 they have cropped the map of USA to focus on where that species occurred, whereas you want to show where the whale sightings occurred in relation to the whole country of Sri Lanka. To show both the whole country and all of the sightings you need to change your plot limits to match the extremities of the two data sources. This code should produce your desired plot, you can add ceiling
/ floor
arguments to improvement aesthetics if needed:
QUESTION
From a given matrix and vector in R
. Which is the short code way to verify if a point is in an area? (Target: get True
or False
)
What I tried at the moment:
...ANSWER
Answered 2020-May-08 at 10:44In my opinion there are two approaches, depdendently on how robust soution you require. If you do not need a high accuracy solution you can easily write the function yourself using ray tracing (ray-line intersection and point in polygon).
What I mean by "not accurate solution" is that you agree to the fact that points that lie exactly on the line or in the polygon nodes etc. will be very, very, very rarely improperly classified. In x64 computers this issue is neglectible unless you do build a high accuracy triangulation algorithm or something similar (which you probably wouldn't do in R).
In such a case it is really simple thing to do, but as mentioned before such function can sometimes fail due to floating point arithmetic precision flaws. More on this issue can be found in computational geometry books and in docs of CGAL.
The basic function could look like:
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