lsmeans | R package for least-squares means | Machine Learning library

 by   rvlenth R Version: Current License: No License

kandi X-RAY | lsmeans Summary

kandi X-RAY | lsmeans Summary

lsmeans is a R library typically used in Artificial Intelligence, Machine Learning, Deep Learning, Tensorflow applications. lsmeans has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

R package lsmeans: Least-squares means (estimated marginal means).
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              lsmeans has a low active ecosystem.
              It has 10 star(s) with 2 fork(s). There are 3 watchers for this library.
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              It had no major release in the last 6 months.
              There are 0 open issues and 11 have been closed. On average issues are closed in 6 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of lsmeans is current.

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              lsmeans has no bugs reported.

            kandi-Security Security

              lsmeans has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              lsmeans does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
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              Without a license, all rights are reserved, and you cannot use the library in your applications.

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              lsmeans releases are not available. You will need to build from source code and install.

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            lsmeans Key Features

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            lsmeans Examples and Code Snippets

            No Code Snippets are available at this moment for lsmeans.

            Community Discussions

            QUESTION

            Why isn't my mixed model loop working? (RStudio, Crossover design)
            Asked 2021-May-31 at 15:44

            I can't figure out why my loop isn't working.

            I have a database (36rows x 51columns, its name is "Seleccio") consisting of 3 factors (first 3 columns: Animal (12 animals), Diet (3 diets) and Period (3 periods)) and 48 variables (many clinical parameters) with 36 observations per column. It is a 3x3 crossover design so I want to implement a mixed model to include the Animal random effect and also Period and Diet fixed effects and the interaction between them.

            A sample of the data (but with less rows and columns):

            ...

            ANSWER

            Answered 2021-May-31 at 15:44

            I don't think i can run the model with only 6 observations, so i couldn't find why would your loop doesn't return the same as doing it one by one. Maybe the problem is with cat(colnames(Seleccio)[i]): you only want the Var names, and for i=1, 2 and 3, that code will return "Animal", "Diet" and "Period", thus messing up how you're comparing the results. Using cat(colnames(vars)[i]) might correct that. If you find a way to include more observations of Seleccio i might be able to help more.

            I would suggest you to create a list to store the output:

            Source https://stackoverflow.com/questions/67774414

            QUESTION

            Failed to contrast intercepts through emmeans in R
            Asked 2021-Apr-30 at 16:28

            I would like to test the simetry in the response of an observer to a contrast stimuli with different polarity, positive (white) and negative (black). I took the reaction time (RT) as dependent variable, along four different contrasts. It is known that the response time follows a Pieron curve whose asymptotas are placed (1) at observer threshold (Inf) and (2) at a base RT placed somewere between 250 and 450 msec. The knowledge allows us to linearize the relationship transforming the independent variable (effective contrast EC) as 1/EC^2 (tEC), so the equation linking RT to EC becomes:

            RT = m * tEC + RT0

            To test the symmetry I established the criteria: same slope and same intercept in the two polarities implies symmetry. To obtain the coefficients I made a linear model with interaction (coding trough a dummy variable for Polarity: Positive or Negative). The output of lm is clear to me, but some colegues prefer somthing more similar to an ANOVA output. So I decided to use emmeans to make the contrasts. With the slope is all right, but when computing the interceps starts the problem. The intercepts computed by lm are very different from the output of emmeans, and the conclusions are also different. In what follows I reproduce the example. The question is two fold: It is possible to use emmeans to solve my problem? If not, it is possible to make the contrasts through other packages (which one)?

            Data RT1000 EC tEC Polarity 596.3564 -25 0.001600 Negative 648.2471 -20 0.002500 Negative 770.7602 -17 0.003460 Negative 831.2971 -15 0.004444 Negative 1311.3331 15 0.004444 Positive 1173.8942 17 0.003460 Positive 1113.7240 20 0.002500 Positive 869.3635 25 0.001600 Positive Code ...

            ANSWER

            Answered 2021-Apr-30 at 16:28

            What you are calling the intercepts are not; they are the model predictions at the mean value of tEC. If you want the intercepts, use instead:

            Source https://stackoverflow.com/questions/67334851

            QUESTION

            Linear mixed model confidence intervals question
            Asked 2021-Apr-22 at 14:22

            Hoping that you can clear some confusion in my head.

            Linear mixed model is constructed with lmerTest:

            ...

            ANSWER

            Answered 2021-Apr-22 at 14:22

            I'm pretty sure this has to do with the dreaded "denominator degrees of freedom" question, i.e. what kind (if any) of finite-sample correction is being employed. tl;dr emmeans is using a Kenward-Roger correction, which is more or less the most accurate available option — the only reason not to use K-R is if you have a large data set for which it becomes unbearably slow.

            load packages, simulate data, fit model

            Source https://stackoverflow.com/questions/67203342

            QUESTION

            R - Least Squared Means Contrasts One Way ANOVA
            Asked 2021-Apr-16 at 20:52

            I am reviewing one way ANOVAs and trying to integrate least squared means. Here is an example from mtcars.

            ...

            ANSWER

            Answered 2021-Apr-16 at 17:21

            That is the work of tukeyHSD fucntion:

            Source https://stackoverflow.com/questions/67129569

            QUESTION

            R: Forest plot difference of means from lsmean?
            Asked 2021-Apr-15 at 22:41

            Hi I want to recreate a plot that looks like this?

            Here is an example, the closest I can get is a ggplot that looks like this.

            ...

            ANSWER

            Answered 2021-Apr-15 at 21:21

            Here's a two step solution. First you'll need to transform the data to get some variables that will make it easier to construct the desired plot.

            Source https://stackoverflow.com/questions/67113987

            QUESTION

            Why Typre III results is different from lsmeans results in Proc glimmix
            Asked 2021-Mar-30 at 21:27

            I am using Proc glimmix to run a random intercept model on a continuous outcome over five time points. Table Type III indicates sex is not significant while the 95% CIs of male and females in table lsmeans have no overlap. I wonder how to explain this discrepancy? When I look at the male and female outcomes over time I also expect a significant higher outcome for males as the CIs in the second table say. Many thanks!

            ...

            ANSWER

            Answered 2021-Mar-30 at 21:27

            It is incorrect to test the significance of a difference based on seeing if the CIs for the means overlap. The means and the difference of the means are two different statistical animals, with their own distributions and their own standard errors. The SE of the difference M - F is sqrt(SE(M)^2 + SE(F)^2 -2*Cov(M,F)). and that can be vastly different from SE(M) + SE(F) which is implicitly assumed when you compare confidence intervals. Moreover, in a mixed model,the degrees of freedom can differ vastly, and that covariance term can be anything.

            To get SAS to compute the right estimates, use an ESTIMATE statement to construct the desired quantity.

            Source https://stackoverflow.com/questions/66873949

            QUESTION

            Factorial - Four Way ANOVA - How to find a statistically effective combination
            Asked 2021-Mar-19 at 16:07

            I have to analyze an experiment data set to find a most effective combination of a molecular biology reaction.

            The experiment has four factors: Temperature, RPM, Time, Catalytic activity. And I am measuring the Efficiency of a reaction (EE). How can I find an effective combination of four factors for the highest efficiency(EE)?

            • No repeated measurements. All data are independent experimental data

            As I understood - EE is parametric data, factors are categorical data (Fixed combinations). Do I have to go for a Fourway ANOVA?

            if so is this model correct for the analysis

            ...

            ANSWER

            Answered 2021-Mar-18 at 03:20

            For a screening DOE you collected more data than what was needed. Here is a starting point, I welcome additional comments.

            I would model the linear combination of all of your factors:

            Source https://stackoverflow.com/questions/66684001

            QUESTION

            Specify a model with crossed and nested factors in sas proc mixed
            Asked 2021-Jan-03 at 17:01
            Brief question

            How do I write the model statement in proc mixed to study the interaction between a factor with a second factor nested within a third factor?

            • So factor_1 is independent from the others (like year is independent from location)
            • but factor_2 is a subdivision of factor_3 (like province is a subdivision of state).

            I would expect it to be model factor_1 * factor_2(factor_3); but that does not work.

            The real problem and context

            I am trying to model this Crossed - Nested Design example from an Analysis of Variance and Design of Experiments course of Eberly College of Science using the techniques from this Nested Treatment Design example and the instructions given in this video.

            Loading my data with ...

            ANSWER

            Answered 2021-Jan-03 at 17:01

            QUESTION

            Manual interaction plot linear regression in R
            Asked 2020-Oct-16 at 09:59

            I am trying to predict the mean abundance of animals sighted during different moon phases (factor), using log-transformed abundance data (better fit) and some other variables. The best model (lowest AIC) turned out to include the interaction of phase and survey duration and the cloud cover (both continuous):

            ...

            ANSWER

            Answered 2020-Oct-14 at 18:48

            Use predict to get predicted values. Don't calculate manually.

            Use expand.grid() to generate a data frame of all combinations of your dur2 sequence and the other predictors at the value(s) you want plot. Something like this:

            Source https://stackoverflow.com/questions/64358946

            QUESTION

            How To Interpret Least Square Means and Standard Error
            Asked 2020-Sep-28 at 16:09

            I am trying to understand the results I got for a fake dataset. I have two independent variables, hours, type and response pain.

            First question: How was 82.46721 calculated as the lsmeans for the first type?

            Second question: Why is the standard error exactly the same (8.24003) for both types?

            Third question: Why is the degrees of freedom 3 for both types?

            ...

            ANSWER

            Answered 2020-Sep-28 at 16:09

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            You can download it from GitHub.

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