ggraph | Grammar of Graph Graphics | Data Visualization library
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QUESTION
Simple enough question that seems to be taking a lot of time to solve. When creating a dendrogram using ggraph
, I'm trying to include a subscript in the node labels. However, I can't seem to get it to work using expression
. For example, if I create some data and a dendrogram like the one below:
ANSWER
Answered 2022-Apr-05 at 09:09This might not be the most elegant way, but you can use parse = TRUE
in geom_node_label
; for some reason it keeps expression()
, but you can get rid of that afterwards:
QUESTION
I was wondering if it is possible to plot a tidygraph object with a single node? For example, if I create some data and a tidygraph object with 2 nodes, that would look like this:
...ANSWER
Answered 2022-Mar-28 at 16:08You could create a two-row node data frame with the same row repeated twice, the same for the edges data frame. Create the plot object and remove the second row of its data component.
QUESTION
Using this reproducable example from another question. How do I label / colour the center node on which the local neighborhood graph is based. (In this case 'x')
...ANSWER
Answered 2022-Mar-28 at 10:20You can do:
QUESTION
I have a graph with each node having a value (value in red).
I would like to do the following two things (I guess 1 is a special case of 2):
Each node should be assigned the mean of the value of the direct peers directing to it. For example node #5
(1+2)/2=1.5
or node #3(0+2+0)/3=2/3
.Instead of direct neighbors, include all connected nodes but with a diffusion of times 1/n with n being the distance to the node. The further away the information is coming from the weaker signal we'd have.
I looked into functions of igraph, but could not find anything that is doing this (I might have overseen though). How could I do this computation?
Below is the code for a sample network with random values.
...ANSWER
Answered 2022-Mar-25 at 15:39Each node should be assigned the mean of the value of the direct peers directing to it.
Guessing that you really mean
Each node should be assigned the mean of the values of the direct peers directing to it, before any node values were changed
This seems trivial - maybe I am missing something?
QUESTION
Is it possible to control the horizontal order of nodes in a ggraph
tree?
- The following code creates a tree:
ANSWER
Answered 2022-Mar-12 at 15:33The graphs nodes are not in the wanted order, reorder them first. This comment has a simple way I will use below.
QUESTION
I recently asked this question about how to colour nodes by variable. And the code works great. However, I'm back trying to colour the terminal nodes separately. For example, if I create some data, then turn them into tidygraph objects and plot them using ggraph then I get something like this:
...ANSWER
Answered 2022-Feb-21 at 15:11If I understand correctly, you want to apply a different colour mapping to
the terminal nodes, mapping value
to colour rather than name
, and using
a different colour scale altogether. ggplot2
doesn’t support that directly,
but you can use e.g. ggnewscale
to apply a different scale for the rest
of the plot.
I simplified your example a bit to focus on the new scale application:
QUESTION
I'd like to modify the legend in my plot (see below) by adjusting the number of columns (e.g. from one column with nine rows to three columns and three rows). I already tried to add guides(alpha = guide_legend(ncol = 3))
to adjust the number of columns. However, that didn't work (I assume 'alpha' is not the correct argument but I can't find the appropriate one).
Example code and plot:
...ANSWER
Answered 2022-Jan-21 at 11:13It's because the alpha for edges is internally called edge_alpha
and not alpha
like the aes()
would let you believe. Therefore, you can use the scale_edge_alpha_continuous()
to define a legend:
QUESTION
I am using as_tbl_graph and ggraph to show the network relation data. I wish to keep the shape and location of each node, while changing the color with several conditions. Problem here is that every time I run the code, the full graph image changes at all. Is there a way to keep the shape of the graph, but only change the color? There are so many items so I can't designate each node's location.
...ANSWER
Answered 2022-Jan-18 at 08:08You can use the layout
argument in ggraph
to fix the graph structure, then change anything else you'd like. You can find more in the Details section of the ?ggraph
help page, in the vigentte("Layouts", package = "ggraph")
and in articles like this one.
QUESTION
required_packs <- c("pdftools","readxl","pdfsearch","tidyverse","data.table","stringr","tidytext","dplyr","igraph","NLP","tm", "quanteda", "ggraph", "topicmodels", "lasso2", "reshape2", "FSelector")
new_packs <- required_packs[!(required_packs %in% installed.packages()[,"Package"])]
if(length(new_packs)) install.packages(new_packs)
i <- 1
for (i in 1:length(required_packs)) {
sapply(required_packs[i],require, character.only = T)
}
...ANSWER
Answered 2021-Dec-27 at 20:12I think the problem is that you used T
when you meant TRUE
. For example,
QUESTION
I have been trying to create a dendrogram with hierarchical edge bundling using the ggraph package, and have run into 2 major issues.
Questions and code are revised slightly for clarity
- Firstly, the graph seems to always start from arbitrary points on the circle, while the default should be 90 degrees (12 o'clock). Setting different values for the offset argument, which should be passed to
[layout_tbl_graph_dendrogram()]
2 also has no effect. Vertices 6 and 41, connected by the red and yellow edges, should be the first and last vertices and fall near 90 degrees. - The second issue is that I wish for overlapping edges (those connecting the same vertices) to be very slightly offset, but usual ggplot2 functions such as
position_dodge()
shift the entire edge. I don't want any shifts where edges are connected to the vertices, but withoutposition_dodge()
or similar functions (or withposition_dodge(width=0)
) the red edge completely covers the yellow, as they share the same two vertices (6 and 41).
Here's a reproducible example:
...ANSWER
Answered 2021-Nov-06 at 19:12For the first problem, I just ended up taking the layout file using create_layout()
, modifying the locations of the vertices manually (doing some basic trigonometry) before sending the file to ggraph()
. For the second problem, I just found all overlapping edges and split the connections dataframe into dataframes of non-overlapping edges, then passed them to geom_conn_bundle()
functions separately and with differing tension values. It would be excellent if someone could come up with a better answer to the first problem though! Here's the repository.
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