purrr | A functional programming toolkit for R | Functional Programming library

 by   tidyverse R Version: v1.0.1 License: Non-SPDX

kandi X-RAY | purrr Summary

kandi X-RAY | purrr Summary

purrr is a R library typically used in Programming Style, Functional Programming applications. purrr has no bugs, it has no vulnerabilities and it has medium support. However purrr has a Non-SPDX License. You can download it from GitHub.

purrr enhances R’s functional programming (FP) toolkit by providing a complete and consistent set of tools for working with functions and vectors. If you’ve never heard of FP before, the best place to start is the family of map() functions which allow you to replace many for loops with code that is both more succinct and easier to read. The best place to learn about the map() functions is the iteration chapter in R for data science.
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            kandi-support Support

              purrr has a medium active ecosystem.
              It has 1144 star(s) with 237 fork(s). There are 64 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 27 open issues and 699 have been closed. On average issues are closed in 27 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of purrr is v1.0.1

            kandi-Quality Quality

              purrr has 0 bugs and 0 code smells.

            kandi-Security Security

              purrr has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              purrr code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              purrr has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              purrr releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            purrr Key Features

            No Key Features are available at this moment for purrr.

            purrr Examples and Code Snippets

            No Code Snippets are available at this moment for purrr.

            Community Discussions

            QUESTION

            How to unlist a list and keep the names of the top level as a new variable in R
            Asked 2022-Apr-14 at 12:15

            is there a simple way to unlist a list and keep the names of one level as a new variable?

            Working example:

            ...

            ANSWER

            Answered 2022-Apr-14 at 11:47

            Use data.table::rbindlist:

            Source https://stackoverflow.com/questions/71870968

            QUESTION

            Fast method of getting all the descendants of a parent
            Asked 2022-Feb-25 at 08:17

            With the parent-child relationships data frame as below:

            ...

            ANSWER

            Answered 2022-Feb-25 at 08:17

            We can use ego like below

            Source https://stackoverflow.com/questions/71022350

            QUESTION

            Iterative filtering in R
            Asked 2022-Feb-21 at 07:59

            I have a dataset of patient visits at a clinic. Each individual patient can visit on multiple occasions. Each patient is identified by a study_id and each visit by an illness_id. I want to iteratively filter the dataframe so that a visit that occurs within 28 days of a previous visit is removed.

            I cannot simply calculate the interval between all visits and then remove those which occur within 28 days. The intervals need to be calculated iteratively as the dataframe is filtered.

            In the example below you can see patient 0003 presented three times. Visit 1 is always retained. Visit 2 should be removed as it occurred 7 days after Visit 1. Once Visit 2 is removed, Visit 3 would occur 29 days after Visit 1 and so should be retained. However if I calculate all the intervals and then filter out any visits with an interval of 28 days or less, both Visits 2 and 3 would be removed (because Visit 2 occurred 7 days after Visit 1 and Visit 3 occurred 22 days after Visit 2).

            study_id illness_id illness_date 0001 000103/12/2007 2007/12/03 0002 000224/03/2008 2008/03/24 0002 000226/04/2008 2008/04/26 0002 000217/07/2008 2008/07/17 0002 000221/08/2008 2008/08/21 0002 000225/08/2008 2008/08/25 0003 000329/09/2008 2008/09/29 0003 000306/10/2008 2008/10/06 0003 000328/10/2008 2008/10/28

            The correctly filtered dataframe should be:

            study_id illness_id illness_date 0001 000103/12/2007 2007/12/03 0002 000224/03/2008 2008/03/24 0002 000226/04/2008 2008/04/26 0002 000217/07/2008 2008/07/17 0002 000221/08/2008 2008/08/21 0003 000329/09/2008 2008/09/29 0003 000328/10/2008 2008/10/28

            Thanks for any help - I am new to R and am struggling to get my head around iteration and loops. If there is a simple solution involving dplyr filter that would be great.

            IN RESPONSE TO SOME SUGGESTIONS BELOW I AM POSTING ANOTHER EXAMPLE TO TRY AND MAKE THE QUESTION CLEARER

            The 'comparator' row cannot be fixed at the first visit for each patient. It needs to roll through the dataframe as the filtering is done iteratively. Sorry if this was not clear in the OP. Here is an eg where rows 2, 3 and 5 should be removed, and rows 1, 4 and 6 should be retained.

            Row 2 is 8 days after row 1, so is removed. Row 3 is 26 days after row 1, so is removed. Row 4 is 41 days after row 1, so is retained and becomes the comparator for subsequent visits for this patient. Row 5 is 6 days after row 4, so is removed. Row 6 is 31 days after row 4 so is retained and becomes the comparator for subsequent visits for this patient.

            study_id illness_id illness_date 0001 000119/12/2007 19/12/2007 0001 000127/12/2007 27/12/2007 0001 000114/01/2008 14/01/2008 0001 000129/01/2008 29/01/2008 0001 000104/02/2008 04/02/2008 0001 000129/02/2008 29/02/2008

            Here is the v elegant solution provided by @sbarbit - sincere thanks!!

            ...

            ANSWER

            Answered 2022-Feb-18 at 13:21

            This should do the trick:

            Source https://stackoverflow.com/questions/71170603

            QUESTION

            Passing map() .x to a function
            Asked 2022-Feb-12 at 13:09

            This might seem like a silly question, but for the life of me I cannot figure it out so appreciate any help.

            I am trying to pass .x (from purrr::map) to a function so in the end I get a list of functions (I will use this eventually to pass a list of column definitions with functions inside to reactable). This is a very basic example of what I want to do:

            ...

            ANSWER

            Answered 2022-Feb-12 at 13:09

            You can get what you want by using a wrapper function to create a new function. Within the wrapper, create an empty function, set the args to the value x passed in (so if x="a", with give the equivalent of alist(a=)), and then also parse a string to the body. Then the returned list will be the functions you want.

            Source https://stackoverflow.com/questions/71090272

            QUESTION

            Using purrr::walk to save the files - invalid 'description' argument
            Asked 2022-Jan-21 at 07:57

            I have problems with saving files using looping. I first wrote a function which works well without loop. However, it always fail with loop. Can anybody tell me the reason?

            ...

            ANSWER

            Answered 2022-Jan-21 at 07:57

            The warning about condition has length is because you are passing path=path which is length 2, and the file= argument of write.csv expects length 1.

            You think that you're using walk to iterate over values, but you need to use a function or ~ quasi-function.

            This works:

            Source https://stackoverflow.com/questions/70797483

            QUESTION

            Conditional cumulative sum from two columns
            Asked 2022-Jan-16 at 23:50

            I can't get my head around the following problem.

            Assuming the follwoing data:

            ...

            ANSWER

            Answered 2022-Jan-14 at 12:56

            @tmfmnk provided an awesome answer and they deserve full credit (NOT ME)

            Below is the same code from their comment (for more visibility, while also setting an initial value)

            Source https://stackoverflow.com/questions/70710345

            QUESTION

            How to use INLINE HTML to make text white on dark background automatically after setting background from palette
            Asked 2022-Jan-16 at 09:28

            This question is somehow related but not depending to this Can you color an adjacent cell in gt table in r?:

            I am explicitly looking for the modification of the part of my code!

            I have this example dataset with colors of the background of mpg column depending on the values applied with html.

            ...

            ANSWER

            Answered 2022-Jan-16 at 09:28

            One option would be prismatic::best_contrast. By default it will not use pure white so we have to set the colors:

            Source https://stackoverflow.com/questions/70728687

            QUESTION

            Change purrr reduce column naming to numeric?
            Asked 2022-Jan-13 at 17:20

            When using purrr::reduce() to left join a large list of data frames the default is to names the columns with .x, .y, .x.x, .y.y etc..

            Is it possible to change this behaviour to obtain column names with numeric endings? e.g.

            .1, .2, .3, .4 ?

            ...

            ANSWER

            Answered 2022-Jan-13 at 13:07

            You can rename the columns first, and then merge:

            Source https://stackoverflow.com/questions/70696900

            QUESTION

            How to subset windows in a dataframe using start- and end-values from another dataframe in R?
            Asked 2022-Jan-09 at 20:18

            I have a dataframe of timeseries data, df1, that I need to extract a number of 'windows' from in R. The start- and end-points for the windows I need are in two columns of a separate dataframe, df2. The values for the start- and end-points correspond to the rownumbers of the windows required.

            In the example below I am part of the way to a solution but currently only the first window is extracted. How do I amend this example to extract all four windows? Could this be a case for purrr?

            ...

            ANSWER

            Answered 2022-Jan-09 at 15:38

            Maybe try this approach with purrr::map2

            Source https://stackoverflow.com/questions/70642567

            QUESTION

            use levene_test in map() function from purrr?
            Asked 2021-Dec-22 at 21:18

            Is there a way to do a Levene Test via the map() function from the purrr package? Or is there another simple way to compute a Levene Test over various variables?

            My data frame contains various factor and numeric columns, so I tried with map_if(), which works fine, e.g., for Shapiro tests. However, I do not know how to specify the formula. I want to test all my numeric variables against the "Treatment" factor.

            ...

            ANSWER

            Answered 2021-Dec-22 at 21:18

            The issue is that map loops over the columns and it is no longer a data.frame whereas levene_test expects a data.frame/tibble. According to ?levene_test

            data - a data frame for evaluating the formula or a model

            therefore, instead of using map_if directly, select the columns that are numeric (select(where(is.numeric))), get the column names (names), loop over those in map, select only the 'Treatment' and the looped column from the data, create the formula with reformulate and apply levene_test

            Source https://stackoverflow.com/questions/70453975

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

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            You can download it from GitHub.

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