odle | use security data parsing tool | JSON Processing library

by BuffaloWill Ruby Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(4)Vulnerabilities Install Support

kandi X-RAY | odle Summary

odle is a Ruby library typically used in Utilities, JSON Processing applications. odle has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

odle is a Ruby gem and binary that takes XML data from various security tools and outputs their JSON equivalent. The goal is to be (1) simple, (2) fast, and (3) work on many platforms with only one dependency -- nokogiri.

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Support

odle has a low active ecosystem.

It has 7 star(s) with 2 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

There are 2 open issues and 0 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of odle is current.

Quality

odle has no bugs reported.

Security

odle has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

odle does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

odle releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

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odle Key Features

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odle Examples and Code Snippets

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Community Discussions

Trending Discussions on odle

returns names but fails to count first examples

create a dict with first name as key, full name associated with the key as value

Appending values in a list in a dictionary in python

Python, counting repeated name

QUESTION

returns names but fails to count first examples

Asked 2020-Jun-07 at 10:09

This code is supposed to return the first names form the data and the return the first name and how many #times a particular name exists.

It works fine but David, the first name, comes out as David 1 David 1 , when it obviously should be # #David 2!!!!

...

ANSWER

Answered 2020-Jun-04 at 11:56

Split each element of the input list separately. Also, use collections.Counter to count the names.

Source https://stackoverflow.com/questions/62193899

QUESTION

create a dict with first name as key, full name associated with the key as value

Asked 2020-May-09 at 22:50

I have a list:

...

ANSWER

Answered 2018-Dec-21 at 17:08

As Patrick Artner suggested in the comments, use defaultdict. How about this:

Source https://stackoverflow.com/questions/53888377

QUESTION

Appending values in a list in a dictionary in python

Asked 2019-Jun-25 at 13:15

I am trying to add values to a list inside a dictionary. I have had a look at this and tried append, but I get an error.

Code:

...

ANSWER

Answered 2019-Jun-25 at 13:15

def name_counts(x):
firsts = {}
for full in x:
    part = full.split()
    fn = part[0]
    if fn not in firsts:
        firsts[fn] = []

    firsts[fn].append(full)
return(firsts)


name_list = ["David Joyner", "David Zuber", "Brenton Joyner",
         "Brenton Zuber", "Nicol Barthel", "Shelba Barthel",
         "Shelba Crowley", "Shelba Fernald", "Shelba Odle",
         "Shelba Fry", "Maren Fry"]
print(name_counts(name_list))

Source https://stackoverflow.com/questions/56753774

QUESTION

Python, counting repeated name

Asked 2019-Feb-03 at 00:03

def name_counts(alist):
    split = []
    for listitem in alist:
        split.extend(listitem.split())
    dicti = {}
    for word in split:
        if word in dicti:
            dicti[word] +=1
        else:
            dicti[word] = 0
    print(split)
    return dicti


name_list = ["David Joyner", "David Zuber", "Brenton Joyner",
             "Brenton Zuber", "Nicol Barthel", "Shelba Barthel",
             "Shelba Crowley", "Shelba Fernald", "Shelba Odle",
             "Shelba Fry", "Maren Fry"]
print(name_counts(name_list))

...

ANSWER

Answered 2019-Feb-03 at 00:03

The counts are off by 1, because the first time you see the name, you initialize that name's count to 0. If you're going to keep the current flow-control structure, you should initialize the count to 1 at that point instead of 0.

But here's a more compact version that avoids luring you into that mistake:

Source https://stackoverflow.com/questions/54498586

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