scala-cookbook | Installs the Scala programming language language | Functional Programming library

 by   RiotGamesCookbooks Ruby Version: Current License: Apache-2.0

kandi X-RAY | scala-cookbook Summary

kandi X-RAY | scala-cookbook Summary

scala-cookbook is a Ruby library typically used in Programming Style, Functional Programming applications. scala-cookbook has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Installs the Scala programming language language. See the Scala homepage.
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            kandi-support Support

              scala-cookbook has a low active ecosystem.
              It has 8 star(s) with 13 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 2 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of scala-cookbook is current.

            kandi-Quality Quality

              scala-cookbook has no bugs reported.

            kandi-Security Security

              scala-cookbook has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              scala-cookbook is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              scala-cookbook releases are not available. You will need to build from source code and install.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of scala-cookbook
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            scala-cookbook Key Features

            No Key Features are available at this moment for scala-cookbook.

            scala-cookbook Examples and Code Snippets

            No Code Snippets are available at this moment for scala-cookbook.

            Community Discussions

            QUESTION

            How to "attach" functionality to objects in Python e.g. to pandas DataFrame?
            Asked 2020-Oct-02 at 16:17

            Maybe this is more of a theoretical language question rather than pandas per-se. I have a set of function extensions that I'd like to "attach" to e.g. a pandas DataFrame without explicitly calling utility functions and passing the DataFrame as an argument i.e. to have the syntactic sugar. Extending Pandas DataFrame is also not a choice because of the inaccessible types needed to define and chain the DataFrame contructor e.g. Axes and Dtype.

            In Scala one can define an implicit class to attach functionality to an otherwise unavailable or too-complex-to-initialize object e.g. the String type can't be extended in Java AFAIR. For example the following attaches a function to a String type dynamically https://www.oreilly.com/library/view/scala-cookbook/9781449340292/ch01s11.html

            ...

            ANSWER

            Answered 2020-Oct-02 at 16:07

            In pandas, you can do:

            Source https://stackoverflow.com/questions/64174437

            QUESTION

            Scala most elegant way to handle option and throw exception from Scala Map
            Asked 2019-Jul-10 at 09:09

            I have a map and want to:

            • retrieve value without handling Option
            • log a message when there is no such the key.
            • nice to return a default value ( in addition to log a message) when the key is not present. This is optional because when the code fails here, it should not continue further.

            I have several ways of doing it

            ...

            ANSWER

            Answered 2019-Jul-10 at 09:09

            The most elegant way to throw an error is your (1):

            map.getOrElse(key, throw /* some Exception */)

            The 2nd and 3rd options should not be used: You know which actual error can happen: the map doesn't contain the key. So wrapping it in a try, or Try, is more work than necessary. And worst, it will catch other exceptions that are not meant to be. In particular Fatal exception that should not be caught.

            But, the real most elegant way to manage exceptions in scala is to actually track them with types.

            A simple generic way (but sometime too generic) is to use Try. As soon as your code might fail, everything is wrapped in Try and later code is called in map and flatMap (you can use for-comprehension to make it more readable)

            A more specific way is to use Either (from scala) or \/ from scalaz and explicit the type of error you are managing, such as \/(MissingData, String) for some MissingData class you've made. Eg:

            Source https://stackoverflow.com/questions/49254811

            QUESTION

            Is class aliasing a bad practice inside your own codebase?
            Asked 2019-Mar-22 at 09:54

            The team I work in has multiple projects, some in Java, some in PHP and some even in Python.

            There has been a discussion about class aliasing.

            Some quote Clean Code about gratuitous context and say that the namespace is enough to separate classes.

            Example:

            For MVC you have a controller, a repository and a service and the following structure:

            • Controllers/
            • Services/
            • Repositories/
            • Entities/

            In Java I would create 4 classes for :

            • User.java inside the Entities folder
            • UserRepository.java inside the Repositories folder
            • UserService.java inside the Services folder
            • UserController.java inside the Controllers folder

            In PHP my colleagues argue that they should all be named User.php and class aliasing should be used to differentiate between them when used in the same context.

            I looked and most languages do offer some form of aliasing:

            It is my understanding that class/namespace aliasing is used to either shorten class names or prevent conflict with other libraries.

            Have I been brainwashed by Java to code this way, or is it a bad practice leading to hard to read code?

            ...

            ANSWER

            Answered 2019-Mar-22 at 09:54

            Naming classes as a Controller or Service is a java convention that most of java developer follows. It is one of the many convention that we follow for good maintenance and readability of code. Nobody stops anyone for having same class name in different package. But if you ask me, it would reduce readability for sure for guys like me and we won't make any friends by doing so.

            It's like one should give class/variable name in camelcase in java classes. It's a coding convention, adopted by most Java programs. It makes reading code easier as you become use to a given standard but you don't have to follow it. It's a choice that we make

            Source https://stackoverflow.com/questions/55254113

            QUESTION

            Uninitialized variable (block cannot contain declarations)
            Asked 2018-Aug-03 at 09:39

            Following these examples and especially this code:

            ...

            ANSWER

            Answered 2018-Aug-03 at 09:29

            Here is a revised example that you can also run on Scastie:

            Source https://stackoverflow.com/questions/51668996

            QUESTION

            Scala primary constructors and the fields/properties they generate
            Asked 2017-Mar-19 at 10:28

            New to Scala and no matter how many articles/tutorials I read (like these | three | ones) I can't seem to wrap my brain around how constructors work.

            Let's take three examples of a primary constructor here:

            ...

            ANSWER

            Answered 2017-Mar-18 at 18:24

            In all the cases you showed the fields are also parameters for the constructor.

            The parameters declared to be either val or var become public members. If you use the variables in the constructor they will not become members, if you use them in the class, they will be private members.

            In first case class Fizz(buzz : Buzz){} the buzz parameter is immutable and not become member (I assume you don't use it anywhere).

            In second case class Fizz (val buzz : Buzz) {} the buzz parameter is immutable and become public member.

            In third case class Fizz (var buzz : Buzz) {} the buzz parameter is mutable and become public member.

            And again in all the cases there isn't any getter or setter created automatically.

            Source https://stackoverflow.com/questions/42877572

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install scala-cookbook

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/RiotGamesCookbooks/scala-cookbook.git

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            gh repo clone RiotGamesCookbooks/scala-cookbook

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            git@github.com:RiotGamesCookbooks/scala-cookbook.git

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