sorting | Helpful functionality | Regex library
kandi X-RAY | sorting Summary
kandi X-RAY | sorting Summary
Helpful functionality for sorting and comparing.
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- returns true if there is no empty
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QUESTION
Giving a bit of context. I'm using c++17. I'm using pointer T* data because this will interop with cuda code. I'm trying write a parallel version (on CPU) of a histogram creator. The sequential version:
ANSWER
Answered 2021-Jun-16 at 00:46The issue you are having has nothing to do with templates. You cannot invoke std::async() on a member function without binding it to an instance. Wrapping the call in a lambda does the trick.
Here's an example:
QUESTION
I have translated a program from javascript to python 3.9 and I am only missing sorting the result, but I just can't get any further.
The list consists of dicts that has an id "components", which is itself a list.
...ANSWER
Answered 2021-Jun-15 at 17:56For your original code:
QUESTION
Sorry I don't show my variables or anything, tried to give information only pertaining to the questions. This 1 Sub is huge.
Currently my code allows a user to select multiple files, the files selected will be sorted in a specific format, then loaded into 2 different arrays. Currently loads Columns D:E into 1 array and Columns I:K into another array (from selected files QSResultFileWS, and returns those arrays to my destination FormattingWS. I'm still trying to learn arrays so if the methodology I used to do this isn't proper, be gentle.
ANSWER
Answered 2021-Jun-14 at 23:12You can use the FILTER function to remove the blanks.
Replace you lines load the arrays
QUESTION
I have been trying to sort the Column values from A to Z which are populated in the List Box.
I have tried with the following but it does not adjust it. Any help will be appreciated.
...ANSWER
Answered 2021-Jun-15 at 18:37You need to sort the range using the Range.Sort method
QUESTION
I'm trying to parallelize a merge-sort algorithm. What I'm doing is dividing the input array for each thread, then merging the threads results. The way I'm trying to merge the results is something like this:
...ANSWER
Answered 2021-Jun-15 at 01:58I'm trying to parallelize a merge-sort algorithm. What I'm doing is dividing the input array for each thread, then merging the threads results.
Ok, but yours is an unnecessarily difficult approach. At each step of the merge process, you want half of your threads to wait for the other half to finish, and the most natural way for one thread to wait for another to finish is to use pthread_join(). If you wanted all of your threads to continue with more work after synchronizing then that would be different, but in this case, those that are not responsible for any more merges have nothing at all left to do.
This is what I've tried:
QUESTION
I am trying to remove duplicates based on the column item_id from a dataframe df.
df :
ANSWER
Answered 2021-Jun-15 at 14:29You can apply a function to the column that will make the item_id "uniform", then can drop_duplicates()
QUESTION
Sorting data from huge lists with two levels of keys is helpful for interpreting dataset and calling by couple or one level of keys some slice of data, especially when creating plots.
I use a very naive and, I guess, inefficient way to create from a 2D-list of data a dict of dicts (two levels of keys) that returns a list of data. How to make this code more elegant, possibly faster and more readable? I guess using collection module but I didn't find a smart way.
Example:
...ANSWER
Answered 2021-Jun-15 at 07:35from itertools import groupby
first=lambda l: l[0]
def group_by_first(listo):
grouped = groupby(sorted(listo,key=first), key=first) # group by first elem, need to sort first
return {k: [e[1:] for e in g] for k,g in grouped} # remove key (first elem) from values
{k: group_by_first(l) for k,l in group_by_first(listo).items()} # group first elem and then by second
QUESTION
In MS Access I have a table with a Short Text field named txtPMTaskDesc in which some records contains numbers, and if they do, at different positions in the string. I would like to recover these numbers from the text string if possible for sorting purposes. There are over 26000 records in the table, so I would rather handle it in a query over using VBA loops etc.
While the end goal is to recover the whole number, I was going to start with just identifying the position of the first numerical value in the string. I have tried a few things to no avail like:
...ANSWER
Answered 2021-Jun-15 at 07:02If data is truly representative and number always preceded by "- No ", then expression in query can be like:
Val(Mid(txtPMTaskDesc, InStr(txtPMTaskDesc, "- No ") + 5))
If there is no match, a 0 will return, however, if field is null, the expression will error.
If string does not have consistent pattern (numbers always in same position or preceded by some distinct character combination that can be used to locate position), don't think can get what you want without VBA. Either loop through string or explore Regular Expressions aka RegEx. Set reference to Microsoft VBScript Regular Expressions x.x library.
QUESTION
I've had trouble articulating a simple way to break this question down in to a question title, and therefore a google search.
I'm wondering if there is a sorting algorithm already defined that can sort an array of numbers without keeping pairs adjacent. Easier to explain with an example:
Values:
1,3,5,2,1,3,2,4
A normal numerical sort would come out as:
1,1,2,2,3,3,4,5
What I would like:
1,2,3,4,5,1,2,3
I could hack this together, I just want to know if there is a name for this kind of sort.
...ANSWER
Answered 2021-Jun-15 at 03:13Nothing exists, but the algorithm is simple enough:
- separate dupes into tmplist
- sort list
- add list to result
- switch list and tmplist
- repeat while list is non-empty
QUESTION
I'm currently sorting the map by value, but I couldn't think on how I would have it sorted by key for the cases that I have the same value.
Currently it works like this:
...ANSWER
Answered 2021-Jun-14 at 21:54You could check in your Comparator if the values are the same and if so compare the keys. Here is your adapted method:
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