chili | The spicy feature toggle framework for Rails | Frontend Framework library

by balvig Ruby Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | chili Summary

chili is a Ruby library typically used in User Interface, Frontend Framework, React, Framework applications. chili has no vulnerabilities, it has a Permissive License and it has low support. However chili has 13 bugs. You can download it from GitHub.

Have you ever wanted to test out a new feature on only a subset of users? Did that implementation end up being lots of if/else statements embedded in the main code? If so, Chili can help. Chili is built on top of Rails Engines and Deface and allows you to conditionally add new/modify existing views, while leaving the main code untouched.

Support

Quality

Security

License

Reuse

Support

chili has a low active ecosystem.

It has 219 star(s) with 9 fork(s). There are 5 watchers for this library.

It had no major release in the last 6 months.

There are 2 open issues and 5 have been closed. On average issues are closed in 1 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of chili is current.

Quality

chili has 13 bugs (0 blocker, 0 critical, 9 major, 4 minor) and 1 code smells.

Security

chili has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

chili code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

chili is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

chili releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

chili saves you 453 person hours of effort in developing the same functionality from scratch.

It has 1069 lines of code, 65 functions and 100 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed chili and discovered the below as its top functions. This is intended to give you an instant insight into chili implemented functionality, and help decide if they suit your requirements.

mounts the current engine .
Create a post object
Returns a feature name
Returns a path for an asset
Set whether the activity is active .
Returns true if the controller exists
Creates a new user
Search for a post

Get all kandi verified functions for this library.

chili Key Features

No Key Features are available at this moment for chili.

chili Examples and Code Snippets

No Code Snippets are available at this moment for chili.

Community Discussions

Trending Discussions on chili

Posting array of objects to REST API with ReactJS

replace() removes the whole word not the character

Delete multiple elements from List on React Native

How to filter and get array by id?

Creating new personal table for user in SQLAlchemy

Update of nested document with update function with $set results in "The positional operator did not find the match needed from the query."

Getting an error when parsing a JSONObject

Appending data to pickle in python

Trying to use inplace for a list Pandas

Trying to filter strings in list in Reactjs

QUESTION

Posting array of objects to REST API with ReactJS

Asked 2021-May-28 at 07:30

I am working on a project in which I need to post a new Course to my API. I tested this with POSTMAN and API works just fine, however when I try to post data using react fetch data is corrupted. While sending single strings like dishName: "pizza" works just fine and is shown in database I cannot manage to send an array of objects. I tried to do it in many ways like:

...

ANSWER

Answered 2021-May-27 at 21:44

You are setting the ingredients state as a string, so you are basically 'stringify' a string which will result in JSON SyntaxError. If you want to send an array that way you must specify the array bracket [ and ] in order to make it a valid array.

To solve it just change:

Source https://stackoverflow.com/questions/67730171

QUESTION

replace() removes the whole word not the character

Asked 2021-Apr-16 at 16:17

I have a dataframe with prices in $. I want to do calculations on it but the $ makes it impossible. I'm trying to remove it using df.iloc[:, 4].replace("$", " ", regex=True) but unfortunately nothing changes. If I add inplace=True then whe whole word disappears. What am I doing wrong? Tried many stackoverflow posts but nothing works. I cant use str.replace() because its about the whole column not one word.

My code:

...

ANSWER

Answered 2021-Apr-16 at 15:53

df.iloc[:, 4].replace("\$", " ", regex=True)

Source https://stackoverflow.com/questions/67128397

QUESTION

Delete multiple elements from List on React Native

Asked 2021-Mar-20 at 19:21

I am currently trying to remove from a list when I press a button. I have tried this:

...

ANSWER

Answered 2021-Mar-20 at 19:21

setCurrentSelection does the job of "setting" currentSelection (thus the name), so you don't need to also assign it with the =. Just use:

Source https://stackoverflow.com/questions/66725218

QUESTION

How to filter and get array by id?

Asked 2021-Jan-29 at 10:13

const id = [1, 4, 10]
const data =[{id: 1, name: Banana}, {id: 2, name: Mango}, {id: 3, name: Chili}, {id: 4, name: WaterMelon},  {id: 10, name: WaterMelon}]

...

ANSWER

Answered 2021-Jan-29 at 02:44

Use filter() with includes():

Source https://stackoverflow.com/questions/65947961

QUESTION

Creating new personal table for user in SQLAlchemy

Asked 2021-Jan-22 at 12:44

Can anyone assist me in solving the problem below.

I have a table in sqlalchemy called 'Person'.
Each person has a unique 'name'.
'Person' table has a relationship to 'Pet' table based on the 'name' field.

I would like everyone in the Person table have the possibility to have a pet with the same name of somebody else, but one person cannot have two pets with the same name, but I am not sure how to model/code that.

Person: Zbyszek

Pet: Flufi - age: 3
Pet: Chili - age: 2

Person: Jon

Pet: Chili - age: 4

code:

...

ANSWER

Answered 2021-Jan-22 at 12:44

You can't have the unique=True tag on the pets if there can be more than one pet with that name, even if they belong to different people. There is no problem in removing it and I don't see why you would need the name to be unique anyway since you obviously want the possibilty of multiple pets with the same name. Since the ID of the pet is unique the name doesn't have to be.

If you now want only one of each pet name available to one person, you to set that as a table argument for the pet. So that no two pets with the same owner can also have the same name.

Updated pet class:

Source https://stackoverflow.com/questions/65844905

QUESTION

Update of nested document with update function with $set results in "The positional operator did not find the match needed from the query."

Asked 2021-Jan-17 at 13:10

I am trying to change the price of middle in a second element of the document from 15.00 to 17.00:

...

ANSWER

Answered 2021-Jan-17 at 13:07

You can try arrayFilters, The filtered positional operator $[] identifies the array elements that match the arrayFilters conditions for an update operation.

try $exists operator to check is field available

Source https://stackoverflow.com/questions/65760781

QUESTION

Getting an error when parsing a JSONObject

Asked 2021-Jan-14 at 09:28

I'm trying to get a data from an online JSON, so getting the json and printing it works without issue, but when I want a particular data, my IDE give me this error

...

ANSWER

Answered 2021-Jan-13 at 18:21

You are getting an array at the top level instead of a JSON object. You should use JSONArray instead of JSONObject to parse the inital response object.

Source https://stackoverflow.com/questions/65707591

QUESTION

Appending data to pickle in python

Asked 2021-Jan-11 at 02:39

I am creating a program which generates a random list of songs, and has a function such that if a user wants to save a song from the random generated list, the user should click the button next to it. Then the user can print the songs he/she saved on a new window, and then I add a function using pickle so that if the user closes and reruns the program the previously saved items are retained and can be reprinted. But an error, how can I implement this correctly

This is the code:

...

ANSWER

Answered 2021-Jan-11 at 02:39

import pickle

lst = [1,2,3]

with open("test.dat", "wb") as msg:
    pickle.dump(lst, msg)

with open("test.dat", "ab+") as msg:
    pickle.dump(lst, msg)

with open("test.dat", "rb") as msg:
    print (pickle.load(msg))

Source https://stackoverflow.com/questions/65660651

QUESTION

Trying to use inplace for a list Pandas

Asked 2020-Nov-29 at 11:36

i have a list of doritos.

...

ANSWER

Answered 2020-Nov-28 at 17:29

you can try like this:

Source https://stackoverflow.com/questions/65052376

QUESTION

Trying to filter strings in list in Reactjs

Asked 2020-Nov-11 at 08:43

This code works, but NOT as expected. For example, typing: red displays "Red Hot Chili Peppers", but continuing with red hot, and it disappears. I am not sure, how a new RegExp should be applied in this code. I managed to come this far with the filtering.

...

ANSWER

Answered 2020-Nov-11 at 07:20

As commented:

No need for this: Object.keys(item) and item[key] === "string" as its an array of string

Your structure is an array of string. So you can directly consume the value and use String methods to validate it

If you have a complex data structure, like nested objects, then using Object.keys and then looping on them makes more sense as you do not know what keys you might need.

Source https://stackoverflow.com/questions/64781133

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install chili

First add Chili to your app's Gemfile:.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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