noober | Setting up a machine for development involves a LOT | Machine Learning library

by bjeanes Ruby Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | noober Summary

noober is a Ruby library typically used in Artificial Intelligence, Machine Learning applications. noober has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Setting up a machine for development involves a LOT of dependencies and time.

Support

Quality

Security

License

Reuse

Support

noober has a low active ecosystem.

It has 30 star(s) with 0 fork(s). There are 4 watchers for this library.

It had no major release in the last 6 months.

noober has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of noober is current.

Quality

noober has 0 bugs and 5 code smells.

Security

noober has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

noober code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

noober does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

noober releases are not available. You will need to build from source code and install.

noober saves you 276 person hours of effort in developing the same functionality from scratch.

It has 668 lines of code, 0 functions and 35 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

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noober Key Features

No Key Features are available at this moment for noober.

noober Examples and Code Snippets

No Code Snippets are available at this moment for noober.

Community Discussions

Trending Discussions on noober

How PostgreSQL function will return a table format with either select case1 or case2 based on input?

QUESTION

How PostgreSQL function will return a table format with either select case1 or case2 based on input?

Asked 2022-Mar-21 at 19:50

I am trying to do something like this. What is the right way to do it

...

ANSWER

Answered 2022-Mar-21 at 19:50

First a couple concepts need to be cleared up. In Postgres:

double quotes indicate identifiers. Therefore in your query the double quoted "values" are undefined identifiers. String/Text values are indicated by tick marks (single quotes).
A case expression can only return a single result. Thus your form case when x then (case ... end, case ... end) end is invalid as the then would be returning 2 values. While a case expression can return only a single result that result may be a tuple. IE case when ... then (a,b) end is valid.

Further as is your returns null if age = 30. That is kept.

Source https://stackoverflow.com/questions/71562002

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install noober

You can download it from GitHub.
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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