woodford | Small management app for running the Internet Cafe
kandi X-RAY | woodford Summary
kandi X-RAY | woodford Summary
Small management app for running the Internet Cafe at the Woodford Folk Festival
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- Loads a Ruby Rails gem with the given Rails name .
- Loads the configuration .
- Initialize the config file .
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Trending Discussions on woodford
QUESTION
I am coding a book store, and am checking if everything works correctly. I am currently creating a method for employees to add books into the built in Inventory of books written into the file, and am trying to display the information using the split method. When testing the add_book method in the Inventory class, it prints the first book's information, and then gives a list index out of range error. Please help if possible. This is the code -
...ANSWER
Answered 2020-Oct-28 at 19:33Your list index out of range means that your call to the split() method didn't find anything to split on. Therefore, there wouldn't be an index 1 (no splits, only one index), causing a list index out of range error to be thrown
QUESTION
I am coding a Shopping Website in Python, and am having trouble with the 4th option in the code, the checkout, since if a user tries to checkout without entering any data in, it will give an error, and I'm not sure how to fix this, since if I just make a cart, it will overwrite the data. Here is the code -
...ANSWER
Answered 2020-Oct-14 at 13:56Right now, you have a couple of problems. The first is that every time you call Cart's add_book function, you overwriting the list of books. The easiest way to fix this is to move cartlist to Cart's __init__ method. You can do this without losing the functionality of Inventory's __init__ with a call to super, like so:
QUESTION
I currently have an excel sheet where the format is like this:
...ANSWER
Answered 2020-Jun-09 at 20:19You can use T + reset_index
QUESTION
ANSWER
Answered 2019-Aug-20 at 10:33If it's a simple dictionary inside each cell, to get the value you can use:
QUESTION
I have two dictionaries. The first one looks like this:
...ANSWER
Answered 2019-Apr-28 at 21:43import numpy as np
import pandas as pd
# i used these names for the dictionaries to not get confused
number_dict = {'15': ['monter', 'boulangerie'], ... }
score_dict = {"beau": ['1', '3', '2'], ... }
# initialise output
out_dict = {}
for number_entry in number_dict:
score_keys = number_dict.get(number_entry)
# intialise scores
temp_score = np.zeros((1,3))
for score_key in score_keys:
# if there is an entry for that word, add its scores to the temp scores
if score_dict.get(score_key):
temp_score += np.array(score_dict.get(score_key), dtype=np.int32)
# assign temp scores to output dictionary
out_dict[int(number_entry)] = [a for a in temp_score.ravel()]
# convert to dataframe, transpose and rename columns
df = pd.DataFrame(out_dict)
df = df.T
df.columns = ['Positive_score', 'Neutral_score', 'Negative_score']
filename = 'filename.csv'
# save to csv with ';' as separator
df.to_csv(filename, sep=';')
QUESTION
I have, in column A, a series of different values. Like:
...ANSWER
Answered 2019-Apr-15 at 02:14May try something Like (if i understood the question correctly)
QUESTION
I have loaded in a dataframe with a number of columns, one of which includes an address. I'm using a python geocoder module to get lat/long for every address in this csv.
Pandas
1) How do I add new columns? Should I add the columns as I iterrate through the rows, or should I add columns at the start?
2) In my code below, I am trying to iterate through every row in the data frame. For every row, I am performing the geocoder.google() method. Column 16 of my csv/data frame contains an address.
How would I refer to that address column whilst iterating through all the rows? I get "IndexError: tuple index out of range" if I run the code as it is.
CSV
3) The 2nd part of my code does a similar thing with the CSV modules. I read in a CSV, loop through every row and perform the geocoder method as said before. The geocoder method returns a list of 2 values (2 coordinates - [XXXX,XXXX]). I am trying to write to the original rows and then two more columns with each of the two coordinates afterwards. I am getting "TypeError: can only concatenate list (not "float") to list"
...ANSWER
Answered 2017-Jun-27 at 15:36You can create new columns in a pandas dataframe similar to how you would use an associative array or dictionary. You can create two new columns for your latitude and longitude like so:
QUESTION
I have a table view cell that is supposed to display just a label but it wont show anything at all when I run my app. I have even tried changing the textLabels within my code but still nothing. I tried changing the cell background color as well which worked in the storyboard but when I actually run the app nothing changes. I have disconnected my view controller entirely to see if my code was the issue and still nothing happened so from what I see is its not my code but the view itself. I could be wrong though. Here is what my view loks like now: tableviewdata
...ANSWER
Answered 2018-May-17 at 15:35You have to reload data after fetch course , your table name is arg
self.arg.reloadData() when finish fetching courses
after that line
QUESTION
I wanted to hide Optionset values on Field Service - Dynamics 365 app. We are doing customizations using Woodford Solution. Based on Resco Javascript Bridge Reference, I see no methods to hide options in existing Option Set. So I created a ComboBox and tried to add Options into ComboBox. But it is showing only one single option even if I add multiple options that too with the wrong Label on ComboBox.
...ANSWER
Answered 2017-Aug-27 at 11:43You're nesting your loops with the same variable name. Give each loop a unique variable: i, j, k...
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On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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