bridgetown | generation progressive site generator & fullstack framework | Static Site Generator library

by bridgetownrb Ruby Version: v1.3.0.beta1 License: MIT

X-Ray Key Features Code Snippets Community Discussions(8)Vulnerabilities Install Support

kandi X-RAY | bridgetown Summary

bridgetown is a Ruby library typically used in Web Site, Static Site Generator, Webpack, Jekyll applications. bridgetown has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

A next-generation progressive site generator & fullstack framework, powered by Ruby

Support

Quality

Security

License

Reuse

Support

bridgetown has a medium active ecosystem.

It has 947 star(s) with 102 fork(s). There are 12 watchers for this library.

There were 1 major release(s) in the last 12 months.

There are 59 open issues and 272 have been closed. On average issues are closed in 47 days. There are 8 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of bridgetown is v1.3.0.beta1

Quality

bridgetown has 0 bugs and 0 code smells.

Security

bridgetown has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

bridgetown code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

bridgetown is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

bridgetown releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

bridgetown saves you 9183 person hours of effort in developing the same functionality from scratch.

It has 20825 lines of code, 1295 functions and 374 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed bridgetown and discovered the below as its top functions. This is intended to give you an instant insight into bridgetown implemented functionality, and help decide if they suit your requirements.

Renders a markdown markdown indentation .
Generates the JavaScript script for the web script .
Adds default values to the collection .
Set the application
Convert the html to HTML
Returns the title of the page
Check the docs for the docs

Get all kandi verified functions for this library.

bridgetown Key Features

No Key Features are available at this moment for bridgetown.

bridgetown Examples and Code Snippets

No Code Snippets are available at this moment for bridgetown.

Community Discussions

Trending Discussions on bridgetown

How to count changes within each column and in SQL

While loop data not appending to list outside of while loop

How do you calculate the distribution of frequencies in a list in Python?

How to use for/ in loop

Match consecutive vowels

Convert CSV to Objects

Reverse lookup Dictionary

Why will to_datetime handle positive timezones (UTC+) fine, but not negative timezones (UTC-)?

QUESTION

How to count changes within each column and in SQL

Asked 2022-Jan-21 at 15:01

This is how the table is looking like:

id city address steps date 1 null null a 2021-11-01 1 NY null b 2021-11-04 1 Chicago null c 2021-11-05 2 SF 33, ABC colony x 2021-12-01 2 SF 33, ABC colony y 2021-12-04 2 SF 44, Kang Street z 2021-12-05 3 Austin null i 2022-01-01 3 Austin 12, Bridgetown j 2022-01-04 3 Austin null k 2022-01-05

What I want is total count of times that for any 'id' there was an update in fields city and address only but excluding null. We dont care about the column steps and any updates there.

For id = 1, the city was changed from null to NY to Chicago. However, the address remained null, but the given the dates I count it as 2. Changing from null to NY is not supposed to be counted as an update.

For id = 2, the city was never changed it was always SF. But, there is a change in address but only once and thus we count the update as 2 again.

For id = 3, the city was never changed but the address changed from null to an address back to null. We don't count the first null because the customer may not have the info but if he/she changes it back to null that has to be counted. Here also update count will be 2.

I am expecting the results as:

id change_count 1 2 2 2 3 2

Can I know how to do this via sql? The major problem is to not count "null" as I rank the id in ascending order of when the record came but count when it is changed back to "null" is where I am mainly confused.

Any help is appreciated. I am working on it and if I get the SQL finalized, I will share it here too.

...

ANSWER

Answered 2022-Jan-20 at 23:51

I tired using combination of window-function lag and coalesce method and I finally got the answer but if someone has a better solution, do suggest. :)

My sql:

Source https://stackoverflow.com/questions/70792171

QUESTION

While loop data not appending to list outside of while loop

Asked 2022-Jan-11 at 18:39

I am trying to scrape data, write it to a pd series then go into a while loop for the remaining pages of the website appending to the original series (located outside of the while loop) after each iteration. I'm not sure why this isn't working. Here's where I'm stuck:

...

ANSWER

Answered 2022-Jan-11 at 18:39

The problem is you're treating pd.Series as a list, but the former are immutable while the later are mutable. This means, appending data to a list works like this:

Source https://stackoverflow.com/questions/70671647

QUESTION

How do you calculate the distribution of frequencies in a list in Python?

Asked 2021-Dec-16 at 12:57

I may just be using the wrong words to search for this question, cause it doesn't strike me as that complicated, but can't seem to find an answer on StackOverflow

I have a list of strings;

...

ANSWER

Answered 2021-Dec-16 at 12:49

You can use collections.Counter to build a frequency map, where the key is a unique string, and the value is the frequency.

After that, your queries become straightforward.

Source https://stackoverflow.com/questions/70379244

QUESTION

How to use for/ in loop

Asked 2021-Mar-04 at 02:55

I am new to this I am trying to use a for/in loop with my code. I have a code that works but I would like it to work in a for/in loop.

This is the source:

...

ANSWER

Answered 2021-Mar-03 at 20:22

The for loop version of the list comprehension would be

Source https://stackoverflow.com/questions/66464345

QUESTION

Match consecutive vowels

Asked 2021-Feb-28 at 23:42

I am trying to match capital cities that contain three consecutive vowels.

I tried this method with this code. It works if I don't have any commas.

...

ANSWER

Answered 2021-Feb-28 at 03:09

Try this:

Source https://stackoverflow.com/questions/66405438

QUESTION

Convert CSV to Objects

Asked 2021-Feb-03 at 22:06

Considering the below string which contains countries and their capitals in csv format.

...

ANSWER

Answered 2021-Feb-03 at 21:58

One of the many solutions:

Source https://stackoverflow.com/questions/66036159

QUESTION

Reverse lookup Dictionary

Asked 2020-Oct-06 at 11:35

I have the following dictionary and I would like to do a reverse lookup.

...

ANSWER

Answered 2020-Oct-06 at 11:28

You can use dict.setdefault() with default list ([]) and then append the country in it:

Source https://stackoverflow.com/questions/64224788

QUESTION

Why will to_datetime handle positive timezones (UTC+) fine, but not negative timezones (UTC-)?

Asked 2020-Aug-29 at 04:46

I've been using Pandas to convert a .CSV file into a format that's readable on another system and I'm close to finishing it, but I just can't get it to work with timezones that are negative (UTC-1, -2 etc)

Here is the code I'm using, it's not the tidiest, but it gets the job done for UTC+ timezones, can you see why it might not be handling UTC- timezones correctly?

...

ANSWER

Answered 2020-Aug-29 at 01:03

Your "minus" signs are not all minus signs. For example in your error message:

Source https://stackoverflow.com/questions/63640234

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install bridgetown

You can download it from GitHub.
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

Support

Bridgetown development is spearheaded by Portland-based web studio Whitefusion. Contact us if you need commercial support for your Bridgetown content strategy, site design, or deployment. Also providing commercial support: Radioactive Toy based in the UK.

Find more information at: