bridgetown | generation progressive site generator & fullstack framework | Static Site Generator library
kandi X-RAY | bridgetown Summary
kandi X-RAY | bridgetown Summary
A next-generation progressive site generator & fullstack framework, powered by Ruby
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Top functions reviewed by kandi - BETA
- Renders a markdown markdown indentation .
- Generates the JavaScript script for the web script .
- Adds default values to the collection .
- Set the application
- Convert the html to HTML
- Returns the title of the page
- Check the docs for the docs
bridgetown Key Features
bridgetown Examples and Code Snippets
Community Discussions
Trending Discussions on bridgetown
QUESTION
This is how the table is looking like:
id city address steps date 1 null null a 2021-11-01 1 NY null b 2021-11-04 1 Chicago null c 2021-11-05 2 SF 33, ABC colony x 2021-12-01 2 SF 33, ABC colony y 2021-12-04 2 SF 44, Kang Street z 2021-12-05 3 Austin null i 2022-01-01 3 Austin 12, Bridgetown j 2022-01-04 3 Austin null k 2022-01-05What I want is total count of times that for any 'id' there was an update in fields city and address only but excluding null. We dont care about the column steps and any updates there.
For id = 1, the city was changed from null to NY to Chicago. However, the address remained null, but the given the dates I count it as 2. Changing from null to NY is not supposed to be counted as an update.
For id = 2, the city was never changed it was always SF. But, there is a change in address but only once and thus we count the update as 2 again.
For id = 3, the city was never changed but the address changed from null to an address back to null. We don't count the first null because the customer may not have the info but if he/she changes it back to null that has to be counted. Here also update count will be 2.
I am expecting the results as:
id change_count 1 2 2 2 3 2Can I know how to do this via sql? The major problem is to not count "null" as I rank the id in ascending order of when the record came but count when it is changed back to "null" is where I am mainly confused.
Any help is appreciated. I am working on it and if I get the SQL finalized, I will share it here too.
...ANSWER
Answered 2022-Jan-20 at 23:51I tired using combination of window-function lag and coalesce method and I finally got the answer but if someone has a better solution, do suggest. :)
My sql:
QUESTION
I am trying to scrape data, write it to a pd series then go into a while loop for the remaining pages of the website appending to the original series (located outside of the while loop) after each iteration. I'm not sure why this isn't working. Here's where I'm stuck:
...ANSWER
Answered 2022-Jan-11 at 18:39The problem is you're treating pd.Series as a list, but the former are immutable while the later are mutable. This means, appending data to a list works like this:
QUESTION
I may just be using the wrong words to search for this question, cause it doesn't strike me as that complicated, but can't seem to find an answer on StackOverflow
I have a list of strings;
...ANSWER
Answered 2021-Dec-16 at 12:49You can use collections.Counter to build a frequency map, where the key is a unique string, and the value is the frequency.
After that, your queries become straightforward.
QUESTION
I am new to this I am trying to use a for/in loop with my code. I have a code that works but I would like it to work in a for/in loop.
This is the source:
...ANSWER
Answered 2021-Mar-03 at 20:22The for loop version of the list comprehension would be
QUESTION
I am trying to match capital cities that contain three consecutive vowels.
I tried this method with this code. It works if I don't have any commas.
...ANSWER
Answered 2021-Feb-28 at 03:09Try this:
QUESTION
Considering the below string which contains countries and their capitals in csv format.
...ANSWER
Answered 2021-Feb-03 at 21:58One of the many solutions:
QUESTION
I have the following dictionary and I would like to do a reverse lookup.
...ANSWER
Answered 2020-Oct-06 at 11:28You can use dict.setdefault() with default list ([]) and then append the country in it:
QUESTION
I've been using Pandas to convert a .CSV file into a format that's readable on another system and I'm close to finishing it, but I just can't get it to work with timezones that are negative (UTC-1, -2 etc)
Here is the code I'm using, it's not the tidiest, but it gets the job done for UTC+ timezones, can you see why it might not be handling UTC- timezones correctly?
...ANSWER
Answered 2020-Aug-29 at 01:03Your "minus" signs are not all minus signs. For example in your error message:
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On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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