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QUESTION
I have json object whose property values are unique and can be anything;
...ANSWER
Answered 2021-Jun-09 at 05:40You can try this
QUESTION
I have a table in the following format :
owner_id question response created_at 1 dog_name Rex 2021-05-31 1 cat_name Old Kitty 2021-05-01 1 cat_name New Kitty 2021-05-30 2 cat_name Bella 2021-05-28 3 bird_name Birdy 2021-05-28And I would like to be able have the list of owner with each pet's name :
owner_id dog_name cat_name bird_name 1 Rex New Kitty NULL 2 NULL Bella NULL 3 NULL NULL BirdyI have manage to list all the data that I need with the following query :
...ANSWER
Answered 2021-Jun-01 at 14:30You could use CTE's. Easy to read, but this could get pretty long if having multiple pet names. Not sure how you want to handle occasions where someone has more than one pet of same species, so that would impact this answer, too.
QUESTION
I am a total script kitty at best and am trying to use google apps scripts to automate a process for me. Here a sample table like the one I am working with(data is in google sheets spreadsheet):
Variety Category Peter Courtney DP HBC 0.00 4.5 DP MNG 2.00 0 UB THN 7.00 0 471H THN 5.00 0 471H THN 0.00 5 GRH FST 4.00 0 GRH THN 8.00 0 GRH THN 0.00 8 GRH THN 0.00 8 HM HBC 6.50 0 HM HBC 0.00 6.5 HM MNG 2.00 0 HM MNG 0.00 2 CL HBC 8.50 0 CL HBC 7.00 0 PSV HBC 2.50 0 PSV HBC 7.00 0 PSV HBC 0.00 2.5The table shows the employees reported hours broken down by Variety and category. My goal is to compile this data so if the employees work at the same category and same variety I want all hours expressed in a single line. For instance if you look at the last two rows of the data you'll notice that the Variety and Category columns are matching which means the data should be compiled. So instead of:
Variety Category Peter Courtney PSV HBC 7.00 0 PSV HBC 0.00 2.5I want to compile the data like this:
Variety Category Peter Courtney PSV HBC 7.00 2.5I am trying to do this from the bottom up because I heard going from the top down can cause issues but I am open to any suggestions. I think I need to write a for loop that compares the variety box of the active row to the variety box of the above row AND compares if the category box of the active row is equal to the category box of the above row and if both are true add the hours of both the "Peter" column and "Courtney" column.
I know there is more to do on top of that but this for loop is what I really need help on, unless you can suggest a better way?
Thanks for looking at my work, JP
Stackoverflow member Ruben has asked me to elaborate more, here is where I am at:
I found a stackoverflow answer that pushed me in the direction of how to parse the data with the for loop. Here is the for loop skeleton I am working with:
...ANSWER
Answered 2021-May-28 at 13:43If you are open to using a formula instead of script, I can propose a solution. (In my own practice of decades, I save script for only those times when formulas cannot produce the desired result; this cuts down greatly on potential problems.)
This solution uses information from the script in your post to ascertain that the name of the source sheet is 'gest' and the ranges of data to include in the new report are B:C and E:F.
Create a new sheet and place the following formula in cell A1:
=ArrayFormula({gest!B1:C1, gest!E1:F1; QUERY({gest!B2:C, E2:F},"Select Col1, Col2, SUM(Col3), SUM(Col4) WHERE Col1 Is Not Null GROUP BY Col1, Col2 LABEL SUM(Col3) '', SUM(Col4) ''")})
This single formula will produce all headers and results, and will "keep up" as you add new rows of data in the 'gest' sheet.
A virtual array is formed between the curly brackets { }. This is a way of "sticking together" non-contiguous data in new ways.
The headers are grabbed by the two references preceding the semicolon.
Then a QUERY
is formed from the non-header information in the target columns.
In plain English, the Select
clause of the QUERY
reads "Return four columns: exactly what is in the first requested column and the second requested column followed by the categorized sums from the third and fourth requested columns, separating (i.e., "GROUP
ing") those sums by each unique pairing from the first two columns." The LABEL
section just removes technical headers from the sum columns created (which would otherwise have placed stock headers of 'sum' above each of the summed columns).
QUESTION
I'm new to Rust and a frequent user of MongoDB. I usually use node.js
+ Mongoose ODM
.
Is there any MongoDB ODM in RUST that implements a custom schema and business logic hooks like Mongoose ODM ? Or do I need to implement it myself inside the Rust's type system?
This is an example from Mongoose
...ANSWER
Answered 2021-Mar-16 at 15:56You may not need an ODM. With serde (which is used by all those ODMs), the "schema" is implemented on the struct itself, so you can add any methods you want with an impl
block. It would look something like this:
QUESTION
I have a simple struct in a custom pallet:
...ANSWER
Answered 2021-May-24 at 06:50my bad, had to add:
QUESTION
I have a data like this below,
...ANSWER
Answered 2021-May-16 at 15:06Have you tried DISTINCT ON
?
A similar case to yours on Stack Overflow: sql - Remove duplicate rows based on field in a select query with PostgreSQL? - Stack Overflow
Example:
QUESTION
My text disappears when I hover over it. I tried removing the hidden and putting the visibility: visible and I changed the opacity to 1 but I still keep getting the same - the text still disappears when I hover. I am trying to make the text stay the same and do nothing when I hover. The weird thing is I have a box border around it and when I hover the whole lower part disappears with it so half the box and the text disappear too. Am I missing something else?
...ANSWER
Answered 2021-May-10 at 14:59Remove the visibility: hidden;
and then run the program again, that worked when I tried it.
QUESTION
ANSWER
Answered 2021-May-12 at 07:01Note: I haven't tried this out fully but what you need is an outer dictionary (where type is the key and value is a list of pets of that type)
QUESTION
I have this text that I want to read the first column from in my project named Data.txt.
...ANSWER
Answered 2021-May-05 at 02:31You're sort-of on the right track with the delimeters. Here's how I did it and it can be cleaned up a bit, and you'll have to make a for loop to iterate through the arraylist and get each one, and split each one and print each one's 0'th index ( "str" is the string/text file you provided )
QUESTION
ANSWER
Answered 2021-Apr-28 at 10:08App 1 has sapUiSizeCompact
in the class list of (see
index.html
at line 34).
App 2 doesn't have it, in which case the default density class is applied (sapUiSizeCozy
).
For more information and other density options, see the step Content Density from the walkthrough as well as the corresponding topic from the documentation.
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