vj | vj - JSON Humanizer | JSON Processing library

 by   busyloop Ruby Version: Current License: BSD-2-Clause

kandi X-RAY | vj Summary

kandi X-RAY | vj Summary

vj is a Ruby library typically used in Utilities, JSON Processing applications. vj has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

vj - JSON Humanizer
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            kandi-support Support

              vj has a low active ecosystem.
              It has 53 star(s) with 2 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 2 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of vj is current.

            kandi-Quality Quality

              vj has 0 bugs and 0 code smells.

            kandi-Security Security

              vj has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              vj code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              vj is licensed under the BSD-2-Clause License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              vj releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.
              vj saves you 36 person hours of effort in developing the same functionality from scratch.
              It has 96 lines of code, 2 functions and 2 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed vj and discovered the below as its top functions. This is intended to give you an instant insight into vj implemented functionality, and help decide if they suit your requirements.
            • Run a command .
            • RGB color .
            Get all kandi verified functions for this library.

            vj Key Features

            No Key Features are available at this moment for vj.

            vj Examples and Code Snippets

            No Code Snippets are available at this moment for vj.

            Community Discussions

            QUESTION

            Function works normally. But when used with sapply in order to pass each value of a vector as one of the arguments, I get an error
            Asked 2022-Feb-18 at 20:51

            Sorry for the bad phrasing of the question!

            I created a function, abc, and it works fine with my data table, DT, by itself.

            ...

            ANSWER

            Answered 2022-Feb-18 at 20:28

            sapply iterates only over the first argument provided, so you would need to change the function call to something like:

            Source https://stackoverflow.com/questions/71179350

            QUESTION

            p5.js: Why is my image duplicating every time I use the keyPressed() function?
            Asked 2022-Jan-10 at 09:31

            I am trying to navigate the legoman image across the canvas using the arrow keys. However, the image seems to duplicate instead (see image).

            legoman p5.js

            How do I get the image to move without leaving a trail of images behind?

            See code:

            ...

            ANSWER

            Answered 2022-Jan-10 at 09:31

            The issue is no longer present in the p5 editor sketch you've shared.

            That is because you're calling

            Source https://stackoverflow.com/questions/70645611

            QUESTION

            Solving this rectangular, nonlinear system with SciPy
            Asked 2022-Jan-07 at 09:35
            Background.

            I'm attempting to write a python implementation of this answer over on Math SE. You may find the following background to be useful.

            Problem

            I have an experimental setup consisting of three (3) receivers, with known locations [xi, yi, zi], and a transmitter with unknown location [x,y,z] emitting a signal at known velocity v. This signal arrives at the receivers at known times ti. The time of emission, t, is unknown.

            I wish to find the angle of arrival (i.e. the transmitter's polar coordinates theta and phi), given only this information.

            Solution

            It is not possible to locate the transmitter exactly with only three (3) receivers, except in a handful of unique cases (there are several great answers across Math SE explaining why this is the case). In general, at least four (and, in practice, >>4) receivers are required to uniquely determine the rectangular coordinates of the transmitter.

            The direction to the transmitter, however, may be "reliably" estimated. Letting vi be the vector representing the location of receiver i, ti being the time of signal arrival at receiver i, and n be the vector representing the unit vector pointing in the (approximate) direction of the transmitter, we obtain the following equations:

            = v(ti - tj)

            (where < > denotes the scalar product)

            ...for all pairs of indices i,j. Together with |n| = 1, the system has 2 solutions in general, symmetric by reflection in the plane through vi/vj/vk. We may then determine phi and theta by simply writing n in polar coordinates.

            Implementation.

            I've attempted to write a python implementation of the above solution, using scipy's fsolve.

            ...

            ANSWER

            Answered 2022-Jan-07 at 09:35

            As you already mentioned, fsolve expects a system with N variables and N equations, i.e. it finds a root of the function F: R^N -> R^N. Since you have four equations, you simply need to add a fourth variable. Note also that fsolve is a legacy function, and it's recommended to use root instead. Last but not least, note that sqrt(x^2+y^2+z^2) = 1 is equivalent to x^2+y^2+z^2=1 and that the latter is much less susceptible to rounding errors caused by the finite differences when approximating the jacobian of F.

            Long story short, your class should look like this:

            Source https://stackoverflow.com/questions/70617656

            QUESTION

            repeat the click only on the last button pressed in jquery
            Asked 2021-Nov-13 at 15:17

            I have a number of buttons on a page. Each button has a different ID. After clicking on any of the buttons, the chat information is displayed. After clicking the button, I want this to be done automatically again.

            Problem :

            If I click on one button(start chat) first and then the other, the system clicks on two buttons. But I want to repeat the click only on the last button pressed.

            I used the following code, but the two buttons are clicked.

            ...

            ANSWER

            Answered 2021-Nov-13 at 15:17

            I just wrote a html code for you with jQuery and Bootstrap

            You just need to create a new setTimeout function to click the same button again, on first click of the respective button.

            This will create a loop and keep your one of the last clicked button automatically clicking.

            Source https://stackoverflow.com/questions/69951639

            QUESTION

            Sort nested array of objects based on parent level and nested level
            Asked 2021-Nov-11 at 08:16

            I want to sort an array of objects with parent category name and nested category name alphabetically.

            ...

            ANSWER

            Answered 2021-Nov-11 at 08:16

            I'm assuming you want case insensitiveness. In that case:

            Source https://stackoverflow.com/questions/69924538

            QUESTION

            Gradient exploding problem in a graph neural network
            Asked 2021-Oct-29 at 16:33

            I have a gradient exploding problem which I couldn't solve after trying for several days. I implemented a custom message passing graph neural network in TensorFlow which is used to predict a continuous value from graph data. Each graph is associated with one target value. Each node of a graph is represented by a node attribute vector, and the edges between nodes are represented by an edge attribute vector.

            Within a message passing layer, node attributes are updated in a certain way (e.g., by aggregating other node/edge attributes), and these updated node attributes are returned.

            Now, I managed to figure out where the gradient problem occurs in my code. I have the below snippet.

            ...

            ANSWER

            Answered 2021-Oct-29 at 16:33

            Looks great, as you have already followed most of the solutions to resolve gradient exploding problem. Below is the list of all solutions you can try

            Solutions to avoid Gradient Exploding problem

            1. Appropriate Weight initialization: utilise appropriate weight Initialization based on the activation function used.

              Initialization Activation Function He ReLU & variants LeCun SELU Glorot Softmax, Logistic, None, Tanh
            2. Redesigning your Neural network: use fewer layers in neural network and/or use smaller batch size

            3. Choosing Non Saturation activation function: choose the right activation function with reduced learning rates

              • ReLU
              • Leaky ReLU
              • randomized leaky ReLU (RReLU)
              • parametric leaky ReLU (PReLU)
              • exponential linear unit (ELU)
            4. Batch Normalisation: Ideally using batch normalisation before/after each layer, based on what works best for your dataset.

            Source https://stackoverflow.com/questions/69427103

            QUESTION

            Reading in a pandas column as a base64 string
            Asked 2021-Oct-21 at 02:10

            I have a csv file that I have read into Pandas. One of the columns in the csv contains a base64 encoded value but it gets read in by Pandas as a string. How would I go about converting this value (now read in as a string) back to a useable base64 value. The structure looks like this.

            I have an example here:

            ...

            ANSWER

            Answered 2021-Oct-21 at 01:26

            Ok I think I've found out your issue. Let's download a fresh file to use as an example and work with that. I'm working with a small snippet of a gray square.

            Source https://stackoverflow.com/questions/69610583

            QUESTION

            Azure AD SAML using Common Certificate instead of app specific
            Asked 2021-Oct-12 at 11:07

            So my observations and expectations is that when I configure an app for Single-Sign On, the certificate for that specific application will be used.

            However I have some already registered applications that do not use these cert, but rather sign the assertion with one of the certificates from Common Metadata. My question is: is there a way to configure this behaviour? I have tried to mimic the configuration in a new app, but cannot get the same behaviour.

            What I have have observed about the configuration of these apps:

            • All these have at some point "talked to" ADFS - and have also used WS-FED (that is the goal here)
            • Even if I try to access the app through MyApps, and there is 'nothing' answering, the signature will be with the common cert.
            • I believe they all use App Proxy (With Azure AD pre-auth)
            • They seem to have the Tags (8adf8e6e-67b2-4cf2-a259-e3dc5476c621, WindowsAzureActiveDirectoryGalleryApplicationNonPrimaryV1) which I do not get when I create a new SAML app.

            This is what the assertion looks like:

            ...

            ANSWER

            Answered 2021-Oct-12 at 11:07

            Seems to be a bug/weird situation. I had one detail wrong; it actually was using the Certificate that was on the enterprise application..

            However, the default certificate on a newly created non-gallery or approxy-application will default to a public Azure Cert (Thumbprint 977B10FB9D1C087E3105564B1D31B09D247BEBCD, subject accounts.accesscontrol.windows.net).

            When you edit the configuration of SSO that certificate seems to be updated, but for some of my applications it seems not to have... So it was still signing with the default Azure AD certificate.

            Source https://stackoverflow.com/questions/69524518

            QUESTION

            How to recover individuals meeting certain conditions in at least one column?
            Asked 2021-Aug-26 at 21:40
            ID<-c(1:10)
            M1<-c("A","C","V","X","V","Z","K","SA","KS","B")
            M2<-c("A","H","D","K","DEL","QS","L","SA","OOB","NO")
            M3<-c("A","C","V","X","V","Z","K","SA","NC","RG")
            M4<-c("ABS","JC","VJ","TE","DEL","GJ","FH","QM","SF","X")
            M5<-c("ER","DU","OD","KZ","GZ","ZB","DEL","SA","DEL","WX")
            
            mydata<-data.frame(ID,M1,M2,M3,M4,M5)
            
            ...

            ANSWER

            Answered 2021-Aug-26 at 21:34

            If we want to get the ID alone

            Source https://stackoverflow.com/questions/68945498

            QUESTION

            XML annotations (JAXB) suggestions for unmarshalling and marshalling
            Asked 2021-Aug-19 at 14:49

            I have a sample XML as shown below:

            ...

            ANSWER

            Answered 2021-Aug-19 at 10:19

            First issue: I am no expert on JAXB so I do not have much idea on what could cause the warnings specified here but I tried following the code and it seems to work fine for me without any warnings. If you want to get more understanding then the best thing to do is search about it and read the doc to get more information. But my guess is that it's happening due to your second issue.

            Also, I am using Moxy which is an extension of JAXB developed by Eclipse-link. It has many additional benefits compared to simple JAXB

            Second issue: obvious error is in this line:

            Source https://stackoverflow.com/questions/68844663

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install vj

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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