oprah | Opinionated presenters for Rails 5 - without the cruft | Application Framework library
kandi X-RAY | oprah Summary
kandi X-RAY | oprah Summary
If you've ever worked on a sufficiently large Rails application you've probably experienced the Rails helper mess first hand. Helper methods are annoying to locate, hard to test and not terribly expressive.
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Top functions reviewed by kandi - BETA
- Allows you to set multiple views .
- Provides access to the view
- Returns true if the object does not exist
- Creates a new instance of the view .
- Returns true if the given object is true .
- Set the options for the Solr application
- This method should be used to be used to use this method .
oprah Key Features
oprah Examples and Code Snippets
Community Discussions
Trending Discussions on oprah
QUESTION
everyone! This is my first post here, so I will try to do my best to ask properly and exposed right my doubts and what I tried so far.
I've been trying to create one quotes generator, with a few features more.
I already put 7 quotes examples, as objects into the array and leaved 3 "spaces free", counting from ID 8 to 10 to the users can add more quotes examples through the "Add new quote button"
I tried to create the logic behind this (picking the HTML input field value typed by the user, add to new existing array through the Event Listener method, clicking on the button) as I commented in the last part of the JS file, but I don't know what I'm doing wrong.
So, if you guys please can give me a hand, I appreciate it!
PS. the ID key value of the object array it's a mandatory value.
Thanks in advance!
...ANSWER
Answered 2021-May-15 at 08:49QUESTION
I have a class script (secondary.py
), that when called in my main.py
file, works. My issue is that I want to call the second function below in another script, tertiary.py
, and that the output variable reg_name
be the same for both of the functions below -
ANSWER
Answered 2021-Mar-30 at 00:01So, you've got ran_line = handle_csv.sample(n = 1, replace = False)
meaning you'll get a random line every time you create a new instance of your class NameHandler
.
Every time you NameHandle()
you're creating a new instance, so, getting a new random line.
Just create the class instance once and use that instance to call the functions on.
QUESTION
Hi I have a sample query if you'd like to see an idea of the graph I'm going to be referring to:
CREATE (u:User {name: "Tim Cook"})-[:FOLLOWS]->(t:Thing {name: "Italy"}), (t)<-[:TAGGED]-(p:Post {name: "Post 1"})<-[:WROTE]-(u1:User {name: "Elon Musk"}), (u)-[:FOLLOWS]->(u2:User {name: "Oprah"})-[:WROTE]->(p1:Post {name: "Post 2"}), (u)-[:FOLLOWS]->(u3:User {name: "Joe Biden"})-[:WROTE]->(p2:Post {name: "Post 3"})
I am trying to get all posts where the user either follows the author directly (someone who "WROTE" a post) OR where the person follows a Thing that was "TAGGED" in a post.
So in the example query, if you are Tim Cook, you should receive Posts 2 and 3 because you follow the authors directly, and Post 1 because you follow Italy that was TAGGED in that post.
I've been searching everywhere, it's a hard thing to search for. Landed here. I'm using "OPTIONAL" so that if the user isn't following any people the first one doesn't crash the whole query, or if they aren't following any things, the second one doesn't crash. However, with how I did it below, it returns Null for either of the queries that are empty.
So if there are no matches for the first part and 6 for the second, I end up with an array of length 7. [null, post1, post2, ...post6].
How should I be doing this instead, please? Thank you in advance!
...ANSWER
Answered 2021-Jan-02 at 09:24You can consider the node in the middle of the path (user or tag) as a generic object, and thus from there use a multi-relationship type pattern matching :
QUESTION
customer date discount_code product_variant
0 KATIE 2019-05-15 no_discount X1.1
1 KATIE 2019-05-15 no_discount X1.2
15 KATIE 2019-06-24 no_discount X1.1
16 KATIE 2019-06-24 no_discount X2
141 MAX 2019-11-26 PR19 X1.1
263 OPRAH 2019-12-01 PR19 X1.2
264 OPRAH 2019-12-01 PR19 X2
334 PAUL 2020-01-14 no_discount X3
1247 PAUL 2019-10-30 CHRISTMAS19 X2
...ANSWER
Answered 2020-Nov-23 at 17:52IIUC you can groupby
and transform
for latest date of each customer, and then compare and get latest date for another groupby
:
QUESTION
I have created a random quote machine project in React with functional component. When I click on new quote it works only once. This is one of the freecodecamp challenge project. Here, I am trying to get new quote every time I click on the new quote button. I am unable to spot the issue. Please help.
...ANSWER
Answered 2020-Jul-15 at 05:41It would be much easier to simply make a list of quotes and when the button is pressed it will get a random value from the list. as for your code, it looks fine tbh.
QUESTION
I'm not really sure how to ask this and I've been search-engining for awhile and haven't come up with anything useful.
Say I have the following three tables People
, Cities
and States
:
ANSWER
Answered 2020-Jul-13 at 05:28I agree with Tim, this should be handled in your presentation layer.
But you can do it if you're using MySQL 8 by taking advantage of window functions. We can use row_number()
to determine the first row per state and per city, then use a case to only display the name for the first row.
QUESTION
I am using Python 3. I need to create a function: contacts()
that loops through a nested list and returns a dictionary of an item for each contact name and area-code. If the data does not include area code (empty element) then the value should be None
.
My starting list is:
...ANSWER
Answered 2020-Jun-28 at 15:12Assuming you'll never have repeated names in your contact_list
QUESTION
I am doing a online course where I got the following assignment:
...ANSWER
Answered 2020-May-28 at 10:47QUESTION
I'm making a lyrics command. Because of discord limit I have to split the message into parts. My current solution just splits the message at 2000 characters.
...ANSWER
Answered 2020-May-20 at 13:08I know this has already been answered but I'm going to put my solution in anyway in case you find it helpful:
QUESTION
considering a list of Pcollection:
[{'id':'1','name':'Tom','country':'USA'},{'id':'2','name':'Oprah','country':'USA'}....]
I want to count the occurrence of every country. The result should be something like this:
{'USA':2, 'Tunisia':3, 'France':1}
...ANSWER
Answered 2020-Mar-31 at 13:53This is similar to the word count example. You can find an implementation in python here - https://beam.apache.org/get-started/wordcount-example/
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Oprah expects a single presenter for each of your classes or modules. If your model is called User it will look for a class called UserPresenter:.
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